Tag: metric system

Questions Related to metric system

A shopkeeper purchased $392\ kg\ 500\ g$ of orange. Later on, he found that $56\ kg\ 460\ g$ of oranges were rotten. Find the quantity of oranges in good condition.

maths metric system converting between units of areas the metric system units of area and their conversions

  1. $330\ kg\ 400\ g$

  2. $336\ kg\ 4\ g$

  3. $336\ kg\ 40\ g$

  4. $33.6\ kg\ 40\ g$

Show answer
Correct Option: C
Explanation:
Quantity of oranges in good condition$=\left( 392.500-56.460 \right) ㎏$
$=336.040ℊ\Rightarrow$ $336$ ㎏ $40$ gm

Add $95\ kg\ 45\ g$ and $45\ kg\ 300\ g$.

maths metric system converting between units of areas the metric system units of area and their conversions

  1. $14\ kg\ 34\ g$

  2. $140\ kg\ 300\ g$

  3. $14\ kg\ 345\ g$

  4. $140\ kg\ 345\ g$

Show answer
Correct Option: D
Explanation:

We know that, $gram$  is abbreviated as $gm$

$1$  $kg =1000$  $gram$


(i) To add   $95$ $kg$  $45$  $gm$  to $45$ $kg$  $300$  $gm$

$95$ $kg$  $45$  $gm$ $ = 95kg + 45gm$  $=A $   ...................(1)

$45$ $kg$  $300$  $gm$ $ = 45kg + 300gm$  $=B $   ...................(2)


Now as per the question we have to add A and B

$A+B = [95$ $kg$  $45$  $gm$] $+ $ [$45$ $kg$  $300$  $gm$]

$A+B = [95$ $kg$ $+$  $45$  $kg$] $+ $ [$45$ $gm$ $+$  $300$  $gm$]


$A+B = 140  $  $kg$ $+ $   $345$ $gm$ 

So, Option $D$ is correct

If Raina weighs $54\ kg\ 43\ g$ and Rohit weighs $60\ kg\ 760\ g$. Then, the sum of weights of Raina and Rohit is :

maths metric system converting between units of areas the metric system units of area and their conversions

  1. $114\ kg\ 803\ g$

  2. $115\ kg\ 19\ g$

  3. $110\ kg\ 703\ g$

  4. $104\ kg\ 803\ g$

Show answer
Correct Option: A
Explanation:
Let $54$ $kg$  $43$  $gm$ $ = 54kg + 43gm$  $=A =  $  Weight of  Raina

$60$ $kg$  $760$  $gm$ $ = 60kg + 760gm$  $=B =  $  Weight of  Rohit

(i) We have to add $54$ $kg$  $43$  $gm$ to $60$ $kg$  $760$  $gm$

$ 54kg + 43gm$  $=A $   ...................(1)

$  60kg + 760gm$  $=B $   ...................(2)


Now as per the question we have to add A and B

$A+B = [54$ $kg$  $43$  $gm$] $+ $ [$60$ $kg$  $760$  $gm$]

$A+B = [54$ $kg$ $+$  $60$  $kg$] $+ $ [$43$ $gm$ $+$  $760$  $gm$]


$A+B = 114  $  $kg$ $+ $   $803$ $gm$ 

The sum of weights of Raina and Rohit is  $ 114  $  $kg$   $803$ $gm$
Hence, Option $A$ is correct

Average weight of $25$ persons is increased by $1$ kg when one man weighing $60$ kg is replaced by a new person. Weight of new person is

maths metric system converting between units of areas the metric system units of area and their conversions

  1. $50$ kg

  2. $61$ kg

  3. $86$ kg

  4. $85$ kg

Show answer
Correct Option: D
Explanation:

Total weight increased $=1\times 25=25 kg$
$\therefore$ weight of new person is $60+25=85 kg$

If $A$ weighs $43\ kg\ 234\ g$ and $B$ weighs $56\ kg\ 450\ g$. Then the difference between the weights of $A$ and $B$ is :

maths metric system converting between units of areas the metric system units of area and their conversions

  1. $12\ kg\ 811\ g$

  2. $13\ kg\ 216\ g$

  3. $13\ kg\ 306\ g$

  4. $10\ kg\ 216\ g$

Show answer
Correct Option: B
Explanation:
The weight of $A = 43\ kg\ 234\ g$

the weight of $A = 56\ kg\ 450\ g$
(i) Difference between weights of $A$ and $B$ is obtained by subtracting $43$ $kg$  $234$  $gm$ from $56$ $kg$  $450$  $gm$

$43$ $kg$  $234$  $gm$ $ = 43kg + 234gm$  $=A $   .... (1)

$56$ $kg$  $450$  $gm$ $ = 56kg + 450gm$  $=B $   ..... (2)


Now as per the question we have to subtract A from B

$B-A = [56\ kg+ 450\ gm] - [43\ kg+234\ gm$

$B-A = [56\ kg-43\ kg]+ [450\ gm -234\ gm] $


$B-A = 13\ kg\ 216\ gm$
So, Option $B$ is correct

Add $17\ kg,13\ kg\ 940\ g$ and $15\ kg\ 65\ g$.

maths metric system converting between units of areas the metric system units of area and their conversions

  1. $40\ kg\ 65\ g$

  2. $4\ kg\ 650\ g$

  3. $46\ kg\ 50\ g$

  4. $46\ kg\ 5\ g$

Show answer
Correct Option: D