Tag: electric charges and fields

Questions Related to electric charges and fields

Multiple choice physics static electricity explaining static electricity charging by induction electric charges and fields

A sure test of electrification is:

  1. attraction

  2. repulsion

  3. friction

  4. induction

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Repulsion is the sure test of electrification.
Note: If two bodies are electrified (i.e., charged they can either attract or repel). If they are:
(a) attracted: this is not only possible by electrification but can also be due to the attraction of an uncharged body with charged body.
(b) repulsion: repulsion is possible only when both objects are charged oppositely.

Multiple choice physics static electricity explaining static electricity charging by induction electric charges and fields

When a glass rod is rubbed with silk, both become charged due to:

  1. migration of protons

  2. exchange of electrons and protons

  3. migration of electrons

  4. migration of neutrons

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

When a glass rod is rubbed with silk cloth glass rod becomes positively charges while silk cloth becomes negatively charged. This is due to transfer or migration of electrons from glass rod to silk cloth.

Multiple choice physics static electricity explaining static electricity charging by induction electric charges and fields

A glass rod when rubbed with silk cloth acquires a charge $1.6 \times 10^{-13}  C$. What is the charge on the silk cloth?

  1. $-1.6 \times 10^{-19} C$
  2. $1.6 \times 10^{-13} C$
  3. $-1.6 \times 10^{-13} C$
  4. $1.6 \times 10^{-19} C$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

When a glass rod is rubbed with silk, both gets electrified due to charging by friction. Given, glass rod acquires positive charge $=1.6\times 10^{-31}\, C$. So silk acquires equal and opposite charge as that on glass rod. Hence the answer is $-1.6\times 10^{-13}\, C$.