Tag: study of diborane

Questions Related to study of diborane

Multiple choice chemistry the p-block elements - group 13 study of diborane some important compounds of boron study of boron
All the $Al-Cl$ bonds in $Al _2Cl _6$ are equivalent.
  1. True

  2. False

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The given statement is False.
All the  $\displaystyle Al-Cl$ bonds in $\displaystyle Al _2Cl _6$ are not equivalent.
Two types of bonds are present in $\displaystyle Al _2Cl _6$, terminal $\displaystyle Al-Cl$ bonds that are normal $\displaystyle 2c-2e$ bonds and $\displaystyle Al-Cl-Al$ bridges that are $\displaystyle 3c-4e$ bonds.

Multiple choice chemistry the p-block elements - group 13 study of diborane some important compounds of boron study of boron

From $B _2H _6$, all the following can be prepared except :

  1. $B _2O _3$
  2. $H _3BO _3$
  3. $B _2(CH _3) _6$
  4. $NaBH _4$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
$B _2H _6+3O _2\rightarrow B _2O _3+3H _2O+Heat$

$B _2H _6+6H _2O\rightarrow H _3BO _3+6H _2$

$2NaH+B _2H _6\rightarrow etherNaBH _4$

From $B _2H _6$, all can be prepared except $B _2(CH _3) _6$

Hence option $C$ is correct.
Multiple choice chemistry the p-block elements - group 13 study of diborane some important compounds of boron study of boron

Which of the following statement is/are correct regarding $B _{2}H _{6}$?

  1. Banana bonds are longer but stronger than normal $B-H$ bonds
  2. $B _{2}H _{6}$ is also known $3c-2e$ compound
  3. The hybrid state of B in $B _{2}H _{6}$ is $sp^{3}$ while that of $sp^{2}$ in $BH _{3}$
  4. It cannot be prepared by reacting $BF _{3}$ with $LiBH _{3}$ in the presence of dry ether
Reveal answer Fill a bubble to check yourself
B,C Correct answer
Multiple choice chemistry the p-block elements - group 13 study of diborane some important compounds of boron study of boron

In which of the following molecules is hydrogen bond absent?

  1. Water

  2. Inorganic benzene

  3. Diborane

  4. Methanol

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

As there is no lone pair of electrons present on the boron in diborane it do not form a hydrogen bond.But in water inorganic benzene and methanol there is a lone pair of electrons on oxygen, nitrogen and oxygen respectively so they form hydrogen bonding between most electronegative atom like nitrogen oxygen and hydrogen.
Hence option $D$ is correct.