Questions Related to physics

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Choose the INCORRECT statement from the following.

  1. Volume is a chemical property of matter

  2. Volume is a physical property of matter

  3. Volume is needed to find density

  4. Volume is the amount of space something takes up

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Option D is the definition of Volume. It is only a physical property of any object and has nothing to do with the chemical properties. Since density is mass/ volume, it is necessary to find density.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Which of the following is used to measure the volume of a liquid or an irregular shaped object?

  1. A burette

  2. A measuring flask

  3. A measuring cylinder

  4. All of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Volume of a liquid or an irregular solid object is measured with the help of burettes, measuring flasks and measuring cylinders.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Which of the following is not used to measure the volume of a liquid or an irregular shaped object?

  1. A pipette

  2. A measuring flask

  3. A graduated cylinder

  4. A meter scale

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A liquid or an irregular shaped object does not have a geometric shape. So, by measuring its certain dimensions, volume may not be calculated. Hence a meter scale can not be used to measure the volume of a liquid or an irregular shaped object.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Find the volume of a ring immersed in water ,increasing the level from 55.2 ml to 75.3 ml.

  1. $20.1\ ml$
  2. $29\ ml$
  3. $10.1\ ml$
  4. $14.1\ ml$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Initial volume level   $V _i = 55.2 \ ml$
Final volume level   $V _f = 75.3 \ ml$
Thus, volume of ring    $V = V _f-V _i$
$\implies \ V = 75.3-55.2 = 20.1 \ ml$

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

The volume enclosed by the cylinder of diameter $1.06\ m$  and height 7.2 m to the correct no. of the significant figure is:

  1. $6.350\ m^3$
  2. $6.35\ m^3$
  3. $6.3\ m^3$
  4. $6\ m^3$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Diameter of cylindrical vessel  $d = 1.06 \ m$
Height of cylindrical vessel  $h = 7.2 \ m$
Volume   $V = \dfrac{\pi d^2 h}{4}$
$\implies \ V = \dfrac{\pi\times (1.06)^2\times 7.2}{4} = 6.354 \ m^3$
Since the number $7.2$ has two significant figures and $1.06$ has three significant figures.
So the final answer must have 2 significant figures.
Thus volume of cylinder   $V = 6.3 \ m^3$

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Volume enclosed by the sphere of diameter $1.06\ m$ to the correct no. of significant figure is:

  1. $0.62329 \ m^3$
  2. $0.623 \ m^3$
  3. $0.6232 \ m^3$
  4. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The significant figures are the number of digits in a value, that are significant. In $1.06m$, the number of significant figures is 3. In the answer also we must maintain 3 significant figures only. Hence option B is correct.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

The density of steel rod is $7850\ kg/m^3$, its mass is $5\ kg$.Find its volume?

  1. $7.36\times 10^{-4}\ m^3$
  2. $36\times 10^{-4}\ m^3$
  3. $6.36\times 10^{-4}\ m^3$
  4. $6\times 10^{-4}\ m^3$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Mass of steel rod $m = 5 \ kg$
Density of steel rod   $d = 7850 \ kg/m^3$
Volume of steel rod  $V = \dfrac{m}{d}$
$\implies \ V = \dfrac{5}{7850} = 6.36\times 10^{-4} \ m^3$

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Each side of a cube is measured to be $7.203\ m$.The volume of the cube to appropriate significant figure is:

  1. $31.3\ m^3$
  2. $313\ m^3$
  3. $373.7\ m^3$
  4. $37.3\ m^3$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Side of cube  $a = 7.203 \ m$
Volume of cube  $V = a^3$
$\implies \ V = (7.203)^3 = 373.714 \ m^3$
Since the value of side of cube has 4 significant figures, thus the value of volume of cube must also have 4 significant figure.
Thus volume of cube  $V = 373.7 \ m^3$

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Density and mass of the solid block is $5.2\  kg/m^3$ and $2\ kg$.Find its volume?

  1. $0.3846\ m^3$
  2. $7846\ cm^3$
  3. $68.46\ cm^3$
  4. $98.46\ cm^3$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Mass of solid block  $m = 2 \ kg$
Density of solid block   $d = 5.2 \ kg/m^3$
Volume of solid block  $V = \dfrac{m}{d}$
$\implies \ V = \dfrac{2}{5.2} = 0.3846 \ m^3$

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Which of the following instruments can be used to measure the volume of a liquid?

  1. Measuring cylinder

  2. Vernier callipers

  3. Pipette

  4. Measuring flask

Reveal answer Fill a bubble to check yourself
A,C,D Correct answer
Explanation

Measuring cylinder, pipette and measuring flask are used to measure the volume of the given liquid whereas vernier calliper is used measure the length of the object.