Tag: natural vegetative propagation

Questions Related to natural vegetative propagation

Other than potato, turmeric is reproduces by 

  1. Leaves

  2. Roots

  3. Stem

  4. All of the above


Correct Option: C

A loose bulb is a

  1. False bulb

  2. Simple tunicated bulb

  3. Compound tunicated bulb

  4. Scaly bulb


Correct Option: A

Leaf cuttings are used for quick vegetative propagation of

  1. Sansevieria

  2. Jasminum

  3. Tea

  4. Blackberry


Correct Option: A
Explanation:

Vegetative propagation is the growth and development of the plant by asexual means. It occurs from specialized vegetative plant parts. It is made possible by meristem tissue that is commonly found within stems and leaves, as well as at the tips of roots and stems. Meristem tissue contains undifferentiated cells that actively divide by mitosis allowing plant growth.

Sansevieria plant has long leaves with meristem tissue at the tip as well as at margins. Cutting of leaf can give rise to adventitious roots for plant growth.
Jasmine, blackberry and Tea are propagated by layering and stem cuttings. Thus, the correct answer is option A.

In whichplant, root will form a new plant?

  1. Populus

  2. Dahlia

  3. Azadirachta

  4. Both A and B


Correct Option: D
Explanation:

Populus and Dahlia's plants have the apical meristematic tissue at the tip of their roots.Populus has long roots while Dehlia has tuberous roots.The meristematic tissue cells have the capacity to divide actively and form a new plant in favourable conditions.

Azadirachta genus, which includes trees like Neem,  can be grown easily by planting seeds. Root cuttings can also produce plants.
The option c is the correct answer.

In Albizzia, vegetative propagation take place with the help of

  1. Fasciculated tuberous roots

  2. Epiphyllous buds

  3. Subaerial branches

  4. Nonfleshy roots


Correct Option: D
Explanation:

Albizia belongs to family fabaceae. In Albizzia, vegetative propagation take place with the help of nonfleshy roots. The non fleshy roots develop adventitious buds which grow to form new plants. 

Fasciculated tuberous roots are swollen to store food. It occurs as a clusters at the base of the stem. It is found in dhalia.
Epiphyllous buds developed on leaves of shoots. It is used for vegetative propagation in sunflower.
Subaerial branches are used for vegetative propagation in runners, stolon etc.
So, the correct answer is option D.

Which of the following groups of plants are propagated through underground root ?

  1. Bryophyllum, and kalanchoe

  2. Ginger, potato, onion and zamikand

  3. Pistia, chrysanthemum and pineapple

  4. Sweet potato, asparagus, tapioca and dahlia


Correct Option: D
Explanation:

Plant propagation from the vegetative part of a parent plant through asexual mode is called vegetative propagation. This is possible because of the presence of meristematic tissue capable of cellular differentiation, in many plant tissues. A part of stem, root or leaf can grow adventitious roots and form a new plant.

Some plants have swollen fleshy roots called root tubers. These tubers bear buds which can develop into the new plant if covered with moist soil e.g., sweet potato, dahlia, yam, tapioca, asparagus etc.
Thus, the correct answer is option D.

Which one is propagated by cuttings? 

  1. Bougainvillea

  2. Tea

  3. Sansevieria

  4. All the above


Correct Option: D
Explanation:
Hardwood cuttings of Bougainvillea, Ixora etc. can be rooted with good amount of success if root-promoting hormones are used. Sansevieria can be propagated through leaf cutting or planting a leaf section and Tea is propagated through cutting from the end of a branch on the tree below a leaf node that has an axillary bud forming. 
So the correct option is 'Bougainvillea, Tea and Sansevieria'.

Potato is a native of.

  1. Peru

  2. Mexico

  3. India

  4. China


Correct Option: A

Statement $1$ : Many plants are propagated vegetatively even though they bear seeds.
Statement $2$: Sweet potatoes multiply vegetatively by root tubers.

  1. Both statements $1$ and $2$ are correct

  2. Statement $1$ is correct but statement $2$ is incorrect

  3. Statement $1$ is incorrect but statement $2$ is correct

  4. Both statements $1$ and $2$ are incorrect


Correct Option: A
Explanation:

Vegetative propagation is the formation of new plants from vegetative units such as buds, tubers, rhizomes, etc. This method produces a large number of population of clones in a short time. It preserves purity, resistance and food qualities of race/variety indefinitely. Fleshy roots (root tubers) which develop adventitious buds also take part in vegetative propagation, e.g., sweet potato.

So, the correct answer is 'Both statements 1 and 2 are correct'.

Read the following statements and select the correct ones.


(i) Conidia are the asexual propagules restricted to Kingdom Fungi.
(ii) A piece of potato tuber having at least one eye (or node) is capable of giving rise to a new plants.
(iii) Ginger propagates vegetatively with the help of its underground roots.
(iv) Fleshy buds which take part in vegetative propagation are called bulbils, present in Dioscorea, Agave, etc.

  1. (ii) and (iii)

  2. (i) and (iv)

  3. (i), (ii), and (iv)

  4. (i), (ii), and (iii)


Correct Option: C
Explanation:

Ginger propagates vegetatively with the help of rhizome. Rhizomes are main underground stems which store food for perennation during unfavourable conditions. These have buds for formation of new aerial during favourable conditions.

So, the correct answer is '(i), (ii) and (iv)'.