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Multiple choice dew point and humidity heat physics

We feel most comfortable at relative humidity at:

  1. < 50%

  2. 50%

  3. > 50%

  4. 100%
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Relative humidity is the ratio of the current absolute humidity to the highest possible absolute humidity which depends on the air temperature. A reading of 100 percent relative humidity means that the air is totally saturated with water vapour and cannot hold any more, creating the possibility of rain. We feel most comfortable at relative humidity 50%.

Multiple choice dew point and humidity heat physics

On a day during the Monsoon season, the relative humidity at a place is 90% and the temperature is $15^\circ$ (C) The saturation vapour pressure of water at this temperature is $0.0169\, \times\, 10^5$ Pa. The partial pressure of water vapour in the air on that day is

  1. $0.9\, \times\, 10^5$ Pa

  2. $0.0169\, \times\, 10^5$ Pa

  3. $0.0152\, \times\, 10^5$ Pa

  4. $1.0\, \times\, 10$^5$ Pa
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
Relative humidity=$\dfrac { \text{Partial pressure of }{ H } _{ 2 }0 }{ \text{Vapour pressure of } { H } _{ 2 }0 }\times100\%$
Let the partial pressure of $H _20$ be $x\rho a$
$90=\dfrac { x }{ 0.169\times { 10 }^{ 5 } } \times 100\\ $
$\dfrac { 90 }{ 100 } \times \dfrac { 169 }{ { 10 }^{ 4 } } \times { 10 }^{ 5 }=x$
$x=169\times9$
$x=1521\rho a$
$=0.0152\times10^5\rho a$

Multiple choice dew point and humidity heat physics

When air is saturated, it cannot hold ____________.

  1. more water vapour

  2. more air

  3. more carbon dioxide

  4. more oxygen
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

When a volume of air at a given temperature holds the maximum amount of water vapour, the air is said to be saturated.

Multiple choice dew point and humidity heat physics

At dew point. RH is _______.

  1. 10%

  2. 30%

  3. 50%

  4. 100%
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation
The dew point is the temperature at which air is saturated with water vapor, which is the gaseous state of water. The relative humidity is 100 percent when the dew point and the temperature are the same.
Multiple choice dew point and humidity heat physics

The relative humidity on a day when partial pressure of water vapour is $0.012 \times 10^5 Pa$ at $12^oC$ is (Take vapour pressure of water at this temperature as $0.016 \times 10^5$ Pa)

  1. 70%

  2. 40%

  3. 75%

  4. 25%
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Given,

Partial pressure of water vapour $={ 0.125\times 10 }^{ 5 }$ Pa
Vapour pressure of water$={ 0.016\times 10 }^{ 5 }$ Pa
Relative humidity at a given temperature (R) 
$=\dfrac { Partial\quad pressure\quad of\quad water\quad vapour }{ vapour\quad pressure\quad of\quad water } \ =\dfrac { { 0.125\times 10 }^{ 5 } }{ { 0.016\times 10 }^{ 5 } } \ =0.75\ =75%$

Multiple choice dew point and humidity heat physics

Formation of dew is an example for ......

  1. Boiling

  2. Melting

  3. Condensation

  4. Evaporation
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

It is a example of condensation.Condensation is the process in which gas changes into a liquid when it touches a cooler surface.


Dew drops are formed due to condensation of water vapors. Air around us contains water vapors which we call moisture or humidity. Hot air contains more moisture as compared to cold air. During the night when the hot air comes into contact with some cold surface, water vapor present in it condenses on the cold surface in the form of droplets. These tiny drops of water are called dew drops

Multiple choice dew point and humidity heat physics

When it is raining, the dew point is:

  1. 0$^o$C

  2. 60$^o$C

  3. 100$^o$C

  4. room temperature
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation
The dew point is the temperature at which the air can exactly hold the amount of moisture present. When raining, at any given temperature, the atmosphere can hold so much water vapour. So the dew point is equal to the room temperature.
Multiple choice physics universe and space science launching of an artificial satellites around the earth launching of satellite india’s space programmes

Communication satellites move in orbits of radius 44,400 km around the earth find the acceleration of such a satelite, assuming that the only force acting on, it is that  due to the earth.Mass of the earth $ = 6 \times {10^{24}}Kg.$

  1. $0.2\;m{s^{ - 2}}$

  2. $2.1\;m{s^{ - 2}}$

  3. $4.2\;m{s^{ - 2}}$

  4. $0.3\;m{s^{ - 2}}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The acceleration (a) of a satellite in orbit is given by the gravitational field strength: a = GM / r^2. Using G = 6.67e-11, M = 6e24, and r = 4.44e7 meters, a = (6.67e-11 * 6e24) / (4.44e7)^2 = 4e14 / 1.97e15 = 0.203 m/s^2.

Multiple choice physics universe and space science launching of an artificial satellites around the earth launching of satellite india’s space programmes

A particle is projected vertically upward and is at a height h after $\displaystyle { t } _{ 1 }$ seconds and again after $\displaystyle { t } _{ 2 }$ seconds, then:

  1. $\displaystyle h={ gt } _{ 1 }{ t } _{ 2 }$

  2. $\displaystyle h=\frac { 1 }{ 2 } { gt } _{ 1 }{ t } _{ 2 }$

  3. $\displaystyle h=\frac { 2 }{ g } { t } _{ 1 }{ t } _{ 2 }$

  4. $\displaystyle h=\sqrt { { gt } _{ 1 }{ t } _{ 2 } } $
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let u be the velocity of the projection and O be the point of projection. Let P be the point in the path of the particle such that OP=h. Then,
$\displaystyle h=ut-\frac { 1 }{ 2 } { gt }^{ 2 }\Rightarrow { gt }^{ 2 }-2ut+2h=0$...(i)
Clearly, $\displaystyle { t } _{ 1 }{ t } _{ 2 }$, are two roots of this equation.
$\displaystyle \therefore \quad { t } _{ 1 }{ t } _{ 2 }=\frac { 2h }{ g } $
$\displaystyle \Rightarrow \quad h=\frac { 1 }{ 2 } g{ t } _{ 1 }{ t } _{ 2 }$

Multiple choice physics universe and space science launching of an artificial satellites around the earth launching of satellite india’s space programmes

In case of an orbiting satellite, if the radius of orbit is decreased.

  1. Its KE decreases

  2. Its PE decreases

  3. Its ME decreases

  4. Its speed decreases
Reveal answer Fill a bubble to check yourself
B,C Correct answer
Explanation

P.E of orbiting satellite at distance $r$ from centre of earth

$=\cfrac{-GMm}{r}\\K.E=\cfrac{GMm}{2R}$ and $M.E=\cfrac{-GMm}{2R}$

If $R$ decreased K.E increases.

P.E and M.E become more negative, thus decrease.