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Multiple choice physics measurements and experimentation measuring distance of celestial bodies unconventional units of measurements units of mass

1 light year is equal to 

  1. $\displaystyle 6.3\times { 10 }^{ 5 }\overset { o }{ A } $

  2. $\displaystyle 6.3\times { 10 }^{ 4 }$$AU$

  3. $\displaystyle 3.0\times { 10 }^{ 16 }{ ms }^{ -1 }$

  4. $\displaystyle 6.3\times { 10 }^{ 4 }\overset { o }{ A } $
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
We know that   $1 \ light year  = 9.46\times 10^{15} \ m$
Also,   $1 \ AU = 1.5\times 10^{11} \ m$
Thus   $1 \ light year  = \dfrac{9.46\times 10^{15}}{1.5\times 10^{11}}  \ AU= 6.3\times 10^4 \ AU$
Multiple choice physics measurements and experimentation measuring distance of celestial bodies unconventional units of measurements units of mass

1 light year is equal to

  1. $\displaystyle 9.46\times { 10 }^{ -15 }m$

  2. $\displaystyle 9.46\times { 10 }^{ 15 }m$

  3. $\displaystyle 9.46\times { 10 }^{ -13 }m$

  4. $\displaystyle 9.46\times { 10 }^{ 13 }m$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
One light-year is defined as the distance traveled by light in a vacuum in one year.

Number of seconds in 1 year is:
$1 year=365\times24\times\times60\times60\\=3.15\times10^7\ sec$

So,
$1 \ light \ year =3\times10^8\times3.15\times10^7\\= 9.46\times 10^{15} \ m$
Multiple choice physics measurements and experimentation measuring distance of celestial bodies unconventional units of measurements units of mass

1 AU is equal to

  1. $\displaystyle 1.5\times { 10 }^{ 11 }m$

  2. $\displaystyle 1.5\times { 10 }^{ 10 }m$

  3. $\displaystyle 1.5\times { 10 }^{ 9 }m$

  4. $\displaystyle 1.5\times { 10 }^{ -11 }m$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
One astronomical unit is defined as the distance between the sun and the earth.
$ 1 \ AU = 1.5\times 10^{11} \ m$