Tag: finding one number as percentage of another

Questions Related to finding one number as percentage of another

$88 \% \text { of } 370 + 24 \% \text { of } 210 - x? = 118$

  1. 256

  2. 258

  3. 268

  4. 358


Correct Option: B
Explanation:

$88\% \ of \ 370+24\% \ of \ 210-x=118$

$\dfrac{88}{100}\times 370 +\dfrac{24}{100} \times 210-x=118$

$\dfrac{3256}{10}+\dfrac{504}{10}-x=118$

$325.6+50.4-118=x$
$x=258$

A spider climbed $62\cfrac{1}{2}$% of the height of the pole in one hour and in the next hour it covered $12\cfrac{1}{2}$% of the remaining height. If pole's height is $192m$, then the distance climbed in second hour is:

  1. $3m$

  2. $5m$

  3. $7m$

  4. $9m$


Correct Option: D

In an examination in which full marks were $500$. $A$ got $25$% more than $C$, $C$ got $20$% less than $D$. If $A$ got $360$ marks. What percentage of full marks was obtained by $D$?

  1. $72$%

  2. $80$%

  3. $50$%

  4. $60$%


Correct Option: A
Explanation:
given,full marks in the examination are $500$
A got $360$ marks  
A got $25\%$ more than $C$.
let the marks of $C$ be $'x'$ then, 
$x+\dfrac{25}{100}\times x=360$ 
$\dfrac{5x}{4}=360$
$x=288$
 so,$C$ got $288$ marks . 
given,$C$ got $20\%$ less than $D$ let the marks of $D$ be $'y'$ then,
 $y-\dfrac{20}{100}\times y=288$
 $\dfrac{4y}{5}=288$
$y=360$
 so,$D$ got $360$ marks percentage of full marks obtained by $D$ $=\dfrac{360}{500}\times 100$
$=72\%$

Tulsiram's salary is $20$% more than that of Kashyap. If tulsiram saves RS. $720$ which is $4$% of his salary, then Kashyap's salary is

  1. Rs. $15,000$

  2. Rs. $12,000$

  3. Rs. $10,000$

  4. RS. $22,000$


Correct Option: A
Explanation:

$Salary\quad of\quad Tulsiram$

$ =Rs\quad \dfrac { 720 }{ 4 } \times 100$

$=Rs\quad 18,000$

$Salary\quad of Kashyap\quad $

$=18000\times \dfrac { 100 }{ 120 } $

$ =Rs.15000$

In two successive years, $80$ and $60$ students of a school appeared at the final examination, of which $60$% and $80$% passed respectively. The average rate of students passed (in percent) is:

  1. $68$%

  2. $68\cfrac{4}{7}$%

  3. $32$%

  4. $36$%


Correct Option: B

If $50$% of (x-y)=$30$% of $(x+y)$, then what percent of $x$ is $y$?

  1. $20$%

  2. $25$%

  3. $30$%

  4. $40$%


Correct Option: B
Explanation:

$50\%$ of $(x-y)=30\% (x+y)$

$\dfrac{50}{100}(x-y)=\dfrac{30}{100}(x+y)$
$5(x-y)=3(x+y)$
$5x-3x=3y+5y$
$2x=8y$
$\Rightarrow x=4y \Rightarrow y=x/4$
To find : $\left[\dfrac{y}{x}\times 100\right]$
$\dfrac{y}{x}\times 100=\dfrac{x}{4}\times \dfrac{1}{x}\times 100 =\dfrac{100}{4}=25\%$
$\therefore y$ is $25\%$ of $x$

$12.5\% \,of\,192 = 50\% \,of\,?$ 

  1. $48$

  2. $96$

  3. $24$

  4. none of these


Correct Option: A
Explanation:
$12.5\% \,\, of \,192 = 50\%$ of ?

First, we will find $12.5\%\,\, of\,\, 192$

$\Rightarrow \dfrac{x}{192}\times 100= 12.5$

$\Rightarrow x=\dfrac{12.5\times 192}{100}= 24$

Now we will find of what $50\%$ will give $24$

i.e., $\dfrac{24}{y}\times 100= 50$

$y = 48$

$45$ is what percent of $54$ ?

  1. $81$%

  2. $83$%

  3. $85$%

  4. None of these


Correct Option: D
Explanation:

Percentage = $\dfrac {45}{54}$ $\times 100$

= $\dfrac {5}{6}$ $\times 100$  (removing common factor 9)

= $\dfrac {500}{6}$

= $\dfrac {250}{3}$

= $83\dfrac{1}{3}$%

Out of 800 oranges, 50 are rotten. Find the percentage of good oranges.

  1. $\displaystyle\,7\,\frac{1}{4}\%$

  2. $\displaystyle\,93\,\frac{1}{4}\%$

  3. $\displaystyle\,93\,\frac{3}{4}\%$

  4. $\displaystyle\,7\,\frac{3}{4}\%$


Correct Option: C
Explanation:

Good oranges are $ 800 - 50 = 750 $
So, percentage of good oranges $ = \cfrac { 750}{800} \times 100 $ %  $ = \cfrac {375}{4} $ % $ = 93 \cfrac {3}{4} $ %

A's income is 25% more than B's. Find, B's income is how much percent less than A's.

  1. $25\%$

  2. $22.5\%$

  3. $20\%$

  4. $30\%$


Correct Option: C
Explanation:

Let B's income be $ 100 $
Then A's income is $ 125 $
So,  B's income is $ \cfrac {125-100}{125} \times 100 = 20 \%$ less than of A.