Tag: quantum physics

Questions Related to quantum physics

Multiple choice physics quantum physics photons concept of photon photons and photoelectric effect

An electron of stationary hydrogen atom passes from the fifth energy level to the ground level. The velocity that the atom acquired as a result of photon emission will be

  1. $\dfrac{25m}{24hR}$

  2. $\dfrac{24m}{25hR}$

  3. $\dfrac{24hR}{25m}$

  4. $\dfrac{25hR}{24m}$

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

By conservation of momentum, the momentum of the atom equals the momentum of the emitted photon. The photon momentum is p = E/c. The energy difference for a hydrogen transition is E = 13.6 * R * (1/n_f^2 - 1/n_i^2). For n=5 to n=1, E = 13.6 * R * (1 - 1/25) = 13.6 * R * (24/25). Equating mv = E/c leads to the result.

Multiple choice physics quantum physics photons concept of photon photons and photoelectric effect

Violet light is falling on a photosensitive material causing ejection of photoelectrons with maximum kinetic energy of $1$ eV. Red light falling on metal will cause emission of photoelectrons with maximum kinetic energy (approximately) equal to

  1. $1.2$ eV

  2. $0.9$ eV

  3. $0.5$ eV

  4. Zero, that is no photoemision

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The photoelectric equation is K_max = E_photon - Work Function. Violet light has a shorter wavelength and higher energy than red light. If red light has a frequency lower than the threshold frequency of the metal, no photoelectrons will be emitted.

Multiple choice physics quantum physics photons concept of photon photons and photoelectric effect

When an electron de-exited back from ${\left( {n + 1} \right)^{th}}$ state to ${n^{th}}$ state in a hydrogen like atoms, wavelength of radiations emitted is ${\lambda _1}\left( {n >  > 1} \right)$. In the same atom de-broglies wavelength associated with an electron in $nth$ state is ${\lambda _2}$. Then $\frac{{{\lambda _1}}}{{{\lambda _2}}}$ is proportional to 

  1. $\frac{1}{n}$

  2. n

  3. ${n^2}$

  4. ${n^3}$

Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice physics quantum physics photons concept of photon photons and photoelectric effect

Approximately, the temperature corresponding to $1 eV$ translational kinetic energy of molecule is

  1. $7.6 \times 10 ^ { 2 } \mathrm { K }$

  2. $7.7 \times 10 ^ { 3 } \mathrm { K }$

  3. $7.1 \times 10 ^ { - 2 } \mathrm { K }$

  4. $7.2 \times 10 ^ { 3 } \mathrm { K }$

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The translational kinetic energy of a molecule is given by E = (3/2)kT. Setting E = 1 eV = 1.6 * 10^-19 J, we solve for T = (2 * 1.6 * 10^-19) / (3 * 1.38 * 10^-23). This yields approximately 7727 K.

Multiple choice physics quantum physics photons concept of photon photons and photoelectric effect

A metal plate of area $1\times { 10 }^{ -4 }{ m }^{ 2 }$ is  illuminated by a radiation of intensity 16 m $W/{ m }^{ 2 }.$ The work function of the metal is 5 eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be :
$\left[ { 1eV=1.6\times 10^{ 19 }J } \right] $

  1. ${ 10 }^{ 12 } and\ 5eV$

  2. ${ 10 }^{ 11 } and\ 2.5eV$

  3. ${ 10 }^{ 10 } and\ 5eV$

  4. ${ 10 }^{ 14 } and\ 5eV$

Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice physics quantum physics photons concept of photon photons and photoelectric effect

The energy of a hydrogen-like atom (or ion ) in its ground state is - 122.4 eV. It may be :

  1. hydrogen atom

  2. $He^{+}$

  3. $Li^{2+}$

  4. $Be^{3+}$

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The ground state energy of a hydrogen-like ion is E = -13.6 * Z^2 eV. Setting -13.6 * Z^2 = -122.4, we get Z^2 = 9, so Z = 3. The element with atomic number 3 is Lithium (Li^2+).

Multiple choice physics quantum physics photons concept of photon photons and photoelectric effect

When radiations of wavelength 3000 are incident on a photosensitive surface, the kinetic energy of electrons is 2.5 eV. The stopping potential for 1500 will he,

  1. $V _ { s } = 2.5 \mathrm { V }$

  2. $V _ { s } = 5.0 \mathrm { V }$

  3. $2.5 \leq \mathrm { V } _ { \mathrm { s } } \leq 5.0 \mathrm { V }$

  4. $V _ { s } > 5.0 \mathrm { V }$

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Energy of photon E = hc/lambda. E1 = hc/3000, E2 = hc/1500 = 2 * E1. K_max = E - Work Function. K1 = E1 - phi = 2.5 eV. K2 = 2 * E1 - phi = 2 * E1 - (E1 - 2.5) = E1 + 2.5. Since E1 > 0, K2 > 2.5 eV. The stopping potential V_s = K_max/e, so V_s > 2.5 V.

Multiple choice physics quantum physics photons concept of photon photons and photoelectric effect

A photon of energy 12.75 eV is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of the excited state is:

  1. $2$

  2. $3$

  3. $4$

  4. $5$

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The energy levels of hydrogen are E_n = -13.6/n^2. The energy required to reach state n from ground state (n=1) is 13.6 * (1 - 1/n^2). Setting 13.6 * (1 - 1/n^2) = 12.75, we get 1 - 1/n^2 = 12.75/13.6 = 0.9375. Thus 1/n^2 = 0.0625, n^2 = 16, n = 4.