Tag: ray optics and optical instruments

Questions Related to ray optics and optical instruments

Lenses applied in achromatic combination having dispersive power in ratio of $5:3$ if focal of length of the concave lens is $15cm$, then focal length of the other lens will be:

  1. $-9 cm$

  2. $+9 cm$

  3. $-12 cm$

  4. $+12 cm$


Correct Option: B
Explanation:

Given,

$\omega _1:\omega _2=5:3$
$f _1=-15cm$
We know that, 
$\dfrac{\omega _1}{\omega _2}=-\dfrac{f _1}{f _2}$. . . . . . .(1)
$\dfrac{\omega _1}{\omega _2}=\dfrac{5}{3}$. . . . . .(2)
From equation (1) and equation (2), we get
$-\dfrac{f _1}{f _2}=\dfrac{5}{3}$
$f _2=-\dfrac{3f _1}{5}$

$f _2=-\dfrac{3\times (-15cm)}{5}=+9cm$
The correct option is B.

Concave and convex lenses are placed torching each other. Ratio of magnitude of their power is $2:3$. The focal length of the system is $30\ cm$. Focal lengths of individual lenses are 

  1. $-75, 50$

  2. $-15, 10$

  3. $75, 50$

  4. $75, -50$


Correct Option: C

When a telescope is adjusted for normal vision, the distance of the objective from the eye-piece is found to be 80 cm. The magnifying power of the telescope is 19. What are the focal lengths of the lenses ?

  1. 61 cm, 19 cm

  2. 76 cm, 4 cm

  3. 40 cm, 40 cm

  4. 50 cm, 30 cm


Correct Option: B

Two plano- concave lenses of glass of refractive index $1.5$ have radii of curvature of $20$ and $30\ cm$. They are placed in contact with curved surfaces towards each other and the space between them is filled with a liquid of refractive index $(4/3)$. Find the focal length of the system :

  1. divergent lens, $f = 72\ cm$

  2. convergent lens, $f = 72\ cm$

  3. divergent lens, $f = 32\ cm$

  4. convergent lens, $f = 32\ cm$


Correct Option: D

Which values for $K, L, M$ and $N$ will make the following paragraph true?
When an object of size $7\ cm$ is placed at the distance of $K$ in front of a $L$ of focal length $M,$ the image will be produced at the distance of $N$ in front of the mirror.

  1. $\mathrm { K } - 27\ \mathrm { cm } ; \mathrm { L-concave \ mirror}; \mathrm { M } - 18\ \mathrm { cm } ; \mathrm { N } - 36\ \mathrm { cm }$

  2. $\mathrm { K } - 18\ \mathrm { cm } ; \mathrm { L-concave\ mirror}; \mathrm { M } - 18\ \mathrm { cm } ; N - 54\ \mathrm { cm }$

  3. $\mathrm { K } - 27\ \mathrm { cm } ; L-concave\ mirror; \mathrm { M } - 18\ \mathrm { cm } ; N - 54\ \mathrm { cm }$

  4. $None\ of\ these$


Correct Option: C

If two lenses of power + 1.5 D and +1.0 D are placed in contact, then the effective power of combination will be :

  1. 4.5 D

  2. 2.5 D

  3. 5.4 D

  4. 4.2 D


Correct Option: B
Explanation:

Given,


$P _1=+1.5 D$


$P _2=+1.0 D$

The effective power of the combination,

$P=P _1+P _2$

$P=(+1.5)+(+1.0)$

$P=+2.5D$

The correct option is B.

A convex lens of focal length 40 cm is in contact with a concave lens of focal length 25 cm. The power of he combination, is :

  1. $+ 6.67 D$

  2. $- 6.5 D$

  3. $- 1.5 D$

  4. $+ 6.5 D$


Correct Option: C
Explanation:

Given,


$f _1=+40cm$


$f _2=-25cm$

Power, $P=\dfrac{1}{f}$

The power of combination,

$P=\dfrac{1}{f _1}+\dfrac{1}{f _2}$

$P=\dfrac{100}{+40cm}+\dfrac{100}{-25cm}$

$P=-1.5D$

The correct option is C.

A far sighted person can see object beyond 71 cm clearly if separation between glasses and eye lens is 2 cm ,then find focal length of glass ?

  1. 23 cm

  2. 34.5 cm

  3. 18.4 cm

  4. 73 cm


Correct Option: D

If the magnitude of dispersive power of two lenses are $0.024$ and $0.036$. There focal length will be for abberation free combination.

  1. $30\ cm,\ -40\ cm$

  2. $30\ cm,\ -45\ cm$

  3. $10\ cm,\ 30\ cm$

  4. $20\ cm,\ -35\ cm$


Correct Option: B

In displacement method,magnification for two positions of the lens are 2 and 0.5 and the distance between the two position of the lens is 30 cm. if the focal length of lens is

  1. 15cm

  2. 20cm

  3. 25cm

  4. 30cm


Correct Option: B