Which ion is colourless?
- $C{ r }^{ +4 }$
- $Sc^{ +3 }$
- $Ti^{ +3 }$
- ${ V }^{ +3 }$
Reveal answer
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B
Correct answer
Explanation
$(A)$ $Cr\quad [Ar]3d^54s^1$
$Cr^{+4}\quad [Ar]3d^2$
$2$ unpaired $e^-s\longrightarrow$ paramagnetic.
$(B)$ $Sc\quad [Ar]3d^14s^2$
$Sc^{+3}\quad [Ar]3d^2$
$0$ unpaired $e^-s\longrightarrow$ dimagnetic.
$(C)$ $Ti\quad [Ar]3d^24s^2$
$Ti^{+3}\quad [Ar]3d^1$
$1$ unpaired $e^-s\longrightarrow$ paramagnetic.
$(D)$ $V\quad [Ar]3d^34s^2$
$V^{+3}\quad [Ar]3d^2$
$2$ unpaired $e^-s\longrightarrow$ paramagnetic.
Ions which do not have unpaired electrons do not show colour in aqueous solution. These are known as diamagnetic ions.