Questions Related to physics

Multiple choice physics light, shadows and images introduction to reflection of light light and sight images in plane mirror

While is not basic transformation function 

  1. Translation

  2. Rotating

  3. Scaling

  4. Reflection

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A transformation is when you take a shape and you move it in some way. A basic rigid transformation is a movement of the shape that does not affect the size of the shape. The shape doesn't shrink or get larger. There are three basic rigid transformations: reflections, rotations, and translations. So, scaing is not a basic transformation function.

Multiple choice physics light, shadows and images introduction to reflection of light light and sight images in plane mirror

A ray of light is incident on a plane mirror along a vector $\hat i+\hat j-\hat k$. The noemal on incident point is along $\hat i+\hat j$. Then unit vector along the reflected ray is:

  1. $ \dfrac { 1 }{ \sqrt { 3 } } \left( \hat { i } +\hat { j } +\hat { k } \right)$
  2. $-\dfrac { 1 }{ \sqrt { 3 } } \left( \hat { i } +\hat { j } +\hat { k } \right)$
  3. $ \dfrac { 1 }{ \sqrt { 3 } } \left( -\hat { i } -\hat { j } +\hat { k } \right)$
  4. $ \dfrac { 1 }{ \sqrt { 3 } } \left( -\hat { i } +\hat { j } +\hat { k }\right)$
Reveal answer Fill a bubble to check yourself
B Correct answer
Multiple choice motional emf physics

A circular coil of radius 6 cm and 20 turns rotates about its vertical diameter with an angular speed of 40 rad $s^{-1}$ in a uniform horizontal magnetic field of magnitude $2 \times 10^{-2}$ T. If the coil form a closed loop of resistance 8 $\Omega$, then the average power loss

  1. $2.07\times 10^{-3}$W
  2. $1.23\times 10^{-3}$W
  3. $3.14\times 10^{-3}$W
  4. $1.80\times 10^{-3}$W
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
Here, $r = 6 cm = 6 \times 10^{-2}m,$ 
$N = 20, \omega = 40 \, rad \, s^{-1}$
$B = 2 \times 10^{-2} T, R = 8 \Omega$
Maximum emf induced, $\epsilon \, = \, NAB \omega$
$ = \, N(\pi r^2)B \omega$
$ = 20 \times \pi \times (6 \times 10^{-2})^2 \times 2 \times 10^{-2} \times 40 \, = \, 0.18 V$

Average value of emf induced over a full cycle $\epsilon _{av}\, = \, 0$ 

Maximum value of current in the coil, $ I \, = \, \dfrac{\varepsilon }{R} = \dfrac{0.18}{8} = 0.023 \,A$

Average power dissipated, $ P \, = \, \dfrac{\varepsilon I}{2} \, = \, \dfrac{0.18 \times 0.023}{2} \, = \, 2.07 \times 10^{-3} W$
Multiple choice motional emf physics

The axle of a circular wheel of radius R is held horizontally by two identical strings of equal lengths separated by a distance D. The tension in each string is $T _0$. The rim of the wheel carries a total charge $+$Q distributed uniformly on it. The wheel is vertical and is kept in a uniform vertical magnetic field $\vec{B}$. It is now rotated at an angular speed $\omega$. If the string break at a tension of $3T _0/2$, than the maximum possible value of $\omega$ at which the wheel can be rotated without breaking a string is $\dfrac{DT _0}{QBR^2}$.

  1. True

  2. False

Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice motional emf physics

A conductor of $3\ m$ length is moving perpendicular to its length as well as a magnetic field of ${10}^{-3}\ T$ with a speed of ${10}\ m/s$, then the force required to move it with this constant speed is

  1. $0.3\ N$
  2. $0.9\ N$
  3. Zero

  4. $3 \times {10}^{-3}\ N$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Force on rod moving in a magnetic fileld is given by:

$F=BIL$
Where $I$ is the current in the rod.

According to the question;
$I=0$
Therefore,
$F=0$

Thus,
No force is exerted on the conductor in the magnetic field.
Thus, no external field is required to move the conductor at constant speed.

Multiple choice motional emf physics

A horizontal straight conductor (otherwise placed in a closed circuit) along east-west direction falls under gravity. There is:-

  1. No induced electromotive force along the length

  2. No induced current along the length

  3. An induced current from west to east

  4. None of the above.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

As the conductor falls, it cuts the horizontal component of the Earth's magnetic field. According to Fleming's Right Hand Rule, an induced EMF is generated. For a conductor falling and moving through the horizontal magnetic field, the current flows from West to East.

Multiple choice motional emf physics

In a uniform magnetic field of induction $B$ a wire in the form of semicircle of radius $r$ rotated about the diameter of the circle with angular frequency $\omega$. The axis of rotation is perpendicular to the field. If the total resistance of the circuit is $R$ the mean power generated per period of rotation is:

  1. $\dfrac { B\pi { r }^{ 2 }\omega }{ 2R }$
  2. $\dfrac { { \left( B\pi { r }^{ 2 }\omega \right) }^{ 2 } }{ 2R }$
  3. $\dfrac { { \left( B\pi r\omega \right) }^{ 2 } }{ 2R }$
  4. $\dfrac { { \left( B\pi r{ \omega }^{ 2 } \right) }^{ 2 } }{ 8R }$
Reveal answer Fill a bubble to check yourself
D Correct answer
Multiple choice motional emf physics

To produce a field of magnetic $\pi$ tesla at the center of circular loop of diameter 1 m, the current flowing through loop is :

  1. $5\times 10^6\;A$
  2. $10^7\;A$
  3. $2.5\times 10^6\;A$
  4. $2\times 10^6\;A$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Magnetic field due to circular loop at center O due to current $i$ is given as,

$B=\dfrac{\mu _0 I}{2r}=\dfrac{4\pi\times 10^{-7} \times I}{2\times 0.5}$
$\pi \times 1=4\pi \times 10^{-7} I$
$I=2.5\times 10^{6} A$

Multiple choice motional emf physics

A metal ring of radius $r = 0.5\ m$ with its plane normal to a uniform magnetic field $B$ of induction $0.2\ T$ carries a current $I = 100\ A$. The tension in newtons developed in the ring is

  1. $100$
  2. $50$
  3. $25$
  4. $10$
Reveal answer Fill a bubble to check yourself
D Correct answer
Multiple choice motional emf physics

A magnet is brought towards a coil (i) speedly (ii) slowly, then the induced electromotive force charge will be respectively

  1. More in first case / More in first case

  2. More in first case / Equal in both case

  3. Less in first case / More in second case

  4. Less in first case / Equal in both case

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Induced EMF is proportional to the rate of change of magnetic flux (dPhi/dt). Moving the magnet speedily increases the rate of change, resulting in a higher induced EMF. However, the total charge induced (q = delta Phi / R) depends only on the total change in flux, which is the same regardless of speed.