Tag: constellations and galaxies

Questions Related to constellations and galaxies

Multiple choice physics constellations and galaxies light year evolution and end stages of stars in the world of stars

The method of measuring distance to stars beyond 100 light-years is

  1. Capheid variable stars

  2. Heid variable stars

  3. Lowheid variable stars

  4. None

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The brightness of the stars changes over time. The difference in the brightness over time allows calculating the distance to the star. This is the cepheid variable stars method that is used to measure the distance to stars beyond 100 light years.

The method of measuring the distance to stars beyond 100 light-years is  Cepheid variable stars

Multiple choice physics constellations and galaxies light year evolution and end stages of stars in the world of stars

Which is the another unit used by astronomers for measuring distance to other parts of Milky Way Galaxy?

  1. Km

  2. Light year

  3. Parsec

  4. Meter

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Units used in astronomy by astronomers are an astronomical unit, light year and parsec.

another unit used by astronomers for measuring the distance to other parts of Milky Way Galaxy is Parsec

Multiple choice physics constellations and galaxies light year evolution and end stages of stars in the world of stars

How can Cepheid variable stars helpful to figure out true brightness?

  1. These stars change their brightness over time

  2. These stars lower their brightness over time

  3. These stars raise their brightness over time

  4. None

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The brightness of the stars changes over time. The difference in the brightness over time allows calculating the distance to the star. This is the cepheid variable stars method that is used to measure the distance to stars beyond 100 light years.

These stars change their brightness over time

Multiple choice physics constellations and galaxies light year evolution and end stages of stars in the world of stars

All the stars are at the same distance from us. This statement is

  1. True

  2. False

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Our Sun is the nearest star to the Earth. After the Sun, the next nearest star is 4.3 light years away. A light year is the distance light travels in one year. One light year is 10 trillion kilometers. Hence, all the stars are not the same distance from our Earth. They are at different distances. Hence, given statement is false.

Multiple choice physics constellations and galaxies light year evolution and end stages of stars in the world of stars

The $6563 \mathring {A}$ line emitted by hydrogen atom in a star is found to be red shifted by $5\mathring{A}$. the speed with which the star is receding from the earth is:

  1. $17.3\times 10^3 $ m/s
  2. $4.29 \times 10^7 $m/s
  3. $3.39 \times 10^5 $m/s
  4. $ 2.29 \times 10^5$ m/s
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

$\dfrac{\triangle v}{v}=\dfrac{V _{radiant}}{C}$
$v=\dfrac{C}{\lambda}$
$d.v=\dfrac{C}{\lambda^2}.dv=\dfrac{\dfrac{x}{\lambda^2}}{\dfrac{C}{\lambda}}=\dfrac{d\lambda}{\lambda}$
$\dfrac{d\lambda}{\lambda }=\dfrac{V _{radial }}{C}$
$\dfrac{5 \times 10^{-10}}{6563 \times 10^{-10}}=\dfrac{C _{radial}}{3\times 10^8}$
Calculate $V _radial=\dfrac{5}{6563}\times 3\times 10^8$
$=\dfrac{15}{6563}\times 10^8$
$\dfrac{15}{6.56}\times 10^5$
$2.29\times 10^5m/s$

Multiple choice physics constellations and galaxies light year evolution and end stages of stars in the world of stars

A star is seen to be rising on the eastern horizon at $23:00$ hrs. At what time the star will rise 2 days later

  1. $00:00$ hrs
  2. $21:40$ hrs
  3. $23:20$ hrs
  4. $23:00$ hrs
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation
The stores appear to be static when seen from earth thus they only appear to be moving due to earth's rotation about its axis. It takes exactly $24$ hors to complete one rotation. So after days $(2\times 24\ hrs)$, the far will be seen rising at the same time
$(i.e., 23:00\ hrs)$