Tag: applications of floatation

Questions Related to applications of floatation

Multiple choice physics upthrust in fluids, archimedes' principle and floatation applications of floatation principle of floatation and its applications when do objects float on water?

A person of mass $m$ is standing on one end of a plank of mass $M$ and length $L$ and floating in water. The person moves from one end to another and stops. The displacement of the plank is :

  1. $\dfrac {Lm}{(m+M)}$
  2. $Lm(M+m)$
  3. $\dfrac {(m+M)}{Lm}$
  4. $\dfrac {LM}{(m+M)}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Since there is no external horizontal force, the center of mass of the system remains stationary. m*x + M*X = 0, where x and X are displacements. The person moves distance L relative to the plank, so x_person = L - X_plank. Solving m(L - X) + MX = 0 gives X = -mL / (m+M). The magnitude is mL / (m+M).

Multiple choice physics upthrust in fluids, archimedes' principle and floatation applications of floatation principle of floatation and its applications when do objects float on water?

A beaker containing water weighs $100$ g. It is placed on the pan of a balance and a piece of metal  weighing 70 g and having a volume of $10c{m^3}$ is placed inside the water in beaker. The weight of the beaker and the metal would be:

  1. $170g$
  2. $160$g
  3. $100$g
  4. $30g$
Reveal answer Fill a bubble to check yourself
B Correct answer
Multiple choice physics upthrust in fluids, archimedes' principle and floatation applications of floatation principle of floatation and its applications when do objects float on water?

A ball rise with constant velocity, to the surface of a liquid whose density is four times that of the ball. The ratio of the v force to weight of the ball is

  1. 1

  2. 2

  3. 3

  4. 4

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For a body rising with constant velocity, the forces are balanced: Buoyancy = Weight + Viscous Force. F_b = rho_liquid * V * g = 4 * rho_ball * V * g = 4 * Weight. Therefore, Viscous Force = F_b - Weight = 4W - W = 3W. The ratio of viscous force to weight is 3.

Multiple choice physics upthrust in fluids, archimedes' principle and floatation applications of floatation principle of floatation and its applications when do objects float on water?

A balloon has volume of 1000 $m^{3}$ . It is filled with hydrogen ($ \rho $ = 0.09 g/L ) . If the density of air is 1.29 g/L , it can lift a total weight of 

  1. 600 kg

  2. 1200 kg

  3. 300 kg

  4. 1800 kg

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
Given,
$V _b=1000m^3$
$\rho _h=0.09g/L$
$\rho _a=1.29g/L$
$g=10m/s^2$
Upthrust force = total downward force
$V _b \rho _a h=mg+\rho _h V _b g$
$1000\times 1.29\times 10=mg+0.09\times 1000\times 10$
$1290=mg+90$
$mg=1200kg-weight$
The correct option is B.