Tag: hcf-lcm

Questions Related to hcf-lcm

Find the G.C.F of $2541$ and $3102$ in the scale of seven.

  1. $87$

  2. $54$

  3. $33$

  4. $85$


Correct Option: C
Explanation:
Prime factors of $2541$ are $3, 7, 11, 11$. Prime factorization of $3102$ in exponential form is

$2541=3^1\times 7^1\times 11^2$


Prime factors of $3102$ are $2, 3, 11, 47$. Prime factorization of $3102$ in exponential form is

$3102=2^1\times 3^1\times 11^1\times 47^1$

We found the factors and prime factorization of $2541$ and $3102$. The biggest common factor number is the $GCF$ number.


So, the greatest common factor $2541$ and $3102$ is $3\times 11=33$.

Hence, this is the answer.

Find $HCF$ by finding factors:
$6$ and $8$.

  1. $4$

  2. $6$

  3. $2$

  4. $8$


Correct Option: C
Explanation:

Factorization of the following.

$6 = 3 \times 2\times 1$
$8 = 2 \times 2 \times 8\times 1$

Since, The common factor is $2$.This implies that
$H.C.F = 2$

Hence,the correct option is $C$

Greatest number which divided $926$ and $2313$, leaving $2$ and $3$ remainders, respectively, is?

  1. $462$

  2. $54$

  3. $152$

  4. $154$


Correct Option: A
Explanation:

A number divides 926 and 2313 leaving remainders 2 and 3 respectively.

This means that the number perfectly divides 926 - 2 = 924 as well as 2313 - 3 = 2310.

Now we simply need to find the HCF of 924 and 2310 

On calculating the HCF , we get it as  462

Hence, the answer is 462

Choose the correct answer from the alternatives given.
LCM of $\dfrac 14 $and $\dfrac 18$ is

  1. $\dfrac12$

  2. $1$

  3. $\dfrac 14$

  4. $\dfrac 18$


Correct Option: C
Explanation:
We know that,
LCM of dfrac tions = $\dfrac { LCM\ of\ numerators}{HCF\ of\ denominators}$
= $\dfrac { LCM (1,1)}{ HCF(4,8)} = \dfrac {1}{4}$ 

The greatest integer that divides 358, 376, 334 leaving the same remainder in each case is

  1. 6

  2. 7

  3. 8

  4. 9


Correct Option: A
Explanation:

The difference between each set of two numbers is respectively 18, 42 and 24.
Now, as the remainder should be the same in each case, the number is the greatest common divisor of 18, 24 and 42.
$18=2\times 3\times 3$
$24=2\times 2\times 2\times 3$
$42=2\times 3\times 7$
$\therefore HCF=2\times 3=6$
$\therefore$ The required number is 6.

A merchant has $120$ litres of oil of one kind, $180$ litres  of another kind and $240$ litres of third kind. He wants to sell the oil by filling the three kinds of oil in tins of equal capacity. What should be the greatest capacity of such a tin?

  1. $20$ liters

  2. $30$ liters

  3. $60$ liters

  4. $80$ liters


Correct Option: C
Explanation:
$\text{We need to find the HCF or GCD that is Greatest Common Divisor}$ 

${120 = 2^3 \times3\times5}$

${180 = 2^2\times3^2 \times5}$

${240 = 2^4\times3\times5}$

${GCD = 2^2\times3\times5= 60}$

$\text{The greatest capacity = 60 liters}$

$\text{So the merchant needs to fill 60 liters of all types of oils }$

$\text{Hence option C is correct}$


HCF of two co-prime numbers is ___.

  1. $1$

  2. $0$

  3. $2$

  4. None of the above


Correct Option: A
Explanation:

When two numbers have no common factors other than $1$, so they are co-prime numbers.

So, their HCF is $1$.
Hence, the answer is $1$.

HCF of $36$ and $144$ is ______.

  1. $36$

  2. $144$

  3. $4$

  4. $2$


Correct Option: A
Explanation:

To find the HCF of $36$ and $ 144 $, first factorise them:

$36= 2 \times 2 \times 3 \times 3 $
$144= 2 \times 2 \times 2 \times 3 \times 3 $
Taking common factor, we get

HCF $= 2 \times 2 \times 3 \times 3 $ $=36$

Hence, the answer is $36$.