Tag: hydrogen chloride: occurrence, preparation, purification and identification

Questions Related to hydrogen chloride: occurrence, preparation, purification and identification

The compound which does not have oxygen is :

  1. nitric acid

  2. sodium hydroxide

  3. hydrochloric acid

  4. acetic acid


Correct Option: C
Explanation:

Nitric acid $(HNO _3)$ has 3 oxygen atoms in its formula.

Sodium hydroxide $(NaOH)$ has 1 oxygen atom in its formula.
Acetic acid $(CH _3COOH)$ has 2 oxygen atoms in its formula.
Hydrochloric acid $(HCl)$ does not have oxygen atom in its formula.

Hence, option C is correct.

Identify the gas evolved when potassium sulphite is treated with dilute hydrochloric acid.

  1. ${ S } _{ 2 }$

  2. ${ O } _{ 2 }$

  3. ${ SO } _{ 2 }$

  4. None of these


Correct Option: C
Explanation:

When potassium sulphite is treated with dilute hydrochloric acid, sulphur dioxide gas is evolved along with potassium chloride and water.


$ { K } _{ 2 }{ SO } _{ 3 }+HCl\rightarrow KCl + { H } _{ 2 }O+{ SO } _{ 2 }$

Hence, option C is correct.

Which of the following gas is evolved when concentrated hydrochloric acid is made to react with manganese dioxide?

  1. ${ O} _{ 3 }$

  2. ${ O } _{ 2 }$

  3. ${ H} _{ 2 }$

  4. ${ Cl } _{ 2 }$


Correct Option: D
Explanation:

When concentrated hydrochloric acid reacts with manganese dioxide, chlorine gas as well as manganese(II) chloride and water. 


${ MnO } _{ 2 }+4HCl\rightarrow { MnCl } _{ 2 }+{ Cl } _{ 2 }+2{ H } _{ 2 }O$

Hence, option $\text{D}$ is correct.

Iron reacts with hydrogen chloride gas-forming (iron [II] chloride, iron [III] chloride) and hydrogen, The reaction is an example of :

  1. double decomposition

  2. synthesis

  3. simple displacement

  4. None of these


Correct Option: C
Explanation:

Iron reacts with hydrogen chloride gas-forming iron$ [II] $ chloride and hydrogen. The reaction is an example of simple displacement reaction.


$Fe + 2HCl \longrightarrow FeCl _2 + H _2$


Hence, the correct answer is option $\text{D}$.

Hydrochloric acid can be converted into chlorine by heating with :

  1. calcium oxide

  2. lead [III] oxide

  3. lead [IV] oxide

  4. lead [II] oxide


Correct Option: C
Explanation:

Explanation :-

In $HCl$, the chlorine atom present with $-1$ oxidation state and $Cl _2$ has zero oxidation state. It means chlorine undergoes reduction that is only possible in the presence of a strong oxidizing agent.

$\underset{agent (Pb \ in \ +4 \ state)}{\underset{strong \ oxidizing}{PbO _2}} + 4HCl \rightarrow PbCl _2 + Cl _2 + 2H _2O$

Compounds $A$ and $B$ are treated with dilute $HCl$ separately. The gases liberated are $Y$ and $Z$ respectively $Y$ turns acidified dichromate paper green while $Z$ turns lead acetate paper black. So $A$ and $B$ compounds are respectively:

  1. $Na _2SO _3, Na _2S$

  2. $NaCl, Na _2CO _3$

  3. $Na _2S, Na _2SO _3$

  4. $Na _2SO _3, K _2SO _4$


Correct Option: A

On adding few drops of dil. HCl to freshly precipitated ferric hydroxide, a red coloured colloidal solution is obtained. The phenomenon is known as :

  1. protective action

  2. flocculation

  3. coagulation

  4. peptisation


Correct Option: D
Explanation:

Peptization is the process of forming stable colloids by using an electrolyte to break up a precipitate and disperse it into the colloid


Hence, option D is correct.

$HCl$ gas cannot be dried by passing through:

  1. $H _{2}SO _{4}$

  2. $CaO$

  3. $P _{2}O _{5}$

  4. $CO$


Correct Option: B,C
Explanation:

$CaO$ and $P _2O _5$ are basic in nature so when $HCl$ is based over them, they will react with $HCl$ and form Salt and water, whereas $H _2SO _4$ and $CO$ are an acidic and hence greater affinity for water. So they can be used to dry $HCl$.

$HCl$  gas does not effect a dry strip of blue litmus paper but it turns red in the presence of a drop of water ?

  1. Blue litmus paper in the presence of water accepts the proton from $HCl$ and turns blue to red

  2. Blue litmus paper in the presence of water accepts the chloride ion from $HCl$ and turns blue to red

  3. Blue litmus paper in the presence of water with acid do not turn into red

  4. None of the above 


Correct Option: A
Explanation:

A dry litmus paper will not show any effect in the presence of dry HCL due to the absence of moisture ($H^+$ ions) in the litmus paper, whereas on putting a drop of water, the blue litmus paper immediately turns to red due to the presence of water in it hence presence of hydrogen ions ($H^+$ ions).


Hence, option A is correct.

When phosphorous pentoxide is reacted with $HCl$ gas, products are:

  1. $POCl _3$

  2. $P _4O _{10}$

  3. $H _3PO _2$

  4. $HPO _3$


Correct Option: A,D
Explanation:

Phosphorous pentoxide reacts with $HCl$ to form Phosphorous Oxychloride and metaphosphoric acid.


$2P _2O _5 + 3HCl \rightarrow POCl _3 + 3HPO _3$


Hence, $POCl _3$ and $HPO _3$ are correct.