Tag: physics

Questions Related to physics

Choose the INCORRECT statement from the following.

physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

  1. Volume is a chemical property of matter

  2. Volume is a physical property of matter

  3. Volume is needed to find density

  4. Volume is the amount of space something takes up

Show answer
Correct Option: A
Explanation:

Option D is the definition of Volume. It is only a physical property of any object and has nothing to do with the chemical properties. Since density is mass/ volume, it is necessary to find density.

Which of the following is used to measure the volume of a liquid or an irregular shaped object?

physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

  1. A burette

  2. A measuring flask

  3. A measuring cylinder

  4. All of these

Show answer
Correct Option: D
Explanation:

Volume of a liquid or an irregular solid object is measured with the help of burettes, measuring flasks and measuring cylinders.

Which of the following is not used to measure the volume of a liquid or an irregular shaped object?

physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

  1. A pipette

  2. A measuring flask

  3. A graduated cylinder

  4. A meter scale

Show answer
Correct Option: D
Explanation:

A liquid or an irregular shaped object does not have a geometric shape. So, by measuring its certain dimensions, volume may not be calculated. Hence a meter scale can not be used to measure the volume of a liquid or an irregular shaped object.

Find the volume of a ring immersed in water ,increasing the level from 55.2 ml to 75.3 ml.

physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

  1. $20.1\ ml$

  2. $29\ ml$

  3. $10.1\ ml$

  4. $14.1\ ml$

Show answer
Correct Option: A
Explanation:

Initial volume level   $V _i = 55.2 \ ml$
Final volume level   $V _f = 75.3 \ ml$
Thus, volume of ring    $V = V _f-V _i$
$\implies \ V = 75.3-55.2 = 20.1 \ ml$

The volume enclosed by the cylinder of diameter $1.06\ m$  and height 7.2 m to the correct no. of the significant figure is:

physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

  1. $6.350\ m^3$

  2. $6.35\ m^3$

  3. $6.3\ m^3$

  4. $6\ m^3$

Show answer
Correct Option: C
Explanation:

Diameter of cylindrical vessel  $d = 1.06 \ m$
Height of cylindrical vessel  $h = 7.2 \ m$
Volume   $V = \dfrac{\pi d^2 h}{4}$
$\implies \ V = \dfrac{\pi\times (1.06)^2\times 7.2}{4} = 6.354 \ m^3$
Since the number $7.2$ has two significant figures and $1.06$ has three significant figures.
So the final answer must have 2 significant figures.
Thus volume of cylinder   $V = 6.3 \ m^3$

Volume enclosed by the sphere of diameter $1.06\ m$ to the correct no. of significant figure is:

physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

  1. $0.62329 \ m^3$

  2. $0.623 \ m^3$

  3. $0.6232 \ m^3$

  4. None of these

Show answer
Correct Option: B
Explanation:

The significant figures are the number of digits in a value, that are significant. In $1.06m$, the number of significant figures is 3. In the answer also we must maintain 3 significant figures only. Hence option B is correct.

The density of steel rod is $7850\ kg/m^3$, its mass is $5\ kg$.Find its volume?

physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

  1. $7.36\times 10^{-4}\ m^3$

  2. $36\times 10^{-4}\ m^3$

  3. $6.36\times 10^{-4}\ m^3$

  4. $6\times 10^{-4}\ m^3$

Show answer
Correct Option: C
Explanation:

Mass of steel rod $m = 5 \ kg$
Density of steel rod   $d = 7850 \ kg/m^3$
Volume of steel rod  $V = \dfrac{m}{d}$
$\implies \ V = \dfrac{5}{7850} = 6.36\times 10^{-4} \ m^3$

Each side of a cube is measured to be $7.203\ m$.The volume of the cube to appropriate significant figure is:

physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

  1. $31.3\ m^3$

  2. $313\ m^3$

  3. $373.7\ m^3$

  4. $37.3\ m^3$

Show answer
Correct Option: C
Explanation:

Side of cube  $a = 7.203 \ m$
Volume of cube  $V = a^3$
$\implies \ V = (7.203)^3 = 373.714 \ m^3$
Since the value of side of cube has 4 significant figures, thus the value of volume of cube must also have 4 significant figure.
Thus volume of cube  $V = 373.7 \ m^3$

Density and mass of the solid block is $5.2\  kg/m^3$ and $2\ kg$.Find its volume?

physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

  1. $0.3846\ m^3$

  2. $7846\ cm^3$

  3. $68.46\ cm^3$

  4. $98.46\ cm^3$

Show answer
Correct Option: A
Explanation:

Mass of solid block  $m = 2 \ kg$
Density of solid block   $d = 5.2 \ kg/m^3$
Volume of solid block  $V = \dfrac{m}{d}$
$\implies \ V = \dfrac{2}{5.2} = 0.3846 \ m^3$

Which of the following instruments can be used to measure the volume of a liquid?

physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

  1. Measuring cylinder

  2. Vernier callipers

  3. Pipette

  4. Measuring flask

Show answer
Correct Option: A,C,D
Explanation:

Measuring cylinder, pipette and measuring flask are used to measure the volume of the given liquid whereas vernier calliper is used measure the length of the object.