Tag: black body radiation

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Questions Related to black body radiation

Multiple choice physics energy production perfectly black body black-body radiation black body radiation

The original temperature of a black body is $727^\circ C$. Calculate temperature at which total radiant energy from this black body becomes double:

  1. $971K$
  2. $1189K$
  3. $2001K$
  4. $1458K$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$Rediant Energy = \sigma T^2$

$Energy = \sigma (1000)^4$
$E _2 = 2 E _1$
$Then$
$\sigma T _2 ^{4} = 2 \times \sigma (1000)^4$
$T _2 = 2^\frac{1}{4} \times1000$
$T _2 = 1189 K$

Multiple choice physics energy production perfectly black body black-body radiation black body radiation

Temp. of black body is $3000K$ when black body cools. Then change in wavelength $\Delta \lambda=9$ micron corresponding to maximum energy density. Now temp. of black body is:

  1. $300K$
  2. $2700K$
  3. $270K$
  4. $1800K$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

According to Wien's displacement law, lambda_max * T = constant. Initially, T1 = 3000K. If lambda_max changes by 9 microns, we need the initial lambda_max. Assuming lambda_max1 = 1 micron (typical for 3000K), then lambda_max2 = 10 microns. T2 = (1/10) * 3000 = 300K.

Multiple choice physics energy production perfectly black body black-body radiation black body radiation

The rate of emission of radiation of a black body at 273$^{ \circ  }{ C }$ is E, then the rate of emission of radiation  of this body at 0$^{ \circ  }{ C }$ will be :-

  1. $\dfrac { E }{ 16 } $
  2. $\dfrac { E }{ 4 } $
  3. $\dfrac { E }{ 8 } $

  4. 0
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Stefan-Boltzmann law states E is proportional to T^4. T1 = 273 + 273 = 546K. T2 = 0 + 273 = 273K. Ratio E2/E1 = (273/546)^4 = (1/2)^4 = 1/16. Thus E2 = E/16.

Multiple choice physics energy production perfectly black body black-body radiation black body radiation

A blackbody does not

  1. emit radiation

  2. absorb radiation

  3. reflect radiation

  4. refract radiation
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

An ideal blackbody is defined as an object that absorbs all electromagnetic radiation that falls on it, regardless of frequency or angle of incidence. Because it absorbs everything, it does not reflect any radiation.

Multiple choice physics energy production perfectly black body black-body radiation black body radiation

An ideal black body is a :

  1. lump of charcoal heated to a high temperature

  2. metal coated with a black dye

  3. glass surface coated with coal tar

  4. hollow enclosure blackened inside and having a small hole
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Hollow enclosure blackened inside and having a small hole is a very good example of a black body.
Suppose once light enters inside it.
It may be absorbed or it may be reflected.
Since it is blackened from inside, there is a high probability that it will be absorbed.
Now if it is reflected, it will suffer multiple reflections and it is very unlikely that it will come out of the hole because the aperture of hole is too small. Moreover, with each reflection, more and more fraction of it will be absorbed. So, it will serve as a good black body.

Multiple choice physics energy production perfectly black body black-body radiation black body radiation

Which of the following is more close to a black body?

  1. Black board paint

  2. Green leaves

  3. Black holes

  4. Red roses
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

we know that $\alpha +\rho +\tau =1$
${\alpha}= absorptivity$
${\rho}=reflectivity$
${\tau}=transmitivity$
so for black body ${\rho}\  and \ {\tau} \ will\  be \ zero$
so ${\alpha}=1$ so black hole has also ${\alpha}=1$ which is equivalent to black body.

Hence we can consider black holes as black body.

Multiple choice physics energy production perfectly black body black-body radiation black body radiation

Initially a black body at absolute temperature $T$ is kept inside a closed chamber at absolute temperature $T _{o}$. Now the chamber is slightly opened to allow sun rays to enter. It is observed that temperatures $T$ and $T _{o}$ remains constant.Which of the following statement is/are true?

  1. The rate of emission of energy from the black body remains the same

  2. The rate of emission of energy from the black body increases

  3. The rate of absorption of energy by the black body increases.

  4. The energy radiated by the black body equals the energy absorbed by it
Reveal answer Fill a bubble to check yourself
A,D Correct answer
Explanation

It is given that the absolute temperatures of both the black body and the surroundings are constant with time, even after sunlight(radiation) is incident on it.

  • When a body absorbs radiation, its temperature increases
  • When a body emits radiation, its temperature decreases
Also the sun, being a source of infinite radiation(very large source of radiation).
We infer from this that the incident radiation should be of constant magnitude.
And if the temperature of the black body is a constant, that means it's emission and absorption of radiation are matched and equal. The absorption is of constant magnitude, because the sun's radiation is of constant value. Hence the emission is of constant value also and is equal to the absorption. The options follow.

Multiple choice physics energy production perfectly black body black-body radiation black body radiation

An ideal black body at room temperature is thrown in a furnace. It is observed that

  1. initially it is darkest body and at later time the brightest

  2. it is darkest body at all the times

  3. it cannot be distinguished at all the times

  4. initially it is the darkest body and at later times it cannot be distinguished
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Initially the black body is in bright environment. So, it appears dark and finally when its temperature becomes equal to temperature of furnace, it becomes invisible