Tag: distinction between pairs of amines

Questions Related to distinction between pairs of amines

Propylamine and aniline can be distinguished by azo dye test.

  1. True

  2. False


Correct Option: A
Explanation:

As only aryl systems undergo azo dye test. Therefore, propylamine gives negative azo dye test.

Aniline gives positive azo dye test.

When chloroform reacts with ethylamine in presence of alc. $KOH$, the compound formed is:

  1. ethyl cyanide

  2. ethyl isocyanide

  3. formic acid

  4. phosgene


Correct Option: B
Explanation:

Reaction:
$C{ H } _{ 3 }N{ H } _{ 2 }+CHCl _3+KOH\rightarrow C{ H } _{ 3 }NC$

Aniline and benzylamine  cannot be distinguished by azo dye test

  1. True

  2. False


Correct Option: A
Explanation:

Aniline and benzylamine both are aryl systems as only highly activated benzene system gives positive azo dye test below room temperature. Therefore, aniline and benzylamine cannot be distinguished by azo dye test as both give positive azo dye test.

A compound $(X)$ with molecular formula $C _3H _9N$ react with $C _6H _5SO _2Cl$ to give a solid which is insoluble in alkali. $(X)$ is:

  1. $CH _3CH _2CH _2NH _2$

  2. $CH _3 - {\underset{CH _3}{\underset{|}{\overset{CH _3}{\overset{|}{N:}}}}}$

  3. $CH _3 - NH - CH _2CH _3$

  4. $CH _3 - {\underset{CH _3}{\underset{|}{CH}}} - NH _2$


Correct Option: C
Explanation:

Since the compound reacts with benzenesulphonyl chloride to give a product which is insoluble in alkali, it shows there is no $H$ attached to $N$ in the product . Hence, the compound $X$ is a secondary amine.
$CH _3 - NH - C-2H _5 + C _6H _5SO _2Cl \rightarrow \underset{N - Ethyl - N - methylbenzene sulphonamide}{CH _3 - {\underset{C _2H _5}{\underset{|}{N}}} - SO _2C _6H _5}$

During preparation of arene diazonium salts, the excess of nitrous acid, if any, is destroyed by adding?

  1. $aq. \, NaOH$

  2. $aq. \, Na _2CO _3$

  3. $aq. \, NH _2CONH _2$

  4. $aq. \, KI$


Correct Option: C
Explanation:

Urea decomposes $HNO _2$ to give $N _2, \, CO _2 $ and $ H _2O$
$NH _2CONH _2+\, 2HONO \rightarrow 2N _2 \uparrow + \, CO _2 \uparrow +\, 3H _2O$

A colourless liquid $A(b.p:184^\circ:C)$ is sparingly soluble in warm water to which it gives feebly alkaline reaction on treating with $NaNO _{2}:and:dil:HCl$ in the cold solution, it yields a solution which reacts with an alkaline solution of $\beta-$napthol to give an orange yellow precipitate. Compound $A$ is :

  1. $C _{6}H _{5}N _{2}Cl$

  2. $C _{6}H _{5}NHNH _{2}$

  3. $n-C _{4}H _{9}NH _{2}$

  4. $C _{6}H _{5}NH _{2}$


Correct Option: D
Explanation:

Aniline is the colourless liquid A having boiling point $184 ^oC$.
On treatment with $NaNO _{2}:and:dil:HCl$ at low temperature, it forms benzne diazonum salt.
The diazonium salt reacts with napthol in alkaline medium to form azo dye which is n orange yellow precipitate.

Primary, secondary and tertiary amines may be separated by using:

  1. iodoform

  2. diethyloxalate

  3. benzenesulphonyl chloride

  4. acetyl chloride


Correct Option: C
Explanation:

The amine is treated with benzenesulphonyl chloride  and shaken with alkali solution when the three amine because in different way$.$

Primary amine from alkyl benzesulphoramide which dissolve in alkali to from sodium potassium salt of mono alkyl benzene sulphoramide$.$ Secondary amine from dialkali benzene$,$ in soluble in alkali solution and tertiary amines do not react with benzene sulphonyl chloride at all$.$

Which of the following is not a property of diazonium salts?

  1. Diazonium salts are colourless crystalline solids.

  2. Being ionic in nature they are soluble in water.

  3. Most of these salts explode when dried.

  4. The aqueous solutions of these salts are poor conductors of electricity.


Correct Option: D
Explanation:

Salt solution such as sodium chloride ($NaCl$) conducts an electric current because it has ions in it that have the freedom to move about in solution. These ions are produced when sodium chloride dissolves in pure water to produce sodium ($Na^+$) and chloride ions ($Cl^–$).

Diazonium salts ($ArN _2^+X$) aqueous solutions are neutral to litmus and conduct electricity due to the presence of ions.
In an aqueous solution (that is, dissolved in water), the ions and electrons are much more mobile, thereby allowing electricity to flow through the solution.