Tag: fundamental quantities

Questions Related to fundamental quantities

The SI unit of specific latent heat is 

  1. $Jkg^{-1}K^{-1}$

  2. $J^{0}K^{-1}$

  3. $J kg^{-1}$

  4. $J kgK^{-1}$


Correct Option: C
Explanation:

The specific latent heat of a substance is the quantity of heat energy required to change the state of a unit mass of a substance.

${E} _{L}= ml$

here ${E} _{L}$ is the heat transferred, in joules,m is the mass, in kilograms, and l is the latent heat in joules per kilogram.

The SI unit for specific latent heat is $J{kg}^{-1}$.

The specific heat capacity of water in SI unit is :

  1. $4.2 Jg^{-1}K^{-1}$

  2. $42 Jg^{-1}K^{-1}$

  3. $420 J kg^{-1}K^{-1}$

  4. $4200 J kg^{-1}K^{-1}$


Correct Option: D
Explanation:

The specific heat capacity  of a substance is the heat needed to raise

the temperature of 1 kg of the substance by 1K (or by ${1}^{0}C$).
The specific heat capacity of water is $4200 J{kg}^{-1}{K}^{-1}$.

The SI unit of thermal capacity is ;

  1. $J\ kg^{-1}\  K^{-1}$

  2. $J^{-1}\ kg\ K^{-1}$

  3. $JK^{-1}$

  4. $J\  kg\ K^{-1}$


Correct Option: C
Explanation:


The heat or thermal capacity of a defined system is the amount of heat required to raise the system's temperature by one degree. It is expressed in units of thermal energy per degree temperature.

$q= C\times t$

$C=\dfrac{q}{\triangle t}$

here,$C=$heat or thermal capacity
        $q=$heat required (J)
        $\triangle t={t} _{1}-{t} _{2}$ (K)

so,The S.I. unit of heat or thermal capacity is $J{K}^{-1}$

Potential is measured in

  1. joule/coulomb

  2. watt/coulomb

  3. newton-second

  4. none of these


Correct Option: A
Explanation:

Potential is work done per unit charge $\displaystyle =\frac {J}{c}$

Name the physical quantity related to the following unit : watt.

  1. $Force$

  2. $Power$

  3. $Work$

  4. $Pressure$


Correct Option: B
Explanation:

Watt is  the SI unit of power, equivalent to one joule per second.

Power $=$ force $\times$ velocity $=$ Work/time
So, $watt=Nms^{-1}=J/s$

Name the physical quantity related to the following unit : pascal.

  1. $Force$

  2. $Pressure$

  3. $Work$

  4. $Distance$


Correct Option: B
Explanation:

The pascal (symbol: Pa) is the SI derived unit of pressure, internal pressure, stress, Young's modulus.

Pressure $=\dfrac{Force}{Area}$ 
So, $1\ pascal=1\ N/m^2$

Column I gives three physical quantities. Select the appropriate units for these from the choices given in column II. Some of the physical quantities may have more than one choice.

Column-I Column - II
a) Capacitance d) Ohm second
b) Inductance e) Coulomb$^{2}$ joule$^{ -1 }$
c) Magnetic induction f) Coulomb volt$^{ -1 }$
g) Newton (ampere/metre)$^{ -1 }$
h) Volt second (ampere)$^{ -1 }$
  1. a-e,f; b-d,h; c-g

  2. a-h; b-d; c-e

  3. a-e; b-g,h; c-g

  4. a-e,f; b-d,h; c-d,e


Correct Option: A
Explanation:

Capacitance is charge per unit volt. 

Volt has unit of work per unit chage. 
So capacitance has units of charge square per unit energy. 
Inductance is defined as volt per unit rate of change of current and voltage per unit current is resistance, so inductance is ohm second. 

The SI unit of magnetic permeability is

  1. ${ Am }^{ -1 }$

  2. ${ Am }^{ -2 }$

  3. ${ Hm }^{ -2 }$

  4. ${ Hm }^{ -1 }$


Correct Option: D
Explanation:

The correct option is D.

The magnetic permeability of any material is its property for allowing the magnetic line of force to pass through it. Therefore, the magnetic material can support the development of the magnetic field. This capability is measured by the magnetic permeability. Also, the magnetic line of force is directly proportional to the conductivity of the material. Its SI unit is Henry per meter i.e. $Hm^{-1}$ or newton per ampere square.

$\left( Coulomb \right) ^{ 2 }{ J }^{ -1 }$ can be the unit of :

  1. electric resistence

  2. electric energy

  3. electric capacity

  4. electric power


Correct Option: C
Explanation:

Electric energy $=ML^{2}T^{-2}$
Electric power $=ML^{2}T^{-3}$
Electric resistance $= ML^{2}I^{-2}T^{-3}$
Electric capacity $=M^{-1}L^{-2}I^{2}T^{4}$$=\left ( \dfrac{I^{2}T^{2}}{(M^{1}L^{2}T^{-2})} \right )=\left ( \dfrac{Q^{2}}{J} \right )$
Hence, option C is correct.

joule is the unit of

  1. heat

  2. temperature

  3. thermometry

  4. work


Correct Option: A,D
Explanation:

Joule is unit of heat , energy and work.