Tag: sedimentation, decantation and filtration

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Questions Related to sedimentation, decantation and filtration

Multiple choice chemistry separation of matter sedimentation, decantation and filtration other methods of separation separation methods

By which process can we separate camphor from ammonium chloride?

  1. Filtration

  2. Sublimation

  3. Dissolution and evaporation

  4. Distillation
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The mixture of camphor and ammonium chloride cannot be separated by sublimation method since both are volatile substances. Thus the mixture is dissolved in water. Ammonium chloride is soluble in water while camphor is not thus the water containing ammonium chloride is decanted in another beaker. Thus camphor is obtained and now the solution is evaporated to separate ammonium chloride. The solution containing ammonium chloride is heated and boiled off the ammonium chloride is left behind

Multiple choice chemistry separation of matter sedimentation, decantation and filtration other methods of separation separation methods

By which method can ammonium chloride be separated from sand?

  1. By hand picking

  2. By filtration

  3. By sublimation

  4. By diffusion
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Sublimation is used to separate a mixture of sand and ammonium chloride. Sublimation is a separation process that entails heating a mixture of solids, where one of the solids transitions from solid to gas without passing through the liquid state. The vaporized solid is then reclaimed by cooling the vapor which reverts back to its initial solid state.

In the case of ammonium chloride and sand, ammonium chloride is the sublimate and changes to vapor

Multiple choice chemistry separation of matter sedimentation, decantation and filtration other methods of separation separation methods

The mixture of X and Y were taken in a condenser flask and were then heated. After keepint it for cooling, crystals of Y were found on the walls of the flask and X was present as such at the bottom of flask. Identify X and Y:

  1. $X= NaCl, Y= KCl$
  2. $X= Anthracene, Y=Naphthalene$
  3. $X=NaCl, Y= Naphthalene$
  4. $X=Anthracene, Y=NaCl$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Since crystals of $Y$ were formed on the walls of flask hence it must be some compound which sublimates on heating, and there was no effect on the $X$ so $X$ must be compound with high boiling point. The only combination with these properties are $X=NaCl$, $Y=Naphthalene$

Multiple choice chemistry separation of matter sedimentation, decantation and filtration other methods of separation separation methods

Evaporation of solution of $CuSO _4$ helps in:

  1. making it more concentrated
  2. crystallization of $CuSO _4$
  3. evaporation of salt $CuSO _4$
  4. both $A$ and $B$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

On evaporation of $CuSO _4$ solution, the amount of solvent will decrease and its concentration increases and it will leads to the crystallization of $CuSO _4$.

Multiple choice chemistry separation of matter sedimentation, decantation and filtration other methods of separation separation methods

Compounds evaporating easily and giving off a smell are:

  1. ionic compounds.

  2. covalent bonds.

  3. metallic bonds.

  4. diatic bonds.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Odour is the result of the compound vaporising, or at least being a gas, so that your olfactory system is capable of detecting it. If a compound is not so volatile that it vaporises at room temperature, it will not give off an odour.Compounds like methane, benzene etc. that possess covalent bonds are volatile at room temperature hence, gives off smell.

Multiple choice chemistry separation of matter sedimentation, decantation and filtration other methods of separation separation methods

When heating begins in miscible solutions, vapors formed will be:

  1. of liquid lower in boiling point

  2. of liquid higher in boiling point

  3. vapors will be of both liquids with a higher concentration of liquid having low boiling point

  4. collected in a gas syring
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

A distinct layer between two liquids will not form when you have a solution that is labelled miscible. A liquid is considered miscible if it can mix with another miscible liquid to form a homogeneous mixture. When heating begins in miscible solutions, vapours will be of both liquids (as miscible solution will give homogeneous mixture in vapour phase as well) with a higher concentration of liquid having low boiling point (since that component will be more volatile in nature).

Multiple choice chemistry separation of matter sedimentation, decantation and filtration other methods of separation separation methods

Put the following 6 steps for separating sand and salt into the correct order:

A.  Heat filtrate to evaporate off the solvent (water).

B.  Pour salt water filtrate into an evaporating basin on a tripod over a Bunsen burner.

C.  Filter to remove the insoluble sand.

D.  Place the sand/salt mixture into a beaker and add water.

E.  Allow basin to cool & collect salt.

F.  Stir to allow the salt to dissolve in the water.

  1. $CDFBAE$
  2. $CDBAFE$
  3. $DFCBAE$
  4. $ABCDEF$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The correct order of the process would be DFCBAE as shown below.

D.  Place the sand/salt mixture into a beaker and  add water

F.  Stir to allow the salt to dissolve in the water

C.  Filter to remove the insoluble sand

B.  Pour salt water filtrate into an evaporating basin on a tripod over a Bunsen burner

A.  Heat filtrate to evaporate off the solvent (water)

E.  Allow basin to cool & collect salt

Multiple choice chemistry separation of matter sedimentation, decantation and filtration other methods of separation separation methods

Which of the following is a seperation technique to seperate potassium chloride and ammonium chloride?

  1. Distillation

  2. Evaporation

  3. Condensation

  4. Sublimation
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A mixture of ammonium chloride and potassium chloride can be separated using the process of sublimation. You must also note that both these substances are sublimable. This technique is quite feasible in this case as the sublimable temperatures of ammonium and potassium chloride differ widely. Between the two, ammonium chloride has lower sublimable temperature. Therefore, it sublimes first followed by potassium chloride.