Tag: our solar system

Quizzes (7) Questions (52)

Questions Related to our solar system

Multiple choice physics our solar system planets of the solar system solar system and sun introduction to solar system

The planets do not emit light of their own. This statement is:

  1. True

  2. False
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Planets are solid heavenly bodies which revolve around the Sun in a closed elliptical paths. A planet is made of rock and metal and produces no light of its own. A planet shines because it reflects the light of the Sun. Since, the planets are much nearer to the stars, they appear to be big and do not twinkle at night.
Hence, the statement is true.

Multiple choice physics our solar system planets of the solar system solar system and sun introduction to solar system

The earth revolves about the sun in an elliptical orbit with mean radius $9.3 \times 10^7\ m$ in a period of $1$ year. Assuming that there are no outside influences, then

  1. The earth's kinetic energy remains constant.

  2. The earth's angular momentum remains constant.

  3. The earth's potential energy remains constant.

  4. All the statements above are correct.
Reveal answer Fill a bubble to check yourself
C Correct answer
Multiple choice physics our solar system planets of the solar system solar system and sun introduction to solar system

The mass of a planet Jupiter is $1.9 \times 10^{27} kg$ and that of the Sun is $1.99 \times 10^{30} kg$. The mean distance of the Sun from Jupiter is $7.8 \times 10^{11} m$. The gravitational force, which the Sun exerts on Jupiter is.

  1. $4.1 \times 10^{23} N$

  2. $4.1 \times 10^{34} N$

  3. $2.2 \times 10^{23} N$

  4. $2.2 \times 10^{34} N$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Using Newton's Law of Universal Gravitation, F = G * (m1 * m2) / r^2. Plugging in G = 6.67e-11, m1 = 1.9e27, m2 = 1.99e30, and r = 7.8e11, the calculation yields approximately 4.1e23 N.

Multiple choice physics our solar system planets of the solar system solar system and sun introduction to solar system

Two plates move around the Sun. The periodic times and the mean radii of the orbits are $T _1, T _2$ and $r _1, r _2$ respectively. The ratio $\dfrac{T _1}{T _2}$ is equal to.

  1. $\left (\dfrac{r _1}{r _2} \right)^{\dfrac{1}{2}}$

  2. $\left (\dfrac{r _1}{r _2} \right)$

  3. $\left (\dfrac{r _1}{r _2} \right)^{2}$

  4. $\left (\dfrac{r _1}{r _2} \right)^{\dfrac{3}{2}}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Kepler's Third Law of Planetary Motion states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit (T^2 proportional to r^3). Therefore, T1/T2 = (r1/r2)^(3/2).

Multiple choice physics our solar system planets of the solar system solar system and sun introduction to solar system

The radius of Jupiter is 11 times the radius of the Earth. Calculate the ratio of the volumes of Jupiter and the Earth. How many Earths can Jupiter accommodate ? 

  1. 1331

  2. 1221

  3. 111

  4. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Planets are like spheres. Volume of a sphere is given by, 
V = $\displaystyle{\frac{4}{3}\pi r^3}$ 
Let the r$ _1$, r$ _2$ be radii of the Jupiter and the Earth respectively. 
r$ _1$ $= 11r _2$ _(1)
Volume of Jupiter, V$ _1$ = $\displaystyle{\frac{4}{3}\pi r^3 _1}$ _(2) 
Volume of Earth, V$ _2$ = $\displaystyle{\frac{4}{3}\pi r^3 _2}$ _(3) 
$\displaystyle{\frac{(2)}{(3)} \Rightarrow \frac{V _1}{V _2} = \frac{\frac{4}{3}\pi r _1^3}{\frac{4}{3} \pi r _2^3} = \frac{r _1^3}{r _2^3}}$ 
$\displaystyle{\frac{V _1}{V _2} = \frac{r _1^3}{r _2^3} = \frac{(11r _2)^3}{r _2^3} = (11)^3}$ = 1331 
Jupiter can accommodate 1331 number of Earths within it.