Questions Related to physics

Multiple choice physics force and newton's laws of motion momentum (p) introduction to momentum linear momentum

A hockey ball of mass 200 g travelling at $10\ ms^{-1}$ is struck by a hockey stick so as to return it along its original path with a velocity of $5\ ms^{-1}$. Calculate the change of momentum which occurred in the motion of the hockey ball by the force applied by the hockey stick:

  1. $-3\ Ns$

  2. $3\ Ns$

  3. $6\ Ns$

  4. $-6\ Ns$

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Mass of ball(m)$=$200g$=$0.2kg
Initial velocity of ball(u)$=$10m${s}^{-1}$
Final velocity of ball(v)$=$5m${s}^{-1}$
Therefore, change in momentum ($\triangle$p) $=$ Final momentum - initial momentum $=m(v-u)=0.2\times(-5-10)=-3\ kgm{s}^{-1}=-3\ Ns$

Multiple choice physics force and newton's laws of motion momentum (p) introduction to momentum linear momentum

The change in momentum of a vehicle weighing 2000 kg when its speed increases from 36 km/h to 72 km/h uniformly is :

  1. 15000 kg.m/s

  2. 4000 kg.m/s

  3. 20000 kg.m/s

  4. 7200 kg.m/s

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Given :   $m = 2000$ kg            $u = 36$ km/h $ = 36 \times \dfrac{5}{18}  = 10$ m/s                $v= 72$ km/h $ = 72 \times \dfrac{5}{18}  = 20$ m/s             

Change in momentum       $\Delta P = m(v-u) = 2000\times (20-10)  =20000$  kg.m/s

Multiple choice physics force and newton's laws of motion momentum (p) introduction to momentum linear momentum

A 4-kilograms ball slides over horizontal friction less surface with velocity of 1 meter per second ball strike the post and rebounds upward perpendicular to the initial direction with same speed.
Calculate the change of momentum of the ball in initial direction.

  1. -4 kg.m/s

  2. -1 kg.m/s

  3. 0 kg.m/s

  4. 1 kg.m/s

  5. 4 kg.m/s

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Initially the velocity of the ball in horizontal direction is $1m/s$.

Finally the velocity of ball remains in vertical direction. Thus velocity in initial direction(horizontal)=$0m/s$
Thus the change in momentum=$\vec{p _2}-\vec{p _1}=m(\vec{v _2}-\vec{v _1})=4\times (0-1)kgm/s=-4kgm/s$

Multiple choice physics force and newton's laws of motion momentum (p) introduction to momentum linear momentum

A cricket ball of mass 500 g is moving with speed of $36 \,km\,h^{-1}$. It is reflected back with the same speed. What is the impulse applied on it?

  1. 20 Kg m/s

  2. 10 Kg m/s

  3. 5 Kg m/s

  4. none of the above

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Impulse $I=$ change in momentum $=mv _2-mv _1$

Here, $v _1=-v _2=36 km/h$
So, $I=(500/1000)[-36-36]=-36 kg.m/s$
The magnitude of impulse $=36 kg.m/s$

Multiple choice physics force and newton's laws of motion momentum (p) introduction to momentum linear momentum

A force acts on a body of mass 3 kg such that its velocity changes from $4 \,m\, s^{-1}$ to $10 \,m\, s^{-1}$. The change in momentum of the body is:

  1. $42 \,kg\, m\, s^{-1}$

  2. $2 \,kg\, m\, s^{-1}$

  3. $18 \,kg\, m\, s^{-1}$

  4. $14 \,kg\, m\, s^{-1}$

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Given, $m=3 kg$, $v _1=4 m/s$ and $v _2=10 m/s$

Change in momentum $=p _2-p _1=mv _2-mv _2=m(v _2-v _1)=3(10-4)=18 $ $kg $ $ms^{-1}$

Multiple choice physics force and newton's laws of motion momentum (p) introduction to momentum linear momentum

State whether true or false.
If two bodies of different masses move with the same momentum, then the heavier body will have the greater velocity.

  1. True

  2. False

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

If two bodies of different masses move with the same momentum, then the heavier body will not have the greater velocity.

Hence,
option $B$ is correct answer.