Tag: compounds of nitrogen - ammonia

Questions Related to compounds of nitrogen - ammonia

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Freshly prepared pure dilute solution of sodium in liquid ammonia :

  1. shows copper-bronze colour.

  2. occupy larger volume than that from the sum of the volumes of $Na$ and $NH _{3}(1)$.
  3. reduced the $GeH _{4}$ to $GeH _{2}^{-}$.
  4. produced sodium amide and hydrogen gas with rusty iron wire.

Reveal answer Fill a bubble to check yourself
A,D Correct answer
Explanation

In dilute solutions  of $Na$ in ammonia, the solvated electrons have a deep blue colour.

In more concentrated solutions, the solution takes on a bronze/copper colour.

The solution of sodium in liquid ammonia is quite stable on its own.

You need to add a small amount of a catalyst such as ${ FeCl } _{ 3 }$ for the sodium to react with the ammonia to form sodium amide and hydrogen gas.

$2N{ a } _{ (s) }+2N{ H } _{ 3(l) }\underrightarrow { \quad FeC{ l } _{ 3 } } 2NaN{ H } _{ 2 }(N{ H } _{ 3 })+{ H } _{ 2(g) }$
conclusion : hence the option (A) and(D) is correct.

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Which of the following are correct statements?

  1. $NH _3$ can be used as a refrigerant
  2. NO is heavier than $O _2$
  3. Nitrogen diffuses fastre than $O _2$
  4. $NO _2$ is a colourless gas
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Ammonia is amongst the oldest of all there frigerants and still used widely in the refrigeration applications. It is also the only refrigerant outside the halo-carbons group, still being used to a great extent.Ammonia refrigerant is commonly known as R717 and its chemical formula is $NH _3$.

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Which of the following can be classified as a molecular hydride ?

  1. $LiH$
  2. $\mathrm { NH } _ { 3 }$
  3. $\mathrm { NiHO } _ { 6 }$
  4. $\mathrm { MgH } _ { 2 }$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
Hydride is the product when hydrogen reacts with any other elements, except the noble gases. So hydrides are compounds where one atom is hydrogen to another more electropositive element. A hydride is an anion of hydrogen $(H^-)$.
Bonding between hydrogen & other elements is always covalent. General chemical formula of a hydride is $MH _{x}$ where   $M=$ other element with hydrogen makes a binary compound. $x=$ no. of hydrogen atoms.
Covalent or Molecular hydrides
Hydrogen atoms from a covalent bond with $p-$block atoms. General chemical formula$-XH _{(8-n)}$ where $n=$no. of electrons the element has in its atomic shell.
$NH _{3}$ is $c$ molecular hydride
$3H _{2(g)}+N _{2(g)}\rightarrow 2NH _{3(g)}$
Answer is $B)\ NH _{3}$

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

When chlorine reacts with a gas X, an explosive inorganic compound Y is formed. Then X and Y will be :

  1. $\displaystyle X=O _{2}$ and $\displaystyle Y=NCl _{3}$
  2. $\displaystyle X=NH _{3}$ and $\displaystyle Y=NCl _{3}$
  3. $\displaystyle X=O _{2}$ and $\displaystyle Y=NH _{4}Cl$
  4. $\displaystyle X=NH _{3}$ and $\displaystyle Y=NH _{4}Cl$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

When $NH _3$ reacts with excess of $Cl$ an explosive substance $NCl _3$ is formed.
$NH _3 + 3Cl _2 \rightarrow NCl _3 + 3HCl$
X is $NH _3$ and Y is $NCl _3$. 

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Ammonia cannot be dried over regular dehydrating agent like: 

  1. $H _{2}SO _{4}$
  2. $P _{2}O _{5}$
  3. Anhydrous $CaCl _{2}$
  4. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Ammonia cannot be dried by passing over conc. sulphuric acid because ammonia gas reacts chemically with conc. sulphuric acid to form ammonium sulphate.
2NH3 + H2SO4 (conc.) $\rightarrow$(NH4)2SO4.

Multiple choice chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

Identify $(E)$ and $(F)$ in the following:
$CaCO _3\rightarrow \underset{(g)}{(A)}+\underset{(solid)}{(B)}$

$(B)+H _2O\rightarrow (C)\overset{(A)}{\rightarrow}(D)\overset{(A)excess}{\rightarrow}(E)$

$(A)+NH _3\overset{\Delta}{\rightarrow}(F)$

  1. $(E)\ Ca(HCO _3) _2;\ (F)\ NHCONH _3$
  2. $(E)\ Ca(HCO _3); \ (F)\ NH _3CONH$
  3. $(E) \ Ca(HCO _3) _2; \ (F)\ NH _2CONH _2$
  4. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$CaCO _3\rightarrow \underset{(g)}{CO _2}+\underset{(solid)}{CaO}$
$CaO+H _2O\rightarrow (Ca(OH) _2)\overset{(CO _2)}{\rightarrow}(CaCO _3)\overset{(CO _2)excess}{\rightarrow}(Ca(HCO _3) _2)$
$(CO _2)+NH _3\overset{\Delta}{\rightarrow}(NH _2CONH _2)$
Hence option C is correct.