Tag: physics

Questions Related to physics

The maximum wavelength of radiations emitted at 900 K is $4 \mu m$. What will be the maximum wavelength of radiation emitted at 1200 K?

kirchoff's laws black body radiation heat transfer thermal properties physics

  1. 3 $\mu m$

  2. 0.3 $\mu m$

  3. 1 $\mu m$

  4. None of these

Show answer
Correct Option: C

Certain substance emit only the wavelength $\lambda  _{1},\lambda  _{2},\lambda  _{3}  \ and  \ \lambda  _{4}$ when it is at a high temperature. When this substance is at a colder temperature, it will absorb only the following wavelength :

kirchoff's laws black body radiation heat transfer thermal properties physics

  1. $\lambda _{1}$

  2. $\lambda _{2}$

  3. $\lambda _{1}$ and $\lambda _{2} $

  4. $\lambda _{1},\lambda _{2},\lambda _{3}$ and $\lambda _{4} $

Show answer
Correct Option: D
Explanation:

With the help of kirchhoff's law  we can say that $\varepsilon =\alpha $
${\varepsilon}= emissivity $
$\alpha=absorptivity $
so kirchhoff's law state that total emissivity of body is equal to total absorptivity.
so ${\lambda} _{1},{\lambda} _{2}, {\lambda} _{3}, {\lambda} _{4}$ will be absorbed.  

In steady state

kirchoff's laws black body radiation heat transfer thermal properties physics

  1. Heat received is partly conducted and partly radiated

  2. Heat is not absorbed

  3. both A and B

  4. All the heat is conducted

Show answer
Correct Option: C
Explanation:

In steady state, heat received by any small element = heat given by it
So, heat is partially radiated and no net heat is absorbed.
We give an argument for this.
suppose that the heat is being given out by the element.
In this case, the element's temperature will decrease.
But, by definition , at steady state, all the temperatures remain constant.
So, this will violate the steady state condition.

A polished metal plate with a rough black spot on it is heated to about $1400 K$ and quickly taken into a dark room. Which one of the following statements will be true?

kirchoff's laws black body radiation heat transfer thermal properties physics

  1. The spot will appear brighter than the plate

  2. The spot will appear darker than the plate

  3. The spot and the plate will appear equally bright

  4. The spot and the plate will not be visible in the dark room

Show answer
Correct Option: A
Explanation:

According to Kirchhoff law, good absorbers are good emitters. Since black spot is good absorbers so it is also a good emitter & will brighter than plate.

An ideal black body at room temperature is thrown into a furnace.It is observed that

kirchoff's laws black body radiation heat transfer thermal properties physics

  1. initially it is the darkest body and at later times the brightest.

  2. it is darkest body at all times.

  3. it cannot be distinguished at all times.

  4. initially it is darkest and at later times it cannot be distinguished.

Show answer
Correct Option: A
Explanation:

An ideal black body is a good emitter and good absorber. Initially it will absorb all the energy and will appear dark. As soon as it attains the temperature equal to that of the furnace, it will start emitting better than the rest of furnace and hence appears the brightest.

A spherical body of area $A$ and emissivity $e = 0.6$ is kept inside a perfectly black body. Total heat radiated by the body at temperature T is :

kirchoff's laws black body radiation heat transfer thermal properties physics

  1. $0.4eAT^{4}$

  2. $0.8eAT^{4}$

  3. $0.6eAT^{4}$

  4. $1.0eAT^{4}$

Show answer
Correct Option: D
Explanation:

When a non black body is placed inside a hollow enclosure, the total radiation from the body is the sum of what it would emit in the open ( with $\epsilon<1$ ) and the part of the incident radiation from the walls reflected by it. The two add up to a black body radiation.

Hence the total radiation emitted by the body is $1.0\epsilon AT^4$.

The rates of heat radiation from two patches of skin each of area $S$, on a patient's chest differ by $2$%. If the patch of the lower temperature is at $300K$ and the emissivity of both the patches is assumed to be unity, the temperature of the other patch is closest to:

kirchoff's laws black body radiation heat transfer thermal properties physics

  1. $301.5K$

  2. $306K$

  3. $308.5K$

  4. $312K$

Show answer
Correct Option: A
Explanation:

$P=\sigma e AT^4$

$\cfrac{P _1}{P _2}=(\cfrac{T _1}{T _2})^4\ \cfrac{P+P\times\cfrac{2}{100}}{P}=(\cfrac{T _1}{300})^4\1+\cfrac{2}{100}=(\cfrac{T _1}{300})^4\ \Rightarrow \cfrac{102}{100}=(\cfrac{T}{300})^4\ \Rightarrow T=301.488K\ \quad\simeq 301.5K$

Choose the correct statements from the following

kirchoff's laws black body radiation heat transfer thermal properties physics

  1. Good reflectors are good emitters of thermal radiation.

  2. Burns caused by water at 100$^{o}$C are more severe than those caused by steam at 100$^{o}$C

  3. If the earth did not have atmosphere, it would become intolerably cold.

  4. It is impossible to construct a heat engine of a 100% efficiency.

Show answer
Correct Option: C,D
Explanation:
Statement (1) is incorrect. According to Kirchhoff's law, a good emitter is good absorber.
Statement (2) is incorrect because 100°C steam has more energy compared to 100°C water. 
Statement (3) is correct. The thermal radiation from the sun warms the earth during the day since air is poor conductor of heat, the atmosphere acts as a blanket for the earth and keeps the earth warm during the night. Moon is very cold because it has no atmosphere. 
Statement (4) is also correct , $\eta=1-T _2/T _1$ where $T _2$ is the temperature of the sink. To have 
an efficiency, $\eta = 1 (or\ 100\%)$, $T _2=0K$. Since absolute zero cannot be achieved, even an ideal heat engine cannot have a $100\%$ efficiency.

Statement-1:Good reflectors are poor emitters of thermal radiation.
Statement-2:The ratio of the emissive power (e) and absorptive power(a) is constant for all substances at any given temperture and for radiation of the same wavelength

kirchoff's laws black body radiation heat transfer thermal properties physics

  1. Statement-1 is true, Statement-2 is true and Statement-2 is the correct explanation for Statement- 1

  2. Statement-1 is true, Statement-2 is true but Statement-2 is not the correct explanation for Staement-1

  3. Statement-1 is true, Statement-2 is false.

  4. Statement-1 is false, Statement-2 is true.

Show answer
Correct Option: A
Explanation:

From the krichoff's law we know that absorptivity is equal to emissivity,so the body which emitt more wil absorbe more nor reflect more. So good reflector are poor emittor.
Now, by taking there ratio it validate krichoff's law because at any fixed or constant temperature both are equal.

In a dark room with ambient temperature $T _o$, a black body is kept at a temperature $T$. Keeping the temperature of the black body constant (at $T$), sunrays are allowed to fall on the black body through a hole in the roof of the dark room. Assuming that there is no change in the ambient temperature of the room, which of the following statement(s) is/are correct?

kirchoff's laws black body radiation heat transfer thermal properties physics

  1. The quantity of radiation absorbed by the black body in unit time will increase

  2. Since emissivity = absorptivity, hence the quantity of radiation emitted by black body in unit time will

    increase

  3. Black body radiates more energy in unit time in the visible spectrum.

  4. The reflected energy in unit time by the black body remains same.

Show answer
Correct Option: A,B,C,D
Explanation:

Since the radiation is continuously falling on the black body, the quantity radiation absorbed per second will increase.

The reason given in question is self explanatory.
With an increase in temperature, the entire Plank's curve shifts upwards and hence radiation in any spectrum will increase.
Reflected energy per unit time will be zero since black body has 0 reflectivity and hence it will remain constant.