If $\cfrac{7}{m-\sqrt{3}} = \cfrac{\sqrt{3}}{m} + \cfrac{4}{2m}$, calculate the value of $m$.
$-3.464$
$-1.978$
$-0.918$
$1.978$
Given $\dfrac { 7 }{ m-\sqrt { 3 } } =\dfrac { \sqrt { 3 } }{ m } +\dfrac { 4 }{ 2m } =\dfrac { 4+2\sqrt { 3 } }{ 2m } $$\Rightarrow 14m=(4+2\sqrt { 3 } )m-\sqrt { 3 } (4+2\sqrt { 3 } )$$ \Rightarrow (10-2\sqrt { 3 } )m=-4\sqrt { 3 } -6$$\Rightarrow m=\dfrac { -4\sqrt { 3 } -6 }{ 10-2\sqrt { 3 } } =\dfrac { -12.928 }{ 6.536 } =-1.98$