Tag: binomial theorem, sequence and series

Quizzes (6) Questions (46)

Questions Related to binomial theorem, sequence and series

Multiple choice maths binomial theorem, sequence and series series introduction to series introduction to sequences and series

Identify the function for the following sequence $4, 10, 18, 28...$

  1. $2n(n+3)$
  2. $n(n+3)$
  3. $n(n-3)$
  4. $n^2(n+3)$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

When $n = 1$, $1(1+3)=4$ i.e. $1(1+3)$
When $n = 2$, $2(2+3)=10$ i.e. $2(2+3)$
When $n = 3$, $3(3+3)=18$ i.e. $3(3+3)$
When $n = 4$, $4(4+3)=28$ i.e. $4(4+3)$
So, $4, 10, 27, 28..$ is the function for the sequence is $n(n+3)$.

Multiple choice maths binomial theorem, sequence and series series introduction to series introduction to sequences and series

Identify the sequence for the following function $n(n+3)$.

  1. $4, 10, 18, 28..$
  2. $4, 12, 18, 28..$
  3. $2, 10, 18, 28..$
  4. $4, 10, 18, 38..$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Given function is $n(n+3)$
When $n = 1$, $1(1+3)=4$
When $n = 2$, $2(2+3)=10$
When $n = 3$, $3(3+3)=27$
When $n = 4$, $4(4+3)=28$....
So, $4, 10, 27, 28..$ is the function for the sequence is $n(n+3)$.

Multiple choice maths binomial theorem, sequence and series series introduction to series introduction to sequences and series

A, B, C, D are four points in a straight line. Distance from A to  B is 10, B to C is 5, C to D  is 4 and A to D is 1. Which  one of the following is the correct sequence of the  points ?

  1. A- B - C - D

  2. A - C - B - D

  3. A - D - C - B

  4. A - C - D - B
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
Given:$A,B,C,D$ are four points in a staraight line
Distance from $A$ to $B$ is $AB=10$ units
Distance from $B$ to $C$ is $BC=5$ units
Distance from $C$ to $D$ is $CD=4$ units
Distance from $A$ to $D$ is $AD=1$ unit
Here $10>5>4>1\Rightarrow\,AB>BC>CD>DA$
$AB$ is the longest line,the sequence is $A-B$
$\Rightarrow\,BC<CD\Rightarrow\,C$ lies between $A$ and $B$
$\therefore\,$the sequence is $A-C-B$
$AC=5$ units then $CB=5$ units
Now,$D$ may lie between $AC$ or $AB$
$\because \,CD<AC,\,CD<BC$
Since $AD$ starts from $A$ and lies between $A$ and $C$
and $AD=1$ unit
$\therefore\,D$ cannot lie between $B$ and $C$
Hence $D$ lies between $A$ and $C$
The correct sequence is $A-D-C-B$

Multiple choice maths binomial theorem, sequence and series series introduction to series introduction to sequences and series

Which of the following statements is false?

  1. $\left \{a _{ij}\right \} _{= 1}^{-\infty}$ can be viewed as a function $g : N\rightarrow R$ defined by $g(k) = a _{k}, \forall k\epsilon N$

  2. A sequence may have infinitely many terms

  3. A function is not necessarily a sequence
  4. The function $f : R\rightarrow R$ given by $f(x) = 2x + 1, x\epsilon R$ is a sequence
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
(A) Both are absolutely different things and can't be viewed as same.
This statement is false.

(B) A sequence may have infinitely many terms. for ex. function $f$ : N $\rightarrow $ N given by $f$($x$) = $x$ will have many terms. As our domain is infinity, so putting infinite values of $x$ will result in infinite no. of terms $f(x)$ as $f(x)$ is $x$.
This statement is true.

(C) There are examples of functions which do not necessarily forms a sequence. You will study things related to this in higher standard or definitely in college.  
This statement is true.

(D) The domain should be natural number, as domain represents the position of that particular term whether it is $1^{st}$ or $2^{nd}$ term, and it can't be $(2.5)^{th}$ term (NOTE : 2.5 is real no.), so there should be natural no. in place of real no. in domain. "A sequence may be regarded as a function whose argument can take on only positive integral values—that is, a functiondefined on the set of natural numbers"
So this statement is also false.
Multiple choice maths binomial theorem, sequence and series series introduction to series introduction to sequences and series

Find the first five terms of the sequence specified by the recursion formula
${a} _{k+1}={a} _{k}+3$, if ${a} _{1}=7$.

  1. $7,10,13,16,19$
  2. $6,9,12,15,18$
  3. $8,11,14,17,20$
  4. $5,8,11,14,17$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Given ${a} _{k+1} = {a} _{k}+3$ and ${a} _{1}=7$

So ${a} _{2}={a} _{1}+3 = 7+3=10$
${a} _{3}={a} _{2}+3 = 10+3=13$
${a} _{4}={a} _{3}+3 = 13+3=16$
${a} _{5}={a} _{4}+3=16+3=19$