Tag: mechanics

Questions Related to mechanics

Multiple choice collisions in one dimension collisions work, energy and power mechanics physics

Two identical balls  $A$  and  $B$  having velocities of  $0.5\mathrm { m } / \mathrm { s }$  and  $- 0.3 \mathrm { m } / \mathrm { s }$  respectively collide elastically in one dimension. The velocities of  $B$  and  $\mathrm { A }$  after the collision respectively will be

  1. $0.3 \mathrm { m } / \mathrm { s } \text { and } 0.5 \mathrm { m } / \mathrm { s }$
  2. $- 0.5 \mathrm { m } / \mathrm { s } \text { and } 0.3 \mathrm { m } / \mathrm { s }$
  3. $0.5 \mathrm { m } / \mathrm { s } \text { and } - 0.3 \mathrm { m } / \mathrm { s }$
  4. $- 0.3 \mathrm { m } / \mathrm { s } \text { and } 0.5 \mathrm { m } / \mathrm { s }$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

When two identical masses collide elastically in one dimension, they simply exchange their velocities. Since A starts at 0.5 m/s and B at -0.3 m/s, after the collision, A will have -0.3 m/s and B will have 0.5 m/s.

Multiple choice collisions in one dimension collisions work, energy and power mechanics physics

A particle of mass $ m _1 $ hits another particle of mass $ m _2 $ at rest with a velocity $ \overrightarrow { u }  $. The collision is head-on and elastic.If $ m _1 >> m _2 $, then after collision, the velocity of $ m _2 $ will be-

  1. $ \overrightarrow { u } $
  2. $ - \overrightarrow { u } $
  3. $ 2 \overrightarrow { u } $
  4. $ -2 \overrightarrow { u } $
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For a head-on elastic collision where a very massive body (m1) hits a stationary light body (m2), the velocity of the light body after the collision is twice the velocity of the incident massive body.

Multiple choice collisions in one dimension collisions work, energy and power mechanics physics

Which of the following does no undergo elastic collision?

  1. When $ m _1 = m _2$ and $m _2 $ is stationary,there is maximum transfer of kinetic energy in head an collision
  2. When $ m _1 = m _2 $ is stationary,there is minimum transfer of momentum in head on collision
  3. When $ m _1 >> m _2 $ is stationary,after head on collision $ m _2 $ moves with twice the velocity of $ m _1 $
  4. When the collision is oblique and $ m _1 = m _2 with m _2 $ stationary,after the collision the particle move in opposite directions.
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice collisions in one dimension collisions work, energy and power mechanics physics

A sphere P of mass m and  velocity $\underset{V _{1}}{\rightarrow}$  undergoes an oblique and perfectly elastic collision with an identical sphere Q initially at rest.  The  angle $\Theta $  between the velocites of the spheres after the collision shall be

  1. 0

  2. $45^{\circ}$
  3. $90^{\circ}$
  4. $180^{\circ}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

In a perfectly elastic collision between two identical masses where one is initially at rest, the two bodies will move at an angle of 90 degrees to each other after the collision, provided the collision is oblique.

Multiple choice collisions in one dimension collisions work, energy and power mechanics physics

A neutron collides head-on with a stationary hydrogen atom $( _1H^1)$ in ground state, then choose the correct statement (assume that mass of neutron and mass of $( _1H^1)$ atom is same)

  1. If kinetic energy of the neutron is less than $13.6eV$, collision must be elastic
  2. If kinetic energy of the neutron is less than $13.6eV$, collision must be inelastic
  3. Inelastic collision may take place only when initial kinetic energy of neutron is greater than $13.6eV$
  4. Perfectly inelastic collisin cannot take place.

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

If the kinetic energy of the neutron is less than the excitation energy of the hydrogen atom (13.6 eV), the collision cannot result in internal energy changes, so it must be elastic to conserve energy and momentum.