Tag: law of reciprocal proportion

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Questions Related to law of reciprocal proportion

Multiple choice law of reciprocal proportion laws of chemical combination basic concepts of chemistry some basic concepts of chemistry chemistry

Two volumes of ammonia, on dissociation gave one volume of nitrogen and three volumes of hydrogen. How much hydrogen will be obtained from dissociation of $40 \,mL\, of\, NH _3$ ? 

  1. 60

  2. 40

  3. 80

  4. 50
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Its easy as $NH _3 : N _2 : H _2$ IS 2:1:3 As $NH _3$ is 40 ml hence form 60 ml of h2 and 20 ml of n2

so the answer is A

Multiple choice law of reciprocal proportion laws of chemical combination basic concepts of chemistry some basic concepts of chemistry chemistry

Which one of the following sets of compounds correctly illustrate the law of reciprocal proportions.

  1. $P _{2}O _{3}, PH _{3}, H _{2}O$
  2. $P _{2}O _{5}, PH _{3}, H _{2}O$
  3. $N _{2}O _{5}, NH _{3}, H _{2}O$
  4. $N _{2}O, NH _{3}, H _{2}O$
  5. $NO _{2}, NH _{3}, H _{2}O$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Law of Reciprocal proportions:-

When two different elements combine with the same mass of a $3^{rd}$ element, the ratio of masses in which they do so must be same or multiple of the mass ratio in which they combine with each other.
$A)$ $P _2O _3,PH,H _2O$
The ratio of phosphorous combining with oxygen in $P _2O _3$ is 
$P:O=62:48=31:24$
The ratio of Phosphorous combining with hydrogen in $PH _3$ is
$P:H=31:3$
The ratio of hydrogen combining with oxygen in $H _2O$ is 
$H:O=2:16=1:8$       $\longrightarrow 1$
Now, the ratio of hydrogen & oxygen combining with $P$
$\Rightarrow 3:24=1:8$     $\longrightarrow 2$
From $1$ & $2$,  $1:8$ is same in both cases
$\therefore$ Law of reciprocal proportions is illustrated correctly.

Multiple choice law of reciprocal proportion laws of chemical combination basic concepts of chemistry some basic concepts of chemistry chemistry

$A$ g of sulphur and $ B$ g of oxygen are allowed to react to form $SO _2 $. What will be the ratio of $ A:B$ ?

  1. $1:1$
  2. $1:2$
  3. $1:3$
  4. $1:4$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
$S\left( 32ℊ \right) +{ O } _{ 2 }\left( \left( 16\times 2 \right) ℊ \right) \longrightarrow S{ O } _{ 2 }$
$\Rightarrow $Ratio of A and B is $1:1$
Multiple choice law of reciprocal proportion laws of chemical combination basic concepts of chemistry some basic concepts of chemistry chemistry

7.95 gm oxide of copper on reaction with hydrogen shows a mass loss and the residue obtained weighs 6.35 gm. In another experiment, 19.05 gm of copper was dissolved in nitric acid and the copper nitrate produced was converted to oxide weighing 23.85 gm. This data illustrates:

  1. Law of multiple proportion

  2. Law of mass conservation

  3. Law of reciprocal proportion

  4. Law of constant proportion
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The ratio of Masses of oxide of $Cu$ to $Cu$,

In experiment $A=\cfrac{7.95}{6.35}=1.25$
In experiment $B=\cfrac{23.85}{19.05}=1.22$
It shows the law of constant proportion.

Multiple choice law of reciprocal proportion laws of chemical combination basic concepts of chemistry some basic concepts of chemistry chemistry

Which of the following sets of compounds correctly illustrate the law of reciprocal proportion ?

  1. $N _2O,NH _3,SO _2$
  2. $P _2O _5,PH _3,H _2O$
  3. $NO _2,NH _3,SO _3$

  4. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The law of reciprocal proportions is one of the basic laws of stoichiometry. It relates the proportions in which elements combine across a number of different elements. A simple statement of the law is:

 Element A combines with element B and also with C, then, if B and C combine together, the proportion by weight in which they do so will be simply related to the weights of B and C which separately combine with a constant weight of A.

Hydrogen combines with Oxygen to form ${ H } _{ 2 }O$

$2:16\\ 1:8$

Phosphorous combines with Oxygen to form ${ P } _{ 2 }O _{ 5 }$

$62:80\\ 31:40\\ $

Phosphorous combines with Hydrogen to form $P{ H } _{ 5 }$

$31:5\\ \cfrac { 31 }{ 40 } \times \cfrac { 8 }{ 1 } =\cfrac { 31 }{ 5 } $

Multiple choice law of reciprocal proportion laws of chemical combination basic concepts of chemistry some basic concepts of chemistry chemistry

Two oxides of metal contain $27.6$% and $30$% of oxygen respectively. if the first one is $M _3O _4$ then which of the following will be the other one?

  1. $M _3O _3$
  2. $M _2O _3$
  3. $M _4O _2$
  4. $M _1O _3$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
Given, ${ M } _{ 3 }{ O } _{ 4 }$; Let mass of the metal$=x$
% of metal in ${ M } _{ 3 }{ O } _{ 4 }=\cfrac { 3x }{ 3x+64 } \times 100$
But as given % age$=\left( 100-27.6 \right) =72.4$
So, $\left( \cfrac { 3x }{ 3x+64 }  \right) \times 100=72.4$
$\Rightarrow x=56$
In 2nd oxide, oxygen$=30$%, So metal$=70$%
So, the ratio is $M:O$
$\cfrac { 70 }{ 56 } :\cfrac { 30 }{ 16 } $
$1.25:1.875$
$2:3\Rightarrow $ oxide is ${ M } _{ 2 }{ O } _{ 3 }$
Multiple choice law of reciprocal proportion laws of chemical combination basic concepts of chemistry some basic concepts of chemistry chemistry

$CO _2$ contains $27.27$% of carbon,$CS _2$ contains $15.79$% of carbon,$SO _2$ contains $50$% sulphur. What will be the ratio of $S:O$ in $SO _2$?

  1. $1:1$
  2. $1:2$
  3. $2:1$
  4. $3:2$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

In CO2, C is 27.27%, so O is 72.73%. In CS2, C is 15.79%, so S is 84.21%. In SO2, S is 50%, so O is 50%. The ratio of S:O in SO2 is 50:50, which simplifies to 1:1.