Tag: technology

Questions Related to technology

How does SUM FIELDS = NONE work?
technology mainframe

  1. Sum up value in the fields specified in the SORT FIELDS statement and keep it as only one occurence in the o/p

  2. Removes the duplicates for the fields specified in the SORT FIELDS statement and keeps only the 1st occurence of it

  3. Works only for those records in the i/p file where no duplicates for the fields specified in SORT FIELDS statement,

  4. None of the above

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Correct Option: B

In the i/p file A contains the records in the following sequence: Arun 20 Naveen40 Priya 35 Naveen10 Priya 25 Arun 50 If the following SORT query runs on file A, how would the o/p file B look like: SORT FIELDS = (1,6,CH,A) SUM FILEDS = (7,2,PD)
technology mainframe

  1. Arun 50 Arun 20 Naveen10 Naveen40 Priya 25 Priya 35

  2. Priya 60 Naveen50 Arun 70

  3. Arun 70 Naveen50 Priya 60

  4. Naveen50 Priya 60 Arun 70

Show answer
Correct Option: C

How should the SORT statement be used to copy only 10 records with the EMP name 'Anil' to the o/p file, where the Emp name is in the 1st 10 chars of the i/p file?
technology mainframe

  1. SORT FIELDS = (1,10,CH,A),SKIPREC= 10

  2. SORT FILEDS = (1,10,CH,A),SIZE = 10

  3. Sort FIELDS = (1,10,CH,A),STOPAFT = 10

  4. Sort FIELDS = (1,10,CH,A),EQUALS = 10

Show answer
Correct Option: C

what are the different types that can be provided in the RECORD Statement?
technology mainframe

  1. F (Fixed), V (Variable), D (ISCII/ASCII Variable)

  2. F (Fixed), V (Variable)

  3. No types are specified in the Record Statement

  4. FI (Fixed), VA (Variable)

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Correct Option: A

Which code from the given options if put in Main class will not print “Done”?

technology programming languages

  1. Function call:- changeName(im); Function implementation :- { im.name = "Done"; return null; }

  2. Function call:- changeName(im); Function implementation :- { im = new Item("Done"); return null; }

  3. Function call :- im = changeName(im); function implementation :- { Item otherObject = new Item("Done"); return otherObject; }

  4. All of the above

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Correct Option: B

Which is simplest code snippet you will add in the main function to set the name attribute of 50th in the ItemList to “Done”?
technology programming languages

  1. im.name = "Done";

  2. Item otherObject = new Item(“Done”); itemList.set(49, otherObject);

  3. ((Item)itemList.get(49)).name = “Done”;

  4. None of above is correct as they are not changing 50th element.

Show answer
Correct Option: A

Which of the given options code is correct and will not waste memory. Note :- Defination of the Class Item is class Item { public int code; public String name; public Item(String name) { this.name = name; } } itemList is ArrayList containing 50 objects of Class Items.

technology programming languages

  1. Item im = new Item(null); im = (Item ) itemList.get(0);

  2. Item im = new Item(“Done”); im = (Item ) itemList.get(0);

  3. Item im = null; im = (Item ) itemList.get(0);

  4. All of the above.

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Correct Option: C

Which is simplest and correct code snippet needs to be put in the main function to replace the value object of the HashMap for the key “orange”?

technology programming languages

  1. itemMap.remove("orange"); itemMap.put("orange", new Item("Orange") );

  2. ((Item)itemMap.get(“orange”)).name = “Orange”;

  3. itemMap.put("orange", new Item("Orange") );

  4. None of above

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Correct Option: B

Which is the most performance efficient implementation for assignCode method from the given options?

technology programming languages

  1. code attribute cannot be changed as Item class doesn’t have setter method for it.

  2. for (int i = 0; i < itemList.size(); i++) { if(itemList.get(i) != null) { ((Item)itemList.get(i)).code = 50+i; } }

  3. int i = 0; Item im = null; while (i < itemList.size()) { im = (Item)itemList.get(i); if(im != null) { im.code = 50+i; } i++; }

  4. int i = 0; Item im = null; Iterator itr = itemList.iterator(); while (itr.hasNext()) { im =(Item) itr.next(); im.code = 50+i; i++; }

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Correct Option: D

How do we resequence a file through the Sort statement where the file record length is 300 bytes and the sequence number is present in the 1st 5 bytes?
technology mainframe

  1. SORT FIELDS=(1,5,ZD,A) OUTREC FIELDS=(1:SEQNUM,5,ZD,6:6,295)

  2. SORT FIELDS=(1,5,BI,A) OUTREC FIELDS=(1:SEQNUM,5,BI,6:6,295)

  3. SORT FIELDS=(1,5,ZD,A) OUTREC FIELDS=(1:RESEQ,5,ZD,6:6,300)

  4. None of the above

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Correct Option: A