Tag: technology

Questions Related to technology

  1. Sum up value in the fields specified in the SORT FIELDS statement and keep it as only one occurence in the o/p

  2. Removes the duplicates for the fields specified in the SORT FIELDS statement and keeps only the 1st occurence of it

  3. Works only for those records in the i/p file where no duplicates for the fields specified in SORT FIELDS statement,

  4. None of the above


Correct Option: B
  1. SORT FIELDS = (1,10,CH,A),SKIPREC= 10

  2. SORT FILEDS = (1,10,CH,A),SIZE = 10

  3. Sort FIELDS = (1,10,CH,A),STOPAFT = 10

  4. Sort FIELDS = (1,10,CH,A),EQUALS = 10


Correct Option: C
  1. F (Fixed), V (Variable), D (ISCII/ASCII Variable)

  2. F (Fixed), V (Variable)

  3. No types are specified in the Record Statement

  4. FI (Fixed), VA (Variable)


Correct Option: A
  1. Function call:- changeName(im); Function implementation :- { im.name = "Done"; return null; }

  2. Function call:- changeName(im); Function implementation :- { im = new Item("Done"); return null; }

  3. Function call :- im = changeName(im); function implementation :- { Item otherObject = new Item("Done"); return otherObject; }

  4. All of the above


Correct Option: B

Which is simplest code snippet you will add in the main function to set the name attribute of 50th in the ItemList to “Done”?

  1. im.name = "Done";

  2. Item otherObject = new Item(“Done”); itemList.set(49, otherObject);

  3. ((Item)itemList.get(49)).name = “Done”;

  4. None of above is correct as they are not changing 50th element.


Correct Option: A

Which is simplest and correct code snippet needs to be put in the main function to replace the value object of the HashMap for the key “orange”?

  1. itemMap.remove("orange"); itemMap.put("orange", new Item("Orange") );

  2. ((Item)itemMap.get(“orange”)).name = “Orange”;

  3. itemMap.put("orange", new Item("Orange") );

  4. None of above


Correct Option: B

Which is the most performance efficient implementation for assignCode method from the given options?

  1. code attribute cannot be changed as Item class doesn’t have setter method for it.

  2. for (int i = 0; i < itemList.size(); i++) { if(itemList.get(i) != null) { ((Item)itemList.get(i)).code = 50+i; } }

  3. int i = 0; Item im = null; while (i < itemList.size()) { im = (Item)itemList.get(i); if(im != null) { im.code = 50+i; } i++; }

  4. int i = 0; Item im = null; Iterator itr = itemList.iterator(); while (itr.hasNext()) { im =(Item) itr.next(); im.code = 50+i; i++; }


Correct Option: D
  1. SORT FIELDS=(1,5,ZD,A) OUTREC FIELDS=(1:SEQNUM,5,ZD,6:6,295)

  2. SORT FIELDS=(1,5,BI,A) OUTREC FIELDS=(1:SEQNUM,5,BI,6:6,295)

  3. SORT FIELDS=(1,5,ZD,A) OUTREC FIELDS=(1:RESEQ,5,ZD,6:6,300)

  4. None of the above


Correct Option: A