Tag: earth's energy budget

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Questions Related to earth's energy budget

Multiple choice evs solar energy water cycle earth's energy budget solar energy and its applications

Sun loses approximately a weight of ________ every second which is the amount of ${H} _{2}$ gas that the sun turns into energy.

  1. $4$ lakh million tons

  2. $4$ million tons

  3. $4$ lakh tons

  4. $40$ lakh tons
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The Sun loses approximately 4 million tons of mass every second as it converts hydrogen into helium through nuclear fusion.

Multiple choice evs solar energy water cycle earth's energy budget solar energy and its applications

The correct order of spatial location of different layer of sun are

  1. core-radiative zone-convective zone-photosphere-chromosphere-transition region

  2. core-convective zone-chromosphere-photosphere-radiative zone

  3. core-convective zone-photosphere-chromosphere-convective zone-radiative zone

  4. core-radiative zone-convective zone-chromosphere-convective zone-photosphere
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The correct spatial order from the center outward is: Core, Radiative Zone, Convective Zone, Photosphere, Chromosphere, and Transition Region.

Multiple choice evs solar energy water cycle earth's energy budget solar energy and its applications


Most of the sources of energy we use represent stored solar energy. Which of the following is not ultimately derived from the Sun's energy?

  1. Geothermal energy

  2. Wind Energy

  3. Nuclear energy

  4. BioMass
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Nuclear energy is not ultimately derived from the Sun's energy as uses radioactive substances to produce energy.

Multiple choice evs solar energy water cycle earth's energy budget solar energy and its applications

The sun radiates electromagnetic energy at the rate of $3.9 \times 10^{26}W$. Its radius is $6.96\times 10^8m$.The intensity of sun light at the solar surface will be $-(in \, W/m^2)$

  1. $1.4 \times 10^4$

  2. $2.8 \times 10^5$

  3. $4.2 \times 10^6$

  4. $5.6 \times 10^7$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

$I=\frac { P }{ { 4\pi { R^{ 2 } } } } =\frac { { 3.9\times { { 10 }^{ 26 } } } }{ { 4\times 3.14\times { { \left( { 6.96\times { { 10 }^{ 8 } } } \right)  }^{ 2 } } } } =5.6\times { 10^{ 7 } }w/{ m^{ 2 } }$