Tag: fundamental principles of counting

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Multiple choice maths combinatorics and mathematical induction fundamental principle of addition fundamental principles of counting principles of counting

The 30 members of a club decided to playa badminton singles tournament. Every time a member loses a game he is out of tournament. There is no ties. What is the minimum number of matches that must be played to determine the winner?

  1. 15

  2. 29

  3. 61

  4. 435
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Clearly, every member except one (i.e. the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 - 1 = 29.

Multiple choice maths combinatorics and mathematical induction fundamental principle of addition fundamental principles of counting principles of counting

Each  section of soccer stadium has 44 rows with 22 sets in first row, 23 in the second row, 24 in the third row, and so on. How many seats are there in row 44.

  1. 65

  2. 1914

  3. 43

  4. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

This is an arithmetic progression where a = 22 and d = 1. The number of seats in row n is a + (n - 1)d. For row 44: 22 + (44 - 1) * 1 = 22 + 43 = 65.

Multiple choice maths combinatorics and mathematical induction fundamental principle of addition fundamental principles of counting principles of counting

The number of all three digit even number such that if $3$ is one of the digits, then next digit is $5$, is 

  1. $359$
  2. $360$
  3. $365$
  4. $380$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
We need even numbers so the last digit must be $0, 2, 4, 6, 8$. So $5$ possibilities
Now the ten's place can be any number between $0$ to $9$ except $3$ because in that case, the $3$ is to be followed by $5$ in the units place then it won't be an even no., so there are $9$ possibilities.
Now in hundred's place can be anything between $1$ to $9$ except $3$ because if $3$ is present then the next digit must be $5$ so there are $8$ possibilities.
Now if there is $3$ in hundred's place then $5$ will be in ten's place and the numbers must be $350, 352, 354, 356, 358$ which will be treated seperately. So $5$ possibilities
Therefore, 
Total no. of even numbers $= 8 \times 9 \times 5 + 5 = 365$
Multiple choice maths combinatorics and mathematical induction fundamental principle of addition fundamental principles of counting principles of counting

In an election, the number of candidates is one more than the number of members to be elected. A voter can cast any number of the vote but not more than the candidates to be elected. If a voter can cast his vote in $30$ ways, then the number of the candidates is 

  1. $4$
  2. $5$
  3. $6$

  4. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer