Tag: measurement of physical quantities

Questions Related to measurement of physical quantities

Which system of units has been taken as standard?

  1. M.K.S

  2. C.G.S

  3. Both

  4. None


Correct Option: A
Explanation:

In S.I system (standard international system), the units of mass,length and time are same,as that of M.K.S system. However , it is an enlarged system encompassing all fundamental units.

MKS system means

  1. Millimeter, kilometre, seconds

  2. Metre, kilogram, seconds

  3. Millisecond, kilolitre, seconds

  4. Milligram, kilogram, seconds


Correct Option: B
Explanation:

In MKS system,M stands for metre (length),K stands for kilogram(mass) and S stands for seconds(time).

Units of Planck's constant in CGS system are:

  1. Erg per second

  2. Second per erg

  3. Erg second

  4. Erg per second per second


Correct Option: C
Explanation:

Planck's constant, symbolized h, relates the energy in one quantum (photon) of electromagnetic radiation to the frequency of that radiation.  In the centimeter-gram-second (CGS) or small-unit metric system, it is equal to approximately $6.626176\times 10^{-27}\,$Erg Second.

If force (F), work (W) and velocity (V) are taken as fundamental quantities then the dimensional formula of time (T) is

  1. $\left[ { W }^{ 1 }{ F }^{ 1 }{ V }^{ 1 } \right] $

  2. $\left[ { W }^{ 1 }{ F }^{ 1 }{ V }^{ -1 } \right] $

  3. $\left[ { W }^{ -1 }{ F }^{ -1 }{ V }^{ -1 } \right] $

  4. $\left[ { W }^{ 1 }{ F }^{ -1 }{ V }^{ -1 } \right] $


Correct Option: D
Explanation:
We know,

$[W]=ML^2T^{-2}$

$[F]=MLT^{-2}$

$[V]=LT^{-1}$

Let,
$W^aF^bV^c=M^0L^0T$

$a+b=0$

$2a+b+c=0$, $a+c=0$

$-2a-2b-c=1$

$c=-1,a=1,b=-1$

Hence , $[T]=[WF^{-1}V^{-1}]$

Option $\textbf D$ is the correct answer

The ratio of SI unit to CGS unit of G is

  1. $10^{3}$

  2. $10^{2}$

  3. $10^{-2}$

  4. $10^{-3}$


Correct Option: A
Explanation:
SI unit of G is  $\dfrac{N m^2}{kg^2}$.
CGS unit of G is  $\dfrac{dyne \ cm^2}{gm^2}$
We know that  $1 \ N = 10^5 \ dyne$ and $1 \ m = 10^2 \ cm$ and $1 \ kg = 10^3 \ gm$
So ratio of SI unit to CGS unit   $ = \dfrac{\dfrac{N  \ m^2}{kg^2}}{\dfrac{dyne \ cm^2}{gm^2}} = \dfrac{\dfrac{10^5 \ dyne \ (10^2 \ cm)^2}{(10^3 \ gm)^2}}{\dfrac{dyne \ cm^2}{gm^2}} = 10^3$
Correct answer is option A.

Which of the following represents the magnitude of a temperature correctly?

  1. 10 k

  2. 10 Kelvins

  3. 10 Ks

  4. 10 K


Correct Option: D
Explanation:
Temperature is measured in Kelvin which is represented by $K$
Thus, $10 \ K$ is the correct representation of temperature.

1 Newton $=$

  1. $10^4 dyne$

  2. $10^5 dyne$

  3. $10^6dyne$

  4. $10^7 dyne$


Correct Option: B
Explanation:
S.I. unit of force is Newton and CGS unit of force is done.

We know $F=ma$
so, force can be expresses in S.I. Units as $Kg m s^{-2}$
and dyne can be expressed as $gcms^{-2}$
1 Newton= $kg ms^{-2}$ 
                 =$10^3 g*10^2 cms  s^{-2}$
                 =$10^5 g cm s^{-2}$
                 =$10^5 dyne$

How many fundamental units are present in the SI system of units?

  1. 5

  2. 6

  3. 7

  4. 3


Correct Option: C
Explanation:

There are seven fundamental units in the SI system of units which are mass, length, time, temperature, electric current, mole and luminous intensity.

State whether true or false.
The quantity of matter in a body is called its mass.

  1. True

  2. False


Correct Option: A
Explanation:

Mass of a body is defined as the quantity of matter contained in a body.

The units which can neither derived from one another nor resolved into any thing more basic are called 

  1. Fundamental unit

  2. Scale

  3. Derived unit

  4. Standard unit


Correct Option: A
Explanation:

The units which can neither derived from one another nor resolved into any thing more basic are called fundamental unit. It is independent of any other unit.