Tag: expanded form

Questions Related to expanded form

The digits in the tens place and units place of a two digit number are $t$ and $u$ respectively. If $1$ is placed between them, what is the value of the three digit number so formed?

  1. $100u+t+10$

  2. $100t+10+u$

  3. $10t+u+1$

  4. $100t+10u+1$


Correct Option: B
Explanation:

Let the number in one's place be $ u$ and the number in ten's place be $10t$.

According the the question 
$\Rightarrow 10t + 1+ u $
Hence now the 10t will become 100t as it will take hundred's digit place and 1 will become 10 as it will take ten's digit place.
Hence the value  of 3 digit number will be $ 100t + 10 + u $.

The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?

  1. 4

  2. 8

  3. 16

  4. None of these


Correct Option: B
Explanation:

$\because $ The number is greater than the number obtained in reversing the digits and the ten's digit is greater than the unit's digit
Let ten's and unit's digit be $2x$ and $x$ respectively
Then, $(10\times 2x+x)-(10x+2x)=36$
$9x=36$
$x=4$
Required difference$=(2x+x)-(2x-x)=2x=8$

$202\times315$ can be expanded as.............

  1. $200\times300+300\times15+2\times200+2\times15$

  2. $200\times300+200\times15+2\times300+2\times15$

  3. $200\times3+300\times2+200\times300+2\times15$

  4. $200\times2+300\times15+200\times300+2\times15$


Correct Option: B
Explanation:

$202\times 315=63,630$

It can be expanded as,
            $63,630=60,000+3000+600+30$
            $300\times 200+200\times 15+300\times 2+15\times 2$
Therefore, option (B) is correct.

What is the sum of $289$ and $410$ in number name form(i.e. in words)? 

  1. Six hundred and ninety two

  2. Six hundred and eighty five

  3. Six hundred and ninety nine

  4. Six hundred and fifty four


Correct Option: C
Explanation:
$\Rightarrow$  The given two numbers are $289$ and $410.$
$\therefore$  $289+410=699$
 Hundreds  Tens  Units
$ 6$  $9$ $ 9$

$\therefore$  In word $699$ can be written as "Six hundred and ninety nine."