Tag: measurement of volume

Questions Related to measurement of volume

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Each side of a cube is measured to be $7.203\ m$.The volume of the cube to appropriate significant figure is:

  1. $31.3\ m^3$
  2. $313\ m^3$
  3. $373.7\ m^3$
  4. $37.3\ m^3$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Side of cube  $a = 7.203 \ m$
Volume of cube  $V = a^3$
$\implies \ V = (7.203)^3 = 373.714 \ m^3$
Since the value of side of cube has 4 significant figures, thus the value of volume of cube must also have 4 significant figure.
Thus volume of cube  $V = 373.7 \ m^3$

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Density and mass of the solid block is $5.2\  kg/m^3$ and $2\ kg$.Find its volume?

  1. $0.3846\ m^3$
  2. $7846\ cm^3$
  3. $68.46\ cm^3$
  4. $98.46\ cm^3$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Mass of solid block  $m = 2 \ kg$
Density of solid block   $d = 5.2 \ kg/m^3$
Volume of solid block  $V = \dfrac{m}{d}$
$\implies \ V = \dfrac{2}{5.2} = 0.3846 \ m^3$

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

Which of the following instruments can be used to measure the volume of a liquid?

  1. Measuring cylinder

  2. Vernier callipers

  3. Pipette

  4. Measuring flask

Reveal answer Fill a bubble to check yourself
A,C,D Correct answer
Explanation

Measuring cylinder, pipette and measuring flask are used to measure the volume of the given liquid whereas vernier calliper is used measure the length of the object.

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

A rectangular vessel $ 1 m \times 0.6 m \times 0.5 m $ filled with maize grains. Treat the grains spheres of diameter 0.3 cm each.The number of grains in the vessel is the nearest to 

  1. $ 5 \times 10^7 $
  2. $ 1 \times 10^7 $
  3. $ 2 \times 10^7 $
  4. $ 2 \times 10^5 $
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let n number of grains are in the vessel.

So, volume of cuboid vessel is equal to n times volume of spheres. i.e.

$ 1\times 0.6\times 0.5=n\left( \dfrac{4}{3}\times 3.14\times {{\left( \dfrac{3}{2000} \right)}^{3}} \right) $

$ 0.3=n\dfrac{4}{3}\times 3.14\times 3.375\times {{10}^{-9}} $

$ 0.3=n\times 14.13\times {{10}^{-9}} $

$ n=\dfrac{0.3}{14.13\times {{10}^{-9}}} $

$ n=0.021\times {{10}^{9}}\, $

$ n=2\times {{10}^{7}}$

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density
A single sheet of aluminium foil is folded twice to produce a stack of four sheets. The total thickness of the stack of sheets is measured to be $(0.80\pm 0.02)mm$. This measurement is made using a digital caliper with a zero error or $(-0.20\pm 0.02)mm$
What is the percentage uncertaintyin calculated thickness of a single sheet?
  1. $1.0$%
  2. $2.0$%
  3. $4.0$%
  4. $6.7$%
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The zero error (−0.20) can be removed but its uncertainty (± 0.02) must be added to the measurement uncertainty.

True value of total thickness =$ 0.80 + 0.20 = 1.0 mm  $

Total uncertainty in measurement = $(0.02+0.02)=0.04\ mm$

So the four sheets have a true thickness of $ (1.00 ± 0.04) mm.$
 A single sheet would have a thickness of $(0.25 ± 0.01) mm.$

Percentage error= $\dfrac{0.01}{0.25}\times 100 = 4.0$%

Multiple choice physics learning how to measure measurement of area and volume measurement of volume measurement of area, volume and density

The volume of water in a measuring cylinder is 55 mL When a stone tied to a string is immersed in the water the water level rises to 83 mL. Find the volume of the stone

  1. $28ml^2$
  2. $28ml$
  3. $38ml$
  4. $28m^2l$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
Initial level of water  $v _i = 55 \ ml$
Final level of water  $v _f = 83  ml$
Volume of stone  $V _{stone} = V _f - V _i = 83 - 55 = 28 \ ml$