The sides of a triangle are $25,39$ and $40$. The diameter of the circumscribed circle is:
- $\cfrac { 133 }{ 3 } $
- $\cfrac { 125 }{ 3 } $
- $42$
- $41$
- $40$
Reveal answer
Fill a bubble to check yourself
B
Correct answer
Explanation
Circum radius formula
$R$ $=\cfrac { abc }{ \sqrt { (a+b+c)(b+c-a)(c+a-b)(a+b-c) } }$ .
Where $a, b, c$ are sides of triangle
$\Rightarrow$ $R$ $=\cfrac { 25\times 39\times 40\quad }{ \sqrt { (140\quad \times (54)\times (26)\quad \times (240) } } $
$=\cfrac { 25\times 39\times 40\quad }{ \sqrt { { 2 }^{ 3 } } \times 13\times 2\times { 3 }^{ 3 }\times 2\times 13\times { 2 }^{ 3 }\times 3 } $
$=\cfrac { 25\times 39\times 40\quad }{ \sqrt { { 2 }^{ 8 } } \times { 3 }^{ 4 }\times { 13 }^{ 2 } } $.
$=\cfrac { 25 \times \ 39 \times 40 }{ { 2 }^{ 4 }\times { 3 }^{ 2 }\times { 13 } } =\quad \cfrac { 25 \times 39 \times40\quad }{ 16\times 9\times { 13 } }$
$=\cfrac { 125 }{ 6 }$
$\therefore$ Diameter $=\cfrac { 125\times \ 2 }{ 6 } = \cfrac { 125 }{ 3 } $
$\therefore$ B) Answer.