Tag: percentage composition and empirical formula

Questions Related to percentage composition and empirical formula

Calculate the percent composition of carbon in $C _6H _{12}O _6$ :

  1. $50%$

  2. $40%$

  3. $35.3%$

  4. $22.1%$


Correct Option: B
Explanation:

Molar mass of compound $: 6(12.0)+12(1.01)+6(16.0)=180g/mol$
Mass due to carbon $=6(12.0)=72.06g/mol$
$%$ composition of $C=72/180\times 100=40%$

The formula for % composition of a compound is:

  1. molar mass of a compound/mass due to specific component $\times$ 100

  2. mass due to specific component $\times$ 100

  3. mass due to specific component/molar mass of a compound $\times$ 100

  4. molar mass of a specific component/temperature $\times$ 100


Correct Option: C
Explanation:

To calculate the per cent composition of a component in a compound: Find the molar mass of the compound by adding up the masses of each atom in the compound using the periodic table or a molecular mass calculator. Calculate the mass due to the component in the compound you are for which you are solving by adding up the mass of these atoms. Divide the mass due to the component by the total molar mass of the compound and multiply by 100.

% $\text{composition of a compound}=\cfrac{\text{ Mass due to specific component}}{\text{molar mass of a compound}}\times 100$

Hence, the correct option is $\text{C}$

% composition requires ................ of the compound :

  1. molar mass

  2. temperature

  3. atmospheric pressure

  4. both a and b


Correct Option: A
Explanation:

The present composition (by mass) of a compound can be calculated by dividing the mass of each element by the total mass of the compound. i.e. by calculating the $molar$ $mass$ of the compound.