Tag: lowest form of a fraction

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Questions Related to lowest form of a fraction

Multiple choice maths fraction lowest form of a fraction simplest ratio lowest form of fractions

Reduce fraction to lowest form:
$\dfrac{144}{36}$

  1. $\dfrac{4}{1}$
  2. $\dfrac{12}{2}$
  3. $\dfrac{1}{36}$
  4. $\dfrac{4}{9}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$\dfrac{144}{36}$


Dividing numerator and denominator by $12$, we get
$\dfrac{144}{36} = \dfrac{12}{3}$

Dividing both numerator and denominator again by $3$, we get

$\dfrac{12}{3} = \dfrac{4}{1}$

This is the lowest form

Multiple choice maths fraction lowest form of a fraction simplest ratio lowest form of fractions

Reduce fraction to lowest form:
$\dfrac{125}{625}$

  1. $\dfrac{1}{5}$
  2. $\dfrac{12}{625}$
  3. $\dfrac{5}{625}$
  4. $\dfrac{15}{25}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$\dfrac{125}{625}$


Dividing numerator and denominator by $25$, we get
$\dfrac{125}{625} = \dfrac{5}{25}$

Dividing again both numerator and denominator by $5$, we get

$\dfrac{5}{25} = \dfrac{1}{5}$

This is the lowest form

Multiple choice maths fraction lowest form of a fraction simplest ratio lowest form of fractions

Which of these statements is CORRECT?

  1. $\dfrac {3}{6}$ and $\dfrac {1}{2}$ are equivalent fractions
  2. $\dfrac {1}{2}$ of an hour is equal to $20$ minutes
  3. $\dfrac {5}{6}$ is equal to $\dfrac {6}{5}$
  4. $1\ mm$ is $\dfrac {1}{100}$ of $1\ cm$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

(A) $\dfrac {3}{6} = \dfrac {3\div 3}{6\div 3} = \dfrac {1}{2}$
(B) $\dfrac {1}{2}$ of an hour $= \dfrac {1}{2}\times 60$ minutes = $30$ minutes
(C) $\dfrac {5}{6} = 0.8333, \dfrac {6}{5} = 1.2$
$\therefore \dfrac {5}{6}\neq \dfrac {6}{5}$
(D) $\dfrac {1}{100}$ of $1$ cm = $\dfrac {1}{100}\times 10$ mm = $\dfrac {1}{10}$ mm.

Hence the correct answer is option A.

Multiple choice maths fraction lowest form of a fraction simplest ratio lowest form of fractions

A fraction $\displaystyle\frac{x}{y}$ can be expressed as a terminating decimal if y has no prime factors other than _________.

  1. $2, 3$
  2. $3, 5$
  3. $2, 5$
  4. $2, 3, 5$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

If the denominator has a prime factor $2$ or $5$ then it is a terminating decimal

Hence the correct answer is option C

Multiple choice maths fraction lowest form of a fraction simplest ratio lowest form of fractions

The value of $\left(\displaystyle 1-\frac{1}{3}\right)\left(\displaystyle 1-\frac{1}{4}\right)\left(\displaystyle 1-\frac{1}{5}\right)\left(\displaystyle 1-\frac{1}{6}\right).....\left(\displaystyle 1-\frac{1}{n}\right)$ is _________.

  1. $\displaystyle\frac{1}{n}$
  2. $\displaystyle\frac{2}{n}$
  3. $\displaystyle\frac{2(n-1)}{4}$
  4. $\displaystyle\frac{2}{n(n+1)}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
We need to find value of $\left(1-\dfrac {1}{3}\right)\left (1-\dfrac {1}{4}\right)\left (1-\dfrac {1}{5}\right)\left(1-\dfrac {1}{6}\right).....\left (1-\dfrac {1}{n}\right)$
Solving each bracket, we get 
$\dfrac{2}{3} \times \dfrac{3}{4} \times \dfrac{4}{5} . . . . ...\dfrac{n-3}{n-2}\times \dfrac{n-2}{n-1} \times \dfrac{n-1}{n}$
Starting from $1^{st}$ term each denominator is cancelled out by next numerator.
Finally, we get $\dfrac{2}{n}$
Multiple choice maths fraction lowest form of a fraction simplest ratio lowest form of fractions

The product of the $9$ fractions $\left(\displaystyle 1-\frac{1}{2}\right)\left(\displaystyle 1-\frac{1}{3}\right)\left(\displaystyle 1-\frac{1}{4}\right)..........\left(\displaystyle 1-\frac{1}{10}\right)=$____________.

  1. $\displaystyle\frac{10}{11}$
  2. $\displaystyle\frac{1}{9}$
  3. $\displaystyle\frac{1}{10}$
  4. $\displaystyle\frac{1}{2}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
We need to simplify $\left (1-\dfrac {1}{2}\right)\left (1-\dfrac {1}{3}\right)\left (1-\dfrac {1}{4}\right).....\left (1-\dfrac {1}{10}\right)$
Simplifying each bracket, we get
$\dfrac{1}{2} \times \dfrac{2}{3} \times \dfrac{3}{4} . . . . ...\dfrac{7}{8}\times \dfrac{8}{9} \times \dfrac{9}{10}$
As we can see 
Starting from $1^{st}$ term, each denominator is cancelled out by next numerator.
Finally we get $\dfrac{1}{10}$