Tag: polarisation

Questions Related to polarisation

Two Polaroids $P _1$ and $P _2$ are placed with their axis perpendicular to each other. Unpolarized light $l _0$ is incident on $P _1$. A third polaroid $P _3$ is kept in between $P _1$ and $P _2$ such that its axis makes an angle $45^{\circ}$ with that of $P _1$. The intensity of transmitted light through $P _2$ is 

  1. $\frac {I _0 }{2 }$

  2. $\frac {I _0 }{4 }$

  3. $\frac {I _0 }{8 }$

  4. $\frac {I _0 }{16 }$


Correct Option: C
Explanation:
$I=I _0 .\cos^2 \theta$
$\theta =$ angle made by $E$ vector with transmission axis.wherein
$I=$ Intensity of transmitted light after polarisation.
$I _0=$Intensity of incident light.

Intensity of light after crossing $P _1=\dfrac {I _0}{2}$
Intensity of light after crossing $P _3=\dfrac {I _0}{2}.\cos^2 45^o =\dfrac {I _0}{4}$
Intensity of light after crossing $P _2=\dfrac {I _0}{4}.\cos^2 45^o$
$I=\dfrac {I _0}{8}$

Three polaroides are placed one above other, such that the first and the last polaroids are crossed with each other. If the angle between the transmission axis of the first two polaroids is $45$, then what is the percentage of incident light transmitted through the combination of three polaroids?

  1. 0%

  2. 12.50%

  3. 50%

  4. 100%


Correct Option: B

For a given medium, the polarising angle is $60^o$. What will be the critical angle for this medium?

  1. $i = 35^o16'$

  2. $i = 45^o16'$

  3. $i = 55^o16'$

  4. $i = 65^o16'$


Correct Option: A

A light has amplitude A and angle between analyzer and polarizer is.$60 ^ { \circ }$ Light is transmitted by analyzer has amplitude. 

  1. $\mathrm { A } \sqrt { 2 }$

  2. $\frac { A } {2 \sqrt { 2 } }$

  3. $\frac { \sqrt { 3 } \mathrm { A } } { 2 }$

  4. $\frac { A } { 2 }$


Correct Option: B

The polaroids are placed in the path of unpolarized beam of intensity $I _{0}$ such that no light is emitted from the second polaroid. If a third polaroid whose polarization axis makes an angle $\theta$ with the polarization axis of first polaroid, is placed between these polariods then the intensity of light emerging from the last polaroid will be

  1. $\left (\dfrac {I _{0}}{8}\right )\sin^{2} 2\theta$

  2. $\left (\dfrac {I _{0}}{4}\right )\sin^{2} 2\theta$

  3. $\left (\dfrac {I _{0}}{2}\right )\sin^{2} 2\theta$

  4. $I _{0}\cos^{4}\theta$


Correct Option: A

A Polaroid examines two adjacent plane polarised beams $A$ and $B$ whose planes of polarisation are mutually perpendicular. In the first position of the analyser, beam $B$ shows zero intensity. From this position a rotation of $30^{o}$ shows that the two beams have same intensity. The ratio of intensities of the two beams $I _{A}$ and $I _{B}$ will be

  1. $1:3$

  2. $3:1$

  3. $\sqrt{3}:1$

  4. $1:\sqrt{3}$


Correct Option: A

In, the visible region of the spectrum the rotation of the plane of polarization is given by $\displaystyle\theta=a+\frac{b}{\lambda^2}$. The optical rotation produced by a particular material is found to be $30^0$ per $mm$ at $\lambda=5000A^o$ and $50^0$ per $mm$ at $\lambda=4000A^o$. The value of constant $a$ will be

  1. $\displaystyle +\frac{50^0}{9}$ per $mm$

  2. $\displaystyle -\frac{50^0}{9}$ per $mm$

  3. $\displaystyle +\frac{9^0}{50}$ per $mm$

  4. $\displaystyle -\frac{9^0}{50}$ per $mm$


Correct Option: B

An unpolarized beam of intensity $2a^2$ passes through a thin Polaroid. Assuming zero absorption in the Polaroid, the intensity of emergent planes polarized light will be  

  1. $2a^2$

  2. $a^2$

  3. $\displaystyle\sqrt2a$

  4. $\displaystyle\frac{a^2}{\sqrt2}$


Correct Option: B
Explanation:

 initial unpolarized intensity is $2a^{2}$ 
the intensity of light transmitted by the first polarizered will be  $\dfrac{I _{unpolarized}}{2}=a^{2}$
option $B$ is correct 

A beam of unpolarized light is passed first through a tourmaline crystal $A$ and then through another tourmaline crystal $B$ oriented so that its principal plane is parallel to that of $A$. The intensity of final emergent light is $I$. If $A$ is rotated by $45^0$ on a plane, perpendicular to the direction of incident ray, then intensity of emergent light will be

  1. $\displaystyle\frac{I}{8}$

  2. $\displaystyle\frac{I}{4}$

  3. $\displaystyle\frac{I}{2}$

  4. none of these


Correct Option: C
Explanation:

$I _{I}=Icos^{2} \theta =Icos^{2}45=\dfrac{I}{2}$
option $C$ is correct 

Unpolarized light of intensity $32Wm^{-2}$ passes through three polarizes such that the transmission axis of the last polarizers is crossed with that of the first. The intensity of final emerging light is $3Wm^{-2}$.The intensity of light transmitted by the first polarizered will be 

  1. $32Wm^{-2}$

  2. $16Wm^{-2}$

  3. $8Wm^{-2}$

  4. $4Wm^{-2}$


Correct Option: B
Explanation:

 initial unpolarized intensity is $32Wm^{-2}$
the intensity of light transmitted by the first polarizered will be  $\dfrac{I _{unpolarized}}{2}=16Wm^{-2}$