Tag: general equation of a line
Questions Related to general equation of a line
For the equation given below, find the the slope and the y-intercept : $\displaystyle 3y=7$
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$\displaystyle 0 \ and \ \frac{7}{3}$
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$\displaystyle 0 \ and \ -\frac{7}{3}$
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$\displaystyle -\frac{7}{3} \ and \ 0$
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$\displaystyle \frac{7}{3} \ and \ 0$
The equation of any straight line can be written as $ y =
mx + c $, where $m$ is its slope and $c$ is its y - intercept.
$ 3y = 7 $ can be written as $ y = \frac {7}{3} $
Comparing this equation with the standard form of the equation, we get:
$ m = 0 , c = \frac {7}{3} $
Hence, slope of $ 3y = 7 $ is $ 0 $ and y -intercept is $ \frac {7}{3} $
$ax + by + c = 0$ does not represent an equation of line if ____.
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$a = c = 0, b \neq 0$
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$b = c = 0, a \neq 0$
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$a = b = 0$
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$c = 0, a \neq 0, b \neq 0 $
$ax+by+c=0$ will represent the equation of line If both or one coefficient of $x$ and $y$ is not equal to $0$.
Find slope, x-intercept & y-intercept of the line 2x - 3y + 5 = 0
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$\dfrac{-5}{2},\dfrac{5}{3},\dfrac{2}{3}$
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$\dfrac{-5}{2},\dfrac{5}{3},\dfrac{1}{3}$
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$\dfrac{-3}{2},\dfrac{5}{3},\dfrac{2}{3}$
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$\dfrac{-5}{2},\dfrac{4}{3},\dfrac{2}{3}$
Find the slope and $y$-intercept of the line $2x + 5y = 1$
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slope $=$ $-\dfrac{2}{5}$, $y$-intercept $=$ $\dfrac{1}{5}$
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slope $=$ $-\dfrac{1}{5}$, $y$-intercept $=$ $\dfrac{1}{5}$
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slope $=$ $-\dfrac{2}{3}$, $y$-intercept $=$ $\dfrac{1}{5}$
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slope $=$ $-\dfrac{2}{5}$, $y$-intercept $= $ $\dfrac{2}{5}$
Find the slope and $y$-intercept of the line $-5x + y = 5$.
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slope $= 5, y$-intercept $= -5$
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slope $= 5, y$-intercept $= -4$
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slope $= 5, y$-intercept $= 5$
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slope $= 5, y$-intercept $= -1$
The slope-intercept form is $y = mx + b$, where $m$ is the slope and $b$ is the $y$-intercept.
Find the slope and $y$-intercept of the line $0.2x - y = 1.2$
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slope $= 0.2$, $y$-intercept $= -1.2$
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slope $= 1.2$, $y$-intercept $= -1.2$
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slope $= 0.2$, $y$-intercept $= -2.2$
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slope $= 0.2$, $y$-intercept $= -1.3$
Find the slope and $y$-intercept of the line $2x + 2y = -2$
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slope = 1, y-intercept $= -3$
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slope = -1, y-intercept $= -1$
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slope = 1, y-intercept $= 3$
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slope = 1, y-intercept $= 1$
Find the slope and $y$-intercept of the line $x - y = 3$
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slope $= 2$, $y$-intercept $= -3$
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slope $= 0$, $y$-intercept $= -3$
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slope $= 1$, $y$-intercept $= -3$
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slope $= 1$, $y$-intercept $= 3$
A line in the $xy$-plane passes through the origin and has a slope of $\dfrac{1}{7}$. Which of the following points lies on the line?
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$\left(0, 7\right)$
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$\left(1, 7\right)$
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$\left(7, 7\right)$
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$\left(14, 2\right)$
If any straight line passes through origin, then it must of the form $y = mx$.
Find an equation of the line through the points $(-3,5)$ and $(9,10)$ and write it in standard form $Ax+By=C$, with $A>0$
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$6x-10y=-75$
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$5x-12y=-75$
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$4x-11y=-65$
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$x-6y=-15$
$y - 5 = \left (\dfrac {5}{12}\right) [x-(-3)]$
$y-5=\left (\dfrac {5}{12}\right)(x+3)$
Solve it and get the equation-
$5x-12y=-75$
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