Tag: perfect square or square number

$3x\sqrt{2y}=\sqrt{2y\times3^2x^2}=\sqrt{18x^2y}$ 

$59^{2} = 59 \times 59 = 3481$

It can also be $(-13)^2$

$-13 \times -13 = 169$

Therefore, A is the correct answer.

Square of $6.3 = 6.3\times 6.3=\dfrac {63}{10}\times \dfrac {63}{10}=\dfrac {3936}{100}$
                        $= 39.69$

We have 2352 =  $ \displaystyle \underline{2\times 2}\times \underline{2\times 2}\times 3\times \underline{7\times 7} $
As the prime factor 3 has no pair 2352 is not a perfect square 

$\dfrac{1}{m}$ $=$ $\dfrac{-1}{3}$

$112^2 = (100 + 12)^2$
$a = 100, b = 12$
$= a(a + b) + b(a + b)$
$= 100(100 + 12) + 12(100 + 12)$
$= 100^2 + 1200 + 1200 + 12^2$
$= 10000 + 2400 + 144$
$= 12544$
The missing number is 144.

Step 1: 

Step 1 :Multiply ten's digit with its next number.
$2 \times (2 + 1) = 2\times 3 = 6 ---(1)$
Step 2 : Find the square of unit's digit: 5
$5^2 = 25 ----(2)$
Combining (1) and (2), we get
$25 \times 25 = 625$
$6 $ is the missing number.