Questions Related to physics

Multiple choice physics fluid pressure pressure in air introduction to atmospheric pressure pressure exerted by air devices to measure pressure

The temperature of an air bubble while rising from bottom to surface of a lake remains constant but its diameter is doubled if the pressure on the surface is equal to h meter of mercury column and relative density of mercury is p then the depth of lake in metre is

  1. $2\rho h$

  2. $4\rho h$

  3. $8\rho h$

  4. $7\rho h$

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Using Boyle's Law: P1V1 = P2V2. P1 = P_atm + rho_w*g*h. P2 = P_atm. Since diameter doubles, volume increases 8 times. P_atm + rho_w*g*h = 8 * P_atm. h = 7 * P_atm / (rho_w*g). Given P_atm = rho_m*g*h_m, we get h = 7 * (rho_m/rho_w) * h_m = 7 * rho * h.

Multiple choice physics fluid pressure pressure in air introduction to atmospheric pressure pressure exerted by air devices to measure pressure

The pressure of water at bottom in a lake is 3/2 times that at half depth where the water barometer reads $10$ m. The depth of the lake is:

  1. $15$ m

  2. infinite

  3. $20$ m

  4. $10$ m

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the point at half depth be $x,$

$P _1=P+dgx$

Let the depth of lake be $2x$,

$P _2=P+dg2x$

$P _2=3/2×P1$

$2P _2=3P1$

$2 (P+dg2x)=3 (P+dgx)$

$2P+4dgx=3P + 3dgx$

$P=dgx$

$x=P/dg$

$x=10^5/10000 (d=10^3kg/m^3) (P=10^5pa)$

But depth of lake is $2x$

$2x=2×10=20m$

Multiple choice physics fluid pressure pressure in air introduction to atmospheric pressure pressure exerted by air devices to measure pressure

Two communicating vessels contain mercury. The diameter of one vessel is four times larger than the diameter of the other. A column of water of height $h _0=70$ cm is poured into the left hand vessel (the narrower one). How much will be mercury level rise in the right hand vessel? ( Specific density of mercury= $13.6$)

  1. $0.3$ cm

  2. $0.7$ cm

  3. $0.1$ cm

  4. $1.0$ cm

Reveal answer Fill a bubble to check yourself
D Correct answer
Multiple choice physics fluid pressure pressure in air introduction to atmospheric pressure pressure exerted by air devices to measure pressure

Suppose the density of air at Hyderabad is $\rho _ { 0 }$ and atmospheric pressure is $P _ { \mathrm { atm } }$.Suppose we wish to calculate the pressure $P$ at a height $10 \mathrm { km }$ above Hyderabad. If we use the equation $P _ { 0 } - P = \rho g z$ to calculate $P$ with $z = 10 km$. But if we take only variation of $\rho$ with height we get $P _1$. if we take only of $g$ with height we get $P _2$, if we take both $\rho$ and $g$ variations with height we get $P _3$. Then 

  1. $P = P _ { 1 } = P _ { 2 } = P _ { 3 }$

  2. $P _ { 3 } < P _ { 1 }$

  3. $P _ { 2 } > P$

  4. $P _ { 0 } - P > P _ { 0 } - P _ { 3 }$

Reveal answer Fill a bubble to check yourself
C Correct answer
Multiple choice physics fluid pressure pressure in air introduction to atmospheric pressure pressure exerted by air devices to measure pressure

An air bubble doubles its radius on rising from the bottom of water reservoir to the surface of water in it. If the atmospheric pressure is equal to $10 m $ of water, the height of water in the reservation s- 

  1. $ 10m $

  2. $20 m$

  3. $70 m$

  4. $80 m$

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Using Boyle's Law: P1V1 = P2V2. P1 = P_atm + rho*g*h. P2 = P_atm. Volume increases 8 times (2^3). P_atm + rho*g*h = 8 * P_atm. h = 7 * P_atm / (rho*g). Since P_atm = 10m of water, h = 7 * 10m = 70m.

Multiple choice physics fluid pressure pressure in air introduction to atmospheric pressure pressure exerted by air devices to measure pressure

A cubical block of steel each side '$\ell $' is floating in mercury in a vessel. The densities of steel and mercury are ${ p } _{ s }\quad and\quad { p } _{ m }$ .The height of block above the mercury level is given by.

  1. $\ell \left( 1+\dfrac { { p } _{ s } }{ { p } _{ m } } \right) $

  2. $\ell \left( 1-\dfrac { { p } _{ s } }{ { p } _{ m } } \right) $

  3. $\ell \left( 1+\dfrac { { p } _{ m } }{ { p } _{ s } } \right) $

  4. $\ell \left( 1-\dfrac { { p } _{ m } }{ { p } _{ s } } \right) $

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

By Archimedes' principle, the weight of the block equals the weight of the displaced mercury. rho_s * L^3 * g = rho_m * (L^2 * (L - h)) * g. Solving for h (height above surface) gives h = L * (1 - rho_s/rho_m).

Multiple choice physics fluid pressure pressure in air introduction to atmospheric pressure pressure exerted by air devices to measure pressure

A flask of volume $10^3cc$ is completely filled with mercury at $0^oC.$ The co-efficient of cubical expansion of mercury is $180\times10^{-6} /^oC$ at that of glass is $40\times10^{-6}/^oC.$ If flask is placed in boiling water at $100^oC,$ how much mercury will overflow   

  1. $7cc$

  2. $14cc$

  3. $21cc$

  4. $28cc$

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The overflow volume is given by V * (gamma_mercury - gamma_glass) * delta_T. Overflow = 1000 * (180 - 40) * 10^-6 * 100 = 1000 * 140 * 10^-4 = 14 cc.

Multiple choice physics fluid pressure pressure in air introduction to atmospheric pressure pressure exerted by air devices to measure pressure

Positive and negative ions are produced in the atmosphere due to cosmic rays from space and also due to radioactive element in the soil . in some region in the atmosphere the electric field strength is 100 V/m in the vertically downwaeds direction. This field exerts force on the positive and negative ions in the given region in atmosphere . as a result, positive ions , having a density $ 500/cm^3 $ drift downward while negative ions , havig a density $ 300/cm^3 $ drift upward al these ions are singly charged. it is observed that the conductivity in the given region is $ 4 \times 10^{-13} $ $ (\Omega -m)^{-1} $ . find the average speed of ions, assuming it to be the same for positive and negative ions.

  1. $1.3 m/s$

  2. $0.31 m/s$

  3. $0.93 m/s$

  4. $1.6 m/s$

Reveal answer Fill a bubble to check yourself
D Correct answer