Tag: money and metric measures as percentage

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Multiple choice maths percentages finding one number as percentage of another money and metric measures as percentage expressing one quantity as a percentage of another

A spider climbed $62\cfrac{1}{2}$% of the height of the pole in one hour and in the next hour it covered $12\cfrac{1}{2}$% of the remaining height. If pole's height is $192m$, then the distance climbed in second hour is:

  1. $3m$
  2. $5m$
  3. $7m$
  4. $9m$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

First hour: 62.5% of 192m = 120m. Remaining height: 192 - 120 = 72m. Second hour: 12.5% of 72m = (1/8) * 72 = 9m.

Multiple choice maths percentages finding one number as percentage of another money and metric measures as percentage expressing one quantity as a percentage of another

In an examination in which full marks were $500$. $A$ got $25$% more than $C$, $C$ got $20$% less than $D$. If $A$ got $360$ marks. What percentage of full marks was obtained by $D$?

  1. $72$%
  2. $80$%
  3. $50$%
  4. $60$%
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
given,full marks in the examination are $500$
A got $360$ marks  
A got $25\%$ more than $C$.
let the marks of $C$ be $'x'$ then, 
$x+\dfrac{25}{100}\times x=360$ 
$\dfrac{5x}{4}=360$
$x=288$
 so,$C$ got $288$ marks . 
given,$C$ got $20\%$ less than $D$ let the marks of $D$ be $'y'$ then,
 $y-\dfrac{20}{100}\times y=288$
 $\dfrac{4y}{5}=288$
$y=360$
 so,$D$ got $360$ marks percentage of full marks obtained by $D$ $=\dfrac{360}{500}\times 100$
$=72\%$
Multiple choice maths percentages finding one number as percentage of another money and metric measures as percentage expressing one quantity as a percentage of another

Tulsiram's salary is $20$% more than that of Kashyap. If tulsiram saves RS. $720$ which is $4$% of his salary, then Kashyap's salary is

  1. Rs. $15,000$
  2. Rs. $12,000$
  3. Rs. $10,000$
  4. RS. $22,000$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$Salary\quad of\quad Tulsiram$

$ =Rs\quad \dfrac { 720 }{ 4 } \times 100$

$=Rs\quad 18,000$

$Salary\quad of Kashyap\quad $

$=18000\times \dfrac { 100 }{ 120 } $

$ =Rs.15000$

Multiple choice maths percentages finding one number as percentage of another money and metric measures as percentage expressing one quantity as a percentage of another

In two successive years, $80$ and $60$ students of a school appeared at the final examination, of which $60$% and $80$% passed respectively. The average rate of students passed (in percent) is:

  1. $68$%
  2. $68\cfrac{4}{7}$%
  3. $32$%
  4. $36$%
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total students = 80 + 60 = 140. Passed in year 1: 60% of 80 = 48. Passed in year 2: 80% of 60 = 48. Total passed = 48 + 48 = 96. Average rate = (96 / 140) * 100 = 960/14 = 480/7 = 68 4/7%.

Multiple choice maths percentages finding one number as percentage of another money and metric measures as percentage expressing one quantity as a percentage of another

If $50$% of (x-y)=$30$% of $(x+y)$, then what percent of $x$ is $y$?

  1. $20$%
  2. $25$%
  3. $30$%
  4. $40$%
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$50\%$ of $(x-y)=30\% (x+y)$

$\dfrac{50}{100}(x-y)=\dfrac{30}{100}(x+y)$
$5(x-y)=3(x+y)$
$5x-3x=3y+5y$
$2x=8y$
$\Rightarrow x=4y \Rightarrow y=x/4$
To find : $\left[\dfrac{y}{x}\times 100\right]$
$\dfrac{y}{x}\times 100=\dfrac{x}{4}\times \dfrac{1}{x}\times 100 =\dfrac{100}{4}=25\%$
$\therefore y$ is $25\%$ of $x$

Multiple choice maths percentages finding one number as percentage of another money and metric measures as percentage expressing one quantity as a percentage of another

$12.5\% \,of\,192 = 50\% \,of\,?$ 

  1. $48$
  2. $96$
  3. $24$

  4. none of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
$12.5\% \,\, of \,192 = 50\%$ of ?

First, we will find $12.5\%\,\, of\,\, 192$

$\Rightarrow \dfrac{x}{192}\times 100= 12.5$

$\Rightarrow x=\dfrac{12.5\times 192}{100}= 24$

Now we will find of what $50\%$ will give $24$

i.e., $\dfrac{24}{y}\times 100= 50$

$y = 48$
Multiple choice maths percentages finding one number as percentage of another money and metric measures as percentage expressing one quantity as a percentage of another

Out of 800 oranges, 50 are rotten. Find the percentage of good oranges.

  1. $\displaystyle\,7\,\frac{1}{4}\%$
  2. $\displaystyle\,93\,\frac{1}{4}\%$
  3. $\displaystyle\,93\,\frac{3}{4}\%$
  4. $\displaystyle\,7\,\frac{3}{4}\%$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Good oranges are $ 800 - 50 = 750 $
So, percentage of good oranges $ = \cfrac { 750}{800} \times 100 $ %  $ = \cfrac {375}{4} $ % $ = 93 \cfrac {3}{4} $ %