Questions Related to physics

Multiple choice physics constellations and galaxies light year evolution and end stages of stars in the world of stars

All the stars are at the same distance from us. This statement is

  1. True

  2. False

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Our Sun is the nearest star to the Earth. After the Sun, the next nearest star is 4.3 light years away. A light year is the distance light travels in one year. One light year is 10 trillion kilometers. Hence, all the stars are not the same distance from our Earth. They are at different distances. Hence, given statement is false.

Multiple choice physics constellations and galaxies light year evolution and end stages of stars in the world of stars

The $6563 \mathring {A}$ line emitted by hydrogen atom in a star is found to be red shifted by $5\mathring{A}$. the speed with which the star is receding from the earth is:

  1. $17.3\times 10^3 $ m/s

  2. $4.29 \times 10^7 $m/s

  3. $3.39 \times 10^5 $m/s

  4. $ 2.29 \times 10^5$ m/s

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

$\dfrac{\triangle v}{v}=\dfrac{V _{radiant}}{C}$
$v=\dfrac{C}{\lambda}$
$d.v=\dfrac{C}{\lambda^2}.dv=\dfrac{\dfrac{x}{\lambda^2}}{\dfrac{C}{\lambda}}=\dfrac{d\lambda}{\lambda}$
$\dfrac{d\lambda}{\lambda }=\dfrac{V _{radial }}{C}$
$\dfrac{5 \times 10^{-10}}{6563 \times 10^{-10}}=\dfrac{C _{radial}}{3\times 10^8}$
Calculate $V _radial=\dfrac{5}{6563}\times 3\times 10^8$
$=\dfrac{15}{6563}\times 10^8$
$\dfrac{15}{6.56}\times 10^5$
$2.29\times 10^5m/s$

Multiple choice physics constellations and galaxies light year evolution and end stages of stars in the world of stars

A star is seen to be rising on the eastern horizon at $23:00$ hrs. At what time the star will rise 2 days later

  1. $00:00$ hrs

  2. $21:40$ hrs

  3. $23:20$ hrs

  4. $23:00$ hrs

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation
The stores appear to be static when seen from earth thus they only appear to be moving due to earth's rotation about its axis. It takes exactly $24$ hors to complete one rotation. So after days $(2\times 24\ hrs)$, the far will be seen rising at the same time
$(i.e., 23:00\ hrs)$

Multiple choice physics constellations and galaxies light year evolution and end stages of stars in the world of stars

One light year is equal to

  1. 3.26 parsec

  2. 3.26km

  3. 3.26 A.U.

  4. $\displaystyle \frac{1}{3.26}$ parsec

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

One light year is the distance travelled by the light in one year. So,

$1$Parse $=3.08\times { 10 }^{ 16 }$m
$1$ light year$9.46\times { 10 }^{ 15 }$m
So
$1$ light year $=9.46\times { 10 }^{ 15 }$ parsec
                       $=3.08\times { 10 }^{ 16 }$
$1$ light year $=0.306$ parsec
                     $=\cfrac { 1 }{ 3.26 } $ parsec