Tag: other methods of separation

Questions Related to other methods of separation

Sublimation process is used:

  1. to separate mixtures that contain a sublimate with a non-volatile component from a non-sublimate impurity

  2. to separate mixtures that contain a sublimate with a volatile component from a non-sublimate volatile impurity

  3. to separate mixtures that contain a sublimate with a volatile component from a non-sublimate impurity

  4. none of above


Correct Option: C
Explanation:

Sublimation process is used to separate mixtures that contain a sublimate with a volatile component from a non-sublimate impurity. Thus, ammonium chloride can be separated from sodium chloride by sublimation. Ammonium chloride sublimes whereas sodium chloride does not.

Method of separation by sublimation is limited. 
  1. True

  2. False


Correct Option: A
Explanation:

The given statement is True.
 Method of separation by sublimation is limited. This method can be used for separation of only those compounds that sublime (i.e, change their state on heating from solid to vapour without passing through liquid state). Examples of sublimable compounds include iodine, ammonium chloride, camphor and naphthalene.

Note: If in the given mixture, none of the compounds is sublimable, then method of separation by sublimation cannot be used.

Ammonium chloride is separated from a mixture of sodium chloride and ammonium chloride by the process of:

  1. evaporation

  2. sublimation

  3. fractional distillation

  4. filtration


Correct Option: B
Explanation:

Ammonium chloride is separated from a mixture of sodium chloride and ammonium chloride by the process of sublimation. Ammonium chloride can be sublimed whereas sodium chloride cannot be sublimed. When a mixture of sodium chloride and ammonium chloride is heated, ammonium chloride changes its state from solid to vapour. The vapours of ammonium chloride are then condensed on cold surface. Sodium chloride is left behind.

Non-reacting gases have the tendency to mix with each other. What is this phenomenon called?

  1. Evaporation

  2. Diffusion

  3. Effusion

  4. Explosion


Correct Option: B
Explanation:

Non reacting gases not reacted with each other so they only mix by diffusion.

Diffusion of gases. a natural process, in which molecules of a gas pass from an area of high concentration to one of lower concentration.

By which process can we separate camphor from ammonium chloride?

  1. Filtration

  2. Sublimation

  3. Dissolution and evaporation

  4. Distillation


Correct Option: C
Explanation:

The mixture of camphor and ammonium chloride cannot be separated by sublimation method since both are volatile substances. Thus the mixture is dissolved in water. Ammonium chloride is soluble in water while camphor is not thus the water containing ammonium chloride is decanted in another beaker. Thus camphor is obtained and now the solution is evaporated to separate ammonium chloride. The solution containing ammonium chloride is heated and boiled off the ammonium chloride is left behind

By which method can ammonium chloride be separated from sand?

  1. By hand picking

  2. By filtration

  3. By sublimation

  4. By diffusion


Correct Option: C
Explanation:

Sublimation is used to separate a mixture of sand and ammonium chloride. Sublimation is a separation process that entails heating a mixture of solids, where one of the solids transitions from solid to gas without passing through the liquid state. The vaporized solid is then reclaimed by cooling the vapor which reverts back to its initial solid state.

In the case of ammonium chloride and sand, ammonium chloride is the sublimate and changes to vapor

The mixture of X and Y were taken in a condenser flask and were then heated. After keepint it for cooling, crystals of Y were found on the walls of the flask and X was present as such at the bottom of flask. Identify X and Y:

  1. $X= NaCl, Y= KCl$

  2. $X= Anthracene, Y=Naphthalene$

  3. $X=NaCl, Y= Naphthalene$

  4. $X=Anthracene, Y=NaCl$


Correct Option: C
Explanation:

Since crystals of $Y$ were formed on the walls of flask hence it must be some compound which sublimates on heating, and there was no effect on the $X$ so $X$ must be compound with high boiling point. The only combination with these properties are $X=NaCl$, $Y=Naphthalene$

Evaporation of solution of $CuSO _4$ helps in:

  1. making it more concentrated

  2. crystallization of $CuSO _4$

  3. evaporation of salt $CuSO _4$

  4. both $A$ and $B$


Correct Option: D
Explanation:

On evaporation of $CuSO _4$ solution, the amount of solvent will decrease and its concentration increases and it will leads to the crystallization of $CuSO _4$.

Compounds evaporating easily and giving off a smell are:

  1. ionic compounds.

  2. covalent bonds.

  3. metallic bonds.

  4. diatic bonds.


Correct Option: B
Explanation:

Odour is the result of the compound vaporising, or at least being a gas, so that your olfactory system is capable of detecting it. If a compound is not so volatile that it vaporises at room temperature, it will not give off an odour.Compounds like methane, benzene etc. that possess covalent bonds are volatile at room temperature hence, gives off smell.

When heating begins in miscible solutions, vapors formed will be:

  1. of liquid lower in boiling point

  2. of liquid higher in boiling point

  3. vapors will be of both liquids with a higher concentration of liquid having low boiling point

  4. collected in a gas syring


Correct Option: C
Explanation:

A distinct layer between two liquids will not form when you have a solution that is labelled miscible. A liquid is considered miscible if it can mix with another miscible liquid to form a homogeneous mixture. When heating begins in miscible solutions, vapours will be of both liquids (as miscible solution will give homogeneous mixture in vapour phase as well) with a higher concentration of liquid having low boiling point (since that component will be more volatile in nature).