Tag: classification of mixtures

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Multiple choice chemistry separation of substances classification of mixtures mixtures: examples and properties types of solutions

A mixture is a material system made up of two or more different substances which are mixed :

  1. chemically

  2. physically

  3. both a and b

  4. none of above
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

A mixture is a material system made up of two or more different substances which are mixed but are not combined chemically. A mixture refers to the physical combination of two or more substances on which the identities are retained and are mixed in the form of solutions, suspensions, and colloids.

Multiple choice chemistry separation of substances classification of mixtures mixtures: examples and properties types of solutions

Water is a ____.
Methane is a ____.

  1. Compound, element

  2. Element, mixture

  3. Element, compound

  4. Compound, compound
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Water and methane are both made up of two different elements. Water is made up of oxygen and hydrogen whereas methane consists of carbon and hydrogen. Compounds are substances that contain atoms of at least two elements chemically combined. Hence, water and methane are compounds.

Multiple choice chemistry separation of substances classification of mixtures mixtures: examples and properties types of solutions

Identify the examples of separation of substances:

  1. separation of milk or curd to remove butter

  2. separation of stalks from grains

  3. separation of dirt particle from water

  4. all of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

All are the examples of separation of substances. 

Separation of milk and curd is done to obtain butter from it which is a useful component of milk.
Stalks are separated from grains to obtain pure grains.
Separation of dirt particles from water is done in order to pure water.

Multiple choice chemistry separation of substances classification of mixtures mixtures: examples and properties types of solutions

Mixtures on separation can give ____________.

  1. elements

  2. compounds

  3. both elements and compounds

  4. impure substances
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Mixtures can be obtained by a combination of elements and compounds. Thus when they are separated, it can give both elements and compounds, depending upon the constituents of a mixture.
Example: Air is the mixture of various gases. It on separation gives oxygen, nitrogen, carbon dioxide, etc. 

Multiple choice chemistry separation of substances classification of mixtures mixtures: examples and properties types of solutions

The amountof $H _2S$ required to precipitate $1.69$g $BaS$ from $BaCl _2$ solution is : 

  1. $3.4g$
  2. $0.24g$
  3. $0.34g$
  4. $0.17g$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$BaCl _2+H _2S\longrightarrow BaS+2HCl$
                                  $1.69$ $g$
For $1$ $mole$ of $H _2S$ produce $1$ $mole$ of $BaS$
So, $1$ $mole$ $H _2S\longrightarrow 1$ $mole$ $BaS$
            $34$ $g$                      $169$ $g$
                      $(x)\longleftarrow 1.69$ $g$
$\implies x=\cfrac {1.69\times 34}{169}=0.34$ $g$
Amount of $H _2S$ needed $=0.34$ $g$

Multiple choice chemistry separation of substances classification of mixtures mixtures: examples and properties types of solutions

$3$ litre of mixture of propane $(C {3}H _{8})$ $ butane $(C{4}H_{10})$ on complete combustion gives $10$ litre $CO_{2}$. Find the composition of mixture.

  1. $C _{3}H _{8}2L$ and $C _{4}H _{10}\ 1L$
  2. $C _{3}H _{8}3L$ and $C _{4}H _{10}\ 0L$
  3. $C _{3}H _{8}\ 1.5L$ and $C _{4}H _{10}\ 1.5L$
  4. $C _{3}H _{8}\ 0L$ and $C _{4}H _{10}\ 3L$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let x be the volume of propane and y be the volume of butane. We have x + y = 3. The combustion reactions are C3H8 + 5O2 -> 3CO2 + 4H2O and C4H10 + 6.5O2 -> 4CO2 + 5H2O. Thus, 3x + 4y = 10. Solving these equations gives x = 2 and y = 1.

Multiple choice chemistry separation of substances classification of mixtures mixtures: examples and properties types of solutions

An aqueous solution containing $1g$ of urea boils at $100.25^ {o}C$. The aqueous solution containing $3g$ of glucose in the same volume will boil at-

  1. $100.75^ {o}C$
  2. $100.5^ {o}C$
  3. $100^ {o}C$
  4. $100.25^ {o}C$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The boiling point elevation depends on the molality of the solution. Urea (molar mass 60) and glucose (molar mass 180) have different molar masses. 1g urea is 1/60 moles, while 3g glucose is 3/180 = 1/60 moles. Since the number of moles is the same in the same volume, the molality is identical, resulting in the same boiling point elevation.