Tag: drift velocity & mobility

Questions Related to drift velocity & mobility

A 2-ampere current flows in a conductor which has $1 \times {10^{24}}$ free electrons per meter. What is their average drift velocity?

  1. $1.25\,m/s$

  2. $125000\,m/s$

  3. $3 \times {10^8}\,m/s$

  4. $1.25 \times {10^{ - 5}}\,m/s$


Correct Option: A
Explanation:

We know 
$I = \eta eAV$
$2 = 1 \times {10^{24}} \times 1.6 \times {10^{ - 24}} \times 1 \times v$
$\boxed{v = 1.25\,m/s}$

An electric current of $16A$ exists in a metal wire of cross section ${ 10 }^{ -6 }{ m }^{ 2 }$ and length $1m$. Assuming one free electron per atom. The drift speed of the free electrons in the wire will be:
(Density of metal $=5\times { 10 }^{  }kg/{ m }^{ 3 }$, atomic weight $=60$)

  1. $5\times { 10 }^{ -3 }m/s$

  2. $2\times { 10 }^{ -3 }m/s$

  3. $4\times { 10 }^{ -3 }m/s$

  4. $7.5\times { 10 }^{ -3 }m/s$


Correct Option: B
Explanation:

We know,


$I=neAv _d$
      where n=electron density,
                  e=electronic charge
                  A= cross section area
                  $v _d$=drift velocity

But, $n=\dfrac{\rho}{Atm. \ Wt}\times N _A$

And $v _d=\dfrac{I}{neA}$

So, $v _d=\dfrac{16\times 60}{5\times 10^4\times N _A\times 1.6\times 10^{-19}\times 10^{-6}}$

Taking $N _A=6\times 10^{23}$

$v _d=\dfrac{120\times 10^{-2}}{6}=2\times 10^{-3}$

Drift velocity $v _a$ varies with the intensity of elastic filed as per the relation:

  1. $v _a$ is directly proportionate to E

  2. $v _a$ is inversely proportionate to E

  3. $v _a$ is constant

  4. $v _a$ is directly proportional to $E^2$


Correct Option: A
Explanation:
Drift velocity can be defined as the average velocity of electrons flowing inside a conductor under the influence of an electric field, which is responsible for the potential difference along the length of the conductor.

The relation between the electric field and potential is given by the following relation:

$ E=V/L$

Or,

$E = - \dfrac{dV}{dR} $


The electric potential changes along the distance in an electric field.

So, in a conductor with a potential difference between its ends, the electrons flow under the influence of this electric field. And the electric force is responsible for the acceleration of electrons and give then a drift velocity.

A copper wire of cross-section $2\ {mm}^{2}$ carries a current of $30\ A$. Calculate the root mean square velocity (thermal velocity) of free electrons at $27^oC$. Also ${v} _{d}$ is very small compared to it.
[Data given: ${ \rho  } _{ { C } _{ 0 } }=8.9\ gm/cc$, Boltzmann constant $(k)=1.38\times {10}^{23}J/K$
${m} _{0}=9.1\times {10}^{-31}kg.{N} _{A}=6.023\times {10}^{23}$ atomic weight of $Cu=63$] 

  1. True

  2. False


Correct Option: A

Two wires $X$ and $Y$ have the same resistivity but their cross-sectional areas are in the ratio $2 : 3$ and lengths in the ratio $1 : 2$. They are first connected in series and then the parallel to a d.c. source. Find the ratio of their drift speeds of the electrons in the two wires for the two cases.

  1. Series $6 : 2$, Parallel $2 : 1$.

  2. Series $3 : 2$, Parallel $2 : 1$.

  3. Series $5 : 2$, Parallel $2 : 1$.

  4. Series $3 : 2$, Parallel $3 : 1$.


Correct Option: B

The drift velocity of the electron in a copper wire of length 2m under the application of a potential difference of 200 V is $0.5 ms^{-1}$.Their mobility is (in $m^{-2} V^{-1} s^{-1}$)

  1. $5 \times 10^{-3}$

  2. $2.5 \times 10^{-2}$

  3. $5 \times 10^{2}$

  4. $ 10^{-3}$


Correct Option: A
Explanation:

Length ,$d=2m$

potential difference ,$V=200V$
Drift velocity, $v _d=0.5 m/s$
mobility ,$\mu=\dfrac{v _d}{E}$
$=\dfrac{v _d .d}{V}$
$=\dfrac{0.5}{200} \times 2$
$=\dfrac{0.5}{100}=5 \times 10^{-3} m^2 V^{-1} s^{-1}$

Current is flowing with a current density $J=480\ amp/cm^{2}$ in a copper wire. Assuming that each copper atom contribution one free electron and gives that  Avogadro number$=6.0\times 10^{23}\ atoms/mole$  Density of copper $=9.0\ g/cm^{3}$ .Atomic weight of copper $=64\ g/mole$ Electronic charge $=1.6\times 10^{-19}$ coulomb. The drift velocity of electrons is:

  1. $1\ mm/s$

  2. $2\ mm/s$

  3. $0.5\ mm/s$

  4. $0.36\ mm/s$


Correct Option: D
Explanation:

Given that,

 Current density $J=480\,amp/c{{m}^{2}}$

Avogadro number $N=6.0\times {{10}^{23}}\,atoms/mole$

Density of copper $\rho =9.0\,g/c{{m}^{3}}$
Atomic weight of copper $m=64\,g/mole$

Electronic charge $e=1.6\times {{10}^{-19}}\,coulomb$

We know that

Current density $J=\dfrac{I}{A}$

Now, the drift velocity is

${{v} _{d}}=\dfrac{J}{ne}....(I)$

We know that,

$n={{N} _{A}}\times \dfrac{1}{m}\times \rho $

Now, put the value of n in equation (I)

  $ {{v} _{d}}=\dfrac{Jm}{{{N} _{A}}e\rho } $

 $ {{v} _{d}}=\dfrac{480\times 64}{6.0\times {{10}^{23}}\times 1.6\times {{10}^{-19}}\times 9} $

 $ {{v} _{d}}=\dfrac{30720}{86.4\times {{10}^{4}}} $

 $ {{v} _{d}}=355.5\times {{10}^{-4}}\,cm/s $

 $ {{v} _{d}}=0.36\,mm/s $

Hence, the drift velocity is $0.36\,mm/s$ 

Assume that each atom of copper contributes one free electron. The density of copper is $9g cm^{-3}$ and atomic weight of copper is $63$. If the current flowing through a copper wire of $1mm$ diameter is $1.1 $ ampere, the drift velocity of electrons will be:- 

  1. $0.01 mm s^{-1}$

  2. $0.02 mm s^{-1}$

  3. $0.2 mm s^{-1}$

  4. $0.1 mm s^{-1}$


Correct Option: D

Find the time an electron takes to drift from one end of a uniform wire $3m$ long to its other end if the wire is $2$ x ${ 10 }^{ -6 }{ m }^{ 2 }$ in cross section and carries a current $3A$.The density of free electrons in a copper conductor is $8.5$ x ${ 10 }^{ 28 }{ m }^{ 3 }$.

  1. $2.7$ x ${ 10 }^{ 4 }s$

  2. $1.1$ x ${ 10 }^{ -4 }s$

  3. $0.9$ x ${ 10 }^{ -4 }s$

  4. $1.414$ x ${ 10 }^{ 4 }s$


Correct Option: A

How many electrons should be removed from a coil of mass 1.6 gram so that it may float in an electric field of intensity $10^9 NC^-1$ directed upwards ?

  1. $10^6$

  2. $10^7$

  3. $10^8$

  4. $10^9$


Correct Option: C