Tag: measuring distance of celestial bodies

Questions Related to measuring distance of celestial bodies

Which of the following is different from others?

  1. Micron

  2. Light year

  3. Mole

  4. Angstrom


Correct Option: C
Explanation:

Micron, light year and Angstrom are the units of distance whereas mole is the measure of amount of substance in a matter. So, mole is different from others.

One angstrom is equal to _________ .

  1. $\displaystyle { 10 }^{ -12 }m$

  2. $\displaystyle { 10 }^{ -10 }m$

  3. the time taken by Neil Armstrong to reach the moon

  4. the distance travelled by Neil Armstrong on the surface of the moon


Correct Option: B
Explanation:
Angstrom is a very small unit of distance.
$1 \ angstrom = 10^{-10} \ m$

Which of the following is not the unit of length ?

  1. Micron

  2. Light year

  3. Angstrom

  4. Radian


Correct Option: D
Explanation:

Angstrom, Micron and light year are all units of length but radian is the unit of angle subtended.

Angstrom is a unit used to express

  1. length

  2. mass

  3. time

  4. none of these


Correct Option: A
Explanation:
Angstrom is a unit to express length.
$1 \ A^o = 10^{-10} \ m$

Par sec is a unit of:

  1. angle

  2. velocity

  3. time

  4. distance


Correct Option: D
Explanation:

The parsec is a unit of length used to measure the large distances to astronomical objects outside the Solar System. One parsec is approximately equal to 31 trillion kilometres or about 3.26 light-years. One parsec is the distance to an object whose parallax angle is one arcsecond.

1 quintal is equal to

  1. $\displaystyle \frac { 1 }{ 10 } $ kg

  2. 10 kg

  3. 100 kg

  4. 1000 kg


Correct Option: C
Explanation:
Quintal is a unit of mass.
1 quintal $=$ 100 kg

1 light year is equal to 

  1. $\displaystyle 6.3\times { 10 }^{ 5 }\overset { o }{ A } $

  2. $\displaystyle 6.3\times { 10 }^{ 4 }$$AU$

  3. $\displaystyle 3.0\times { 10 }^{ 16 }{ ms }^{ -1 }$

  4. $\displaystyle 6.3\times { 10 }^{ 4 }\overset { o }{ A } $


Correct Option: B
Explanation:
We know that   $1 \ light year  = 9.46\times 10^{15} \ m$
Also,   $1 \ AU = 1.5\times 10^{11} \ m$
Thus   $1 \ light year  = \dfrac{9.46\times 10^{15}}{1.5\times 10^{11}}  \ AU= 6.3\times 10^4 \ AU$

Pound is the unit of ________ in the F.P.S. system.

  1. mass

  2. length

  3. time

  4. temperature


Correct Option: A
Explanation:

Pound is a unit of mass in the F.P.S. system.

1 parsec is equal to

  1. $\displaystyle 3.1\times { 10 }^{ 15 }m$

  2. $\displaystyle 3.1\times { 10 }^{ -15 }m$

  3. $\displaystyle 3.1\times { 10 }^{ 16 }m$

  4. $\displaystyle 3.1\times { 10 }^{ -16 }m$


Correct Option: C
Explanation:
Parsec is the unit of distance.
$1 \ $ parsec $ = 3.1\times 10^{16} \ m$

1 light year is equal to

  1. $\displaystyle 9.46\times { 10 }^{ -15 }m$

  2. $\displaystyle 9.46\times { 10 }^{ 15 }m$

  3. $\displaystyle 9.46\times { 10 }^{ -13 }m$

  4. $\displaystyle 9.46\times { 10 }^{ 13 }m$


Correct Option: B
Explanation:
One light-year is defined as the distance traveled by light in a vacuum in one year.

Number of seconds in 1 year is:
$1 year=365\times24\times\times60\times60\\=3.15\times10^7\ sec$

So,
$1 \ light \ year =3\times10^8\times3.15\times10^7\\= 9.46\times 10^{15} \ m$