Tag: ammonia

Questions Related to ammonia

Ammonia burns with oxygen to give :

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. nitrogen and water vapour

  2. nitrogen and steam

  3. both a and b

  4. none

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Correct Option: C
Explanation:

${ 4NH } _{ 3 }+{ 3O } _{ 2 }\rightarrow { 2N } _{ 2 }+{ 6H } _{ 2 }O$

Ammonia burns with oxygen to give water vapour or steam.

Which of the following compounds are formed by the reaction of ammonia with acids?

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. Calcium ammonium nitrate

  2. Ammonium chloride

  3. Ammonium phosphate

  4. Ammonium sulphate

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Correct Option: A,B,C,D
Explanation:

$NH _3$ is a base and it forms salt with acids.
Ammonia reacts with Nitric acid to form ammonium nitrate and on further addition with Calcium carbonate it forms Calcium ammonium nitrate.

Ammonia gas cannot be dried by passing through:

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. conc. $H _{2}SO _{4}$

  2. anhydrous $CaO$

  3. $P _{2}O _{5}$

  4. $CuSO _{4}$

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Correct Option: A,C
Explanation:

Conc. $H _{2}SO _{4}$ & $P _{2}O _{5}$ can't be used to dry Ammonia gas.

Identify the probable products for the reaction of $NH _{3}$ with $Cl _{2}$.

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. $N _{2}$ and $NH _{4}Cl$

  2. $NCl _{3}$ and $HCl$

  3. $N _{2}$ and $NCl _{3}$

  4. $NH _{4}Cl$ and $HCl$

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Correct Option: A,B
Explanation:

If $NH _3$ is in excess then $8NH _3 + 3Cl _2 \rightarrow 6NH _4Cl + N _2$
If $Cl _2$ is in excess then $NH _3 + 3Cl _2 \rightarrow NCl _3 + 3HCl$

In Ammonia-Boron trifluoride complex, the donor molecule is Ammonia.

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. True

  2. False

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Correct Option: A
Explanation:

In Ammonia-Boron trifluoride complex ($H _3N \rightarrow BF _3$), the donor molecule is ammonia and the acceptor molecule is boron trifluoride. N atom of ammonia donates a lone pair of electrons to B atom of boron trifluoride and forms co-ordinate covalent bond.

$NH^+ _4$ is iso structural with:

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. $PCl _3$

  2. $CH _4$

  3. $BF _3$

  4. ${NO _3}^{-}$

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Correct Option: B
Explanation:

$NH^+ _4$ is iso structural with $CH _4$. Both have tetrahedral geometry.$N$ atom in $NH^+ _4$ and $C$ atom in $CH _4$ have 4 bond pairs and zero lone pairs of electrons.

$S _1$: AgCl with liquid ammonia forms a complex $[Ag(NH _3) _2]^+$.
$S _2$: Ammonium dichromate on heating decomposes to give nitrogen and a green colored compound.
$S _3$: CaNCN on hydrolysis produces a white precipitate and a gas which turns filter paper moistened with copper sulphate solution deep blue.

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. T T T

  2. T F T

  3. F F T

  4. T T F

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Correct Option: A
Explanation:

$AgCl+NH _3\rightarrow [Ag(NH _3) _2]^++Cl^-$
$(NH _4)Cr _2O _7\xrightarrow {\Delta}N _2+Cr _2O _3+4H _2O$
$CaNCN+3H _2O\rightarrow \underset {(white\ ppt.)}{CaCO _3}+2NH _3$
So, all the three statements are correct.

The reaction between two different gases produce a solid substance as product always.

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. True

  2. False

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Correct Option: B

Geometry of ammonia molecule and the hybridisation of nitrogen involved in it are: 

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. $sp^3$- hybridisation and tetrahedral geometry

  2. $sp^3$- hybridisation and distorted tetrahedral geometry

  3. $sp^2$- hybridisation and trianguklar geometry

  4. none of the above

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Correct Option: B
Explanation:

(i) Hybridisation $= \frac{1}{2}$ [no.of $e^-$ in valence shell of central atom + no. of monovalent atoms + charge on anion - charge on cation]
(ii) Shape or geometry of molecule depends on lone pair and bond pair of electrons present in it.
Hybridisation  of N in $NH _3$
$=\frac{1}{2}(5+3+0)$
$=4$
$\therefore sp^3$ hybridisation.
$\because$, its has 3 bond pair and 1 lone pair of electrons, so it has distorted tetrahedron shape. 

Carbonyl chloride react with ammonia to give:

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. Urea

  2. Acetone

  3. Acetamide

  4. Chloroform

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Correct Option: C
Explanation:

carbonyl chloride is $COCl _2$.the reaction between $COCl _2$&$NH _3$ is given as 

$COCl _2+NH _3\longrightarrow ClCONH _2+HCl$