Questions Related to physics

Multiple choice physics kinetic theory maxwell-boltzmann speed distribution function behavior of perfect gas and kinetic theory kinetic theory of matter

A vessel contains a mixture consisting of m$ _{1}$ - 7 g of nitrogen (M$ _{1}$ = 28) and m$ _{2}$ = 11 g of carbon dioxide (M$ _{2}$ = 44) at temperature T - 300 K and pressure P$ _{0}$ = 1 atm. The density of the mixture is

  1. $1.46g\ per\ litre$

  2. $2.567 g \ per \ litre$

  3. $3.752 g \ per \ litre$

  4. $4.572 g \ per \ litre$

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the volume occupied $=V$

By Dalton's law of partial pressure
$\cfrac{P _{nit}}{P _0}=\cfrac{n _{nit}}{n _{nit}+n _{carb}}$
No. of moles of Nitrogen $\eta _{nit}=\cfrac{M _1}{M _{nit}}=\cfrac{7}{28}=0.25 mol$
No. of moles of carbon $\eta _{carb}=\cfrac{M _2}{M _{carb}}=\cfrac{11}{4}=0.25 mol$
Thus,
$P _{nit}=P _0\times\cfrac{0.25}{0.25\times0.25}=P _0/2=0.5atm$
From ideal gas equation
$V=\cfrac{nRT}{P}=\cfrac{0.25\times8.314\times290}{0.5\times101325}=0.0119mole$
Total mixture $m=(7+11)\times 10^{-11}kg$
Thus density s $P=\cfrac{m}{V}=\cfrac{(7+11)\times 10^{-3}}{0.0119}\approx1.46kg/m^3$
Option A is correct.

Multiple choice physics kinetic theory maxwell-boltzmann speed distribution function behavior of perfect gas and kinetic theory kinetic theory of matter

A vessel of volume V contains a mixture of $1$mole of hydrogen and $1$ mole of oxygen(both considered as ideal). Let $f _1(v)dv$ denote the fraction of molecules with speed between v and $(v+dv)$ with $f _2(v)dv$, similarly for oxygen. then

  1. $f _1(v)+f _2(v)=f(v)$ obeys the Maxwell's distribution law

  2. $f _1(v), f _2(v)$ will obey the Maxwell's distribution law separately

  3. Neither $f _1(v)$ nor $f _2(v)$ will obey the Maxwell's distribution law

  4. $f _2(v)$ and $f _1(v)$ will be the same

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The Maxwell-Boltzmann speed distribution function $\left(N _v=\dfrac{dN}{dv}\right)$ depends on the mass of the gas molecule. [Here, dN is the number of molecules with speeds between v and $(v+dv)$]. The masses of hydrogen and oxygen molecules are different.

Multiple choice physics artificial satellite communication and mass media understanding communication and impact of mass media satellites in communication

For satellite communication which wave is used?

  1. Space wave

  2. Sky wave

  3. Ground wave

  4. Microwave

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

A space wave travels in a straight line from transmitting antenna to the receiving antenna. Space waves are used for line of sight communication as well as satellite communication.

Multiple choice physics artificial satellite communication and mass media understanding communication and impact of mass media satellites in communication

State whether the given statement is True or False :

Remote sensing is a technique of collection of information about an object, without a physical contact.

  1. True

  2. False

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Remote sensing is the acquisition of information about an object or phenomenon without making physical contact with the object and thus it is in contrast to on site observation. In modern usage, the term generally refers to the use of aerial sensor technologies to detect and classify objects on Earth.
Hence, the statement is true.

Multiple choice physics artificial satellite communication and mass media understanding communication and impact of mass media satellites in communication

As the height of a satellite orbit gets lower, the speed of the satellite _________.

  1. decreases

  2. increases

  3. remains the same

  4. none of the above

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$V=\sqrt { \cfrac { GMe }{ r }  } \ \therefore V\propto \cfrac { 1 }{ \sqrt { r }  } $

With decrease in $'r'$, velocity of satellite $increases$.

Multiple choice physics artificial satellite communication and mass media understanding communication and impact of mass media satellites in communication

Let $R _s$ and $R _m$ be the distance of the geostationary satellite and moon from the center of earth. Then $\dfrac{R _m}{R _s}$ is

  1. $(29)^{1/2}$

  2. $(29)^{2/3}$

  3. $29$

  4. $(29)^{3/2}$

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Using Kepler's Third Law, T^2 is proportional to R^3. For a geostationary satellite, T is 1 day. For the moon, T is approximately 29 days. Thus, (Rm/Rs)^3 = (Tm/Ts)^2 = (29/1)^2, which means Rm/Rs = (29^2)^(1/3) = 29^(2/3).

Multiple choice physics artificial satellite communication and mass media understanding communication and impact of mass media satellites in communication

If the satellite is stopped sudden;y in its orbit which is at a distance radius of earth from earth's surface and allowed to fall freely into the earth. the speed with which it hits the surface of earth will be:

  1. <span>$38,525 km/s$</span>

  2. <span>$1,525 km/s$</span>

  3. <span>$18,525 km/s$</span>

  4. $28,525 km/s$

Reveal answer Fill a bubble to check yourself
D Correct answer
Multiple choice physics artificial satellite communication and mass media understanding communication and impact of mass media satellites in communication

A remote -sensing satellite of earth revolves in a circular orbit at a height of $ 0.25 \times 10^6 $ m above the surface of earth. if earth's radius is $ 0.25 \times 10^6 $ m above the surface of earth. if earth's radius is $ 6.38 \times 10^6 m $ and $ g= 9.8 m/s^2 $, then the orbital speed of the satellite is :

  1. $6.67 km/s$

  2. $7.76 km/s$

  3. $8.56 km/s$

  4. $9.13 km/s$

Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice physics artificial satellite communication and mass media understanding communication and impact of mass media satellites in communication

State the chronological order in which the following events took place.
$1$. Launching of APPLE
$2$. Launching of Rohini
$3$. Antarctica expectation
$4$. Indian cosmonaut

  1. $2 - 1 - 3 - 4$

  2. $2 - 3 - 1 - 4$

  3. $3 - 1 - 2 - 4$

  4. $4 - 1 - 2 - 3$

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

a) Lunching of Apple - $1$ April, $1976$

b) Lunching of Rohini - $10$ Aug, $1979$
c) Indian cosmonaut - $1982$
(i.e. Rakesh Sharma, Indian air force pilot)
d) Antarctica expectation - $1965$
So, order is $d-a-b-c$.