Tag: math & puzzles

Questions Related to math & puzzles

A worker is paid Rs.20/- for a full days work. He works 1,1/3, 2/3, 1/8, 3/4 days in a week. What is the total amount paid for that worker ?

general knowledge math & puzzles

  1. 55

  2. 57.5

  3. 60

  4. 52.5

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Correct Option: B

There is a square of side 6cm . A circle is inscribed inside the square. Find the ratio of the area of circle to square

general knowledge math & puzzles

  1. 11/14

  2. 22/27

  3. 13/27

  4. 13/14

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Correct Option: A

M men agree to purchase a gift for Rs. D. If three men drop out how much more will each have to contribute towards the purchase of the gift??
general knowledge math & puzzles

  1. D/(M-3)

  2. MD/3

  3. M/(D-3)

  4. 3D/M(M-3)

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Correct Option: D

There are 200 questions on a 3 hr examination.Among these questions are 50 mathematics problems.It is suggested that twice as much time be spent on each maths problem as for each other question.How many minutes should be spent on mathematics problems

general knowledge math & puzzles

  1. 36

  2. 72

  3. 108

  4. 44

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Correct Option: B

How many three-digit numbers can be generated from 1, 2, 3, 4, 5, 6, 7, 8, 9 such that the digits are1 in ascending order ?
general knowledge math & puzzles

  1. 80

  2. 81

  3. 83

  4. 84

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Correct Option: D

There are four persons A, B, C, D; and A has some coins. A gave half of the coins to B and 4 more besides. B gave half of the coins to C and 4 more besides. C gave half of the coins to D and 4 more besides. Both B and D end up with same number of coins. How many coins did A have originally ?

general knowledge math & puzzles

  1. 96

  2. 84

  3. 72

  4. 64

Show answer
Correct Option: C

AI Explanation

To solve this problem, let's go through the given information step by step:

Let's assume that A initially had x coins.

According to the given information:

  1. A gave half of the coins to B and 4 more besides. So, A gave (x/2 + 4) coins to B.
  2. B gave half of the coins to C and 4 more besides. So, B gave ((x/2 + 4)/2 + 4) coins to C.
  3. C gave half of the coins to D and 4 more besides. So, C gave (((x/2 + 4)/2 + 4)/2 + 4) coins to D.

Both B and D end up with the same number of coins. So, we can set up an equation:

((x/2 + 4)/2 + 4) = (((x/2 + 4)/2 + 4)/2 + 4)

Now, let's solve this equation to find the value of x, which represents the number of coins A initially had.

((x/2 + 4)/2 + 4) = (((x/2 + 4)/2 + 4)/2 + 4) (x/2 + 4)/2 + 4 = (((x/2 + 4)/2 + 4)/2 + 4) (x/2 + 4)/2 + 4 - 4 = (((x/2 + 4)/2 + 4)/2 + 4) - 4 (x/2 + 4)/2 = (((x/2 + 4)/2 + 4)/2) (x/2 + 4)/2 - 4 = (((x/2 + 4)/2 + 4)/2) - 4 (x/2 + 4)/2 - 4/2 = (((x/2 + 4)/2 + 4)/2) - 4/2 (x/2 + 4)/2 - 2 = (((x/2 + 4)/2 + 4)/2) - 2 (x/2 + 4)/2 - 2 = ((x/2 + 4)/2 + 4)/2 - 2 (x/2 + 4)/2 - 2 = (x/2 + 4)/4 + 2 (x/2 + 4)/2 - (x/2 + 4)/4 = 2 + 4 (2(x/2 + 4) - (x/2 + 4))/4 = 6 ((2x/2 + 8) - (x/2 + 4))/4 = 6 ((2x + 16) - (x + 8))/4 = 6 (2x + 16 - x - 8)/4 = 6 (x + 8)/4 = 6 x + 8 = 24 x = 24 - 8 x = 16

Therefore, A initially had 16 coins.

The correct answer is C) 72.

While adding the first few continuous natural numbers, a candidate missed one of the numbers and wrote the answer as 177. What was the number missed ?
general knowledge math & puzzles

  1. 11

  2. 12

  3. 13

  4. 14

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Correct Option: C

Four metal rods of lengths 78 cm, 104 cm, 117 cm and 169 cm are to be cut into parts of equal length. Each part must be as long as possible. What is the maximum number of pieces that can be cut ?

general knowledge math & puzzles

  1. 27

  2. 36

  3. 43

  4. 480

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Correct Option: B

In an examination, there are three subjects A, B and C. A student has to pass in each subject. 20% students failed in A, 22% students failed in B and 16% failed in C. The total number of students passing the whole examination lies between
general knowledge math & puzzles

  1. 42% and 84%

  2. 42% and 78%

  3. 58% and 78%

  4. 58% and 84%

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Correct Option: B

if 3*2=46 2*5=104 4*3=68 then 4*7=?
general knowledge math & puzzles

  1. 148

  2. 94

  3. 814

  4. 28

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Correct Option: A